我想知道,删除一个包含所有文件的目录最简单的方法是什么?

我使用的是rmdir(PATH。“/”。美元价值);要删除一个文件夹,但是,如果里面有文件,我根本不能删除它。


当前回答

现在至少有两种选择。

Before deleting the folder, delete all its files and folders (and this means recursion!). Here is an example: public static function deleteDir($dirPath) { if (! is_dir($dirPath)) { throw new InvalidArgumentException("$dirPath must be a directory"); } if (substr($dirPath, strlen($dirPath) - 1, 1) != '/') { $dirPath .= '/'; } $files = glob($dirPath . '*', GLOB_MARK); foreach ($files as $file) { if (is_dir($file)) { self::deleteDir($file); } else { unlink($file); } } rmdir($dirPath); } And if you are using 5.2+ you can use a RecursiveIterator to do it without implementing the recursion yourself: $dir = 'samples' . DIRECTORY_SEPARATOR . 'sampledirtree'; $it = new RecursiveDirectoryIterator($dir, RecursiveDirectoryIterator::SKIP_DOTS); $files = new RecursiveIteratorIterator($it, RecursiveIteratorIterator::CHILD_FIRST); foreach($files as $file) { if ($file->isDir()){ rmdir($file->getRealPath()); } else { unlink($file->getRealPath()); } } rmdir($dir);

其他回答

一点点修改alcuadrado的代码- glob不看到文件名从点像.htaccess,所以我使用scandir和脚本删除本身-检查__FILE__。

function deleteDir($dirPath) {
    if (!is_dir($dirPath)) {
        throw new InvalidArgumentException("$dirPath must be a directory");
    }
    if (substr($dirPath, strlen($dirPath) - 1, 1) != '/') {
        $dirPath .= '/';
    }
    $files = scandir($dirPath); 
    foreach ($files as $file) {
        if ($file === '.' || $file === '..') continue;
        if (is_dir($dirPath.$file)) {
            deleteDir($dirPath.$file);
        } else {
            if ($dirPath.$file !== __FILE__) {
                unlink($dirPath.$file);
            }
        }
    }
    rmdir($dirPath);
}

这个对我很有用:

function removeDirectory($path) {
    $files = glob($path . '/*');
    foreach ($files as $file) {
        is_dir($file) ? removeDirectory($file) : unlink($file);
    }
    rmdir($path);
    return;
}

类似Playnox的解决方案,但有优雅的内置DirectoryIterator:

function delete_directory($dirPath){
 if(is_dir($dirPath)){
  $objects=new DirectoryIterator($dirPath);
   foreach ($objects as $object){
    if(!$object->isDot()){
     if($object->isDir()){
      delete_directory($object->getPathname());
     }else{
      unlink($object->getPathname());
     }
    }
   }
   rmdir($dirPath);
  }else{
   throw new Exception(__FUNCTION__.'(dirPath): dirPath is not a directory!');
  }
 }

使用DirectoryIterator等价于之前的答案…

function deleteFolder($rootPath)
{   
    foreach(new DirectoryIterator($rootPath) as $fileToDelete)
    {
        if($fileToDelete->isDot()) continue;
        if ($fileToDelete->isFile())
            unlink($fileToDelete->getPathName());
        if ($fileToDelete->isDir())
            deleteFolder($fileToDelete->getPathName());
    }

    rmdir($rootPath);
}

删除一个包含所有文件的目录最简单的方法是什么?

system("rm -rf ".escapeshellarg($dir));