对我来说最好的解决方案

my_folder_delete("../path/folder");

代码:

function my_folder_delete($path) {
    if(!empty($path) && is_dir($path) ){
        $dir  = new RecursiveDirectoryIterator($path, RecursiveDirectoryIterator::SKIP_DOTS); //upper dirs are not included,otherwise DISASTER HAPPENS :)
        $files = new RecursiveIteratorIterator($dir, RecursiveIteratorIterator::CHILD_FIRST);
        foreach ($files as $f) {if (is_file($f)) {unlink($f);} else {$empty_dirs[] = $f;} } if (!empty($empty_dirs)) {foreach ($empty_dirs as $eachDir) {rmdir($eachDir);}} rmdir($path);
    }
}

注。记住!不要将空值传递给任何目录删除函数!!(总是备份它们，否则有一天你可能会遇到灾难!!)

现在至少有两种选择。

Before deleting the folder, delete all its files and folders (and this means recursion!). Here is an example: public static function deleteDir($dirPath) { if (! is_dir($dirPath)) { throw new InvalidArgumentException("$dirPath must be a directory"); } if (substr($dirPath, strlen($dirPath) - 1, 1) != '/') { $dirPath .= '/'; } $files = glob($dirPath . '*', GLOB_MARK); foreach ($files as $file) { if (is_dir($file)) { self::deleteDir($file); } else { unlink($file); } } rmdir($dirPath); } And if you are using 5.2+ you can use a RecursiveIterator to do it without implementing the recursion yourself: $dir = 'samples' . DIRECTORY_SEPARATOR . 'sampledirtree'; $it = new RecursiveDirectoryIterator($dir, RecursiveDirectoryIterator::SKIP_DOTS); $files = new RecursiveIteratorIterator($it, RecursiveIteratorIterator::CHILD_FIRST); foreach($files as $file) { if ($file->isDir()){ rmdir($file->getRealPath()); } else { unlink($file->getRealPath()); } } rmdir($dir);

完成工作的简短函数:

function deleteDir($path) {
    return is_file($path) ?
            @unlink($path) :
            array_map(__FUNCTION__, glob($path.'/*')) == @rmdir($path);
}

我在Utils类中使用它，就像这样:

class Utils {
    public static function deleteDir($path) {
        $class_func = array(__CLASS__, __FUNCTION__);
        return is_file($path) ?
                @unlink($path) :
                array_map($class_func, glob($path.'/*')) == @rmdir($path);
    }
}

能力越大责任越大:当你用空值调用这个函数时，它会删除根目录(/)下的文件。为了安全起见，你可以检查path是否为空:

function deleteDir($path) {
    if (empty($path)) { 
        return false;
    }
    return is_file($path) ?
            @unlink($path) :
            array_map(__FUNCTION__, glob($path.'/*')) == @rmdir($path);
}

这个对我很有用:

function removeDirectory($path) {
    $files = glob($path . '/*');
    foreach ($files as $file) {
        is_dir($file) ? removeDirectory($file) : unlink($file);
    }
    rmdir($path);
    return;
}

我想通过@Vijit处理符号链接的评论来扩展@alcuadrado的答案。首先，使用getRealPath()。但是，如果你有任何符号链接是文件夹，它会失败，因为它会尝试在链接上调用rmdir -所以你需要额外的检查。

$it = new RecursiveDirectoryIterator($dir, RecursiveDirectoryIterator::SKIP_DOTS);
$files = new RecursiveIteratorIterator($it, RecursiveIteratorIterator::CHILD_FIRST);
foreach($files as $file) {
    if ($file->isLink()) {
        unlink($file->getPathname());
    } else if ($file->isDir()){
        rmdir($file->getPathname());
    } else {
        unlink($file->getPathname());
    }
}
rmdir($dir);

Glob函数不返回隐藏文件，因此当试图递归删除树时，scandir可能更有用。

<?php
public static function delTree($dir) {
   $files = array_diff(scandir($dir), array('.','..'));
    foreach ($files as $file) {
      (is_dir("$dir/$file")) ? delTree("$dir/$file") : unlink("$dir/$file");
    }
    return rmdir($dir);
  }
?>