你可以像这样从uri中检索位图

Bitmap bitmap = null;
try {
    bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
} catch (IOException e) {
    e.printStackTrace();
}

  InputStream imageStream = null;
    try {
        imageStream = getContext().getContentResolver().openInputStream(uri);
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    }
    final Bitmap selectedImage = BitmapFactory.decodeStream(imageStream);

我没有看到正确答案，所以我把这个扩展写在这里

fun Context.getBitmap(uri: Uri): Bitmap =
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) ImageDecoder.decodeBitmap(ImageDecoder.createSource(this.contentResolver, uri))
    else MediaStore.Images.Media.getBitmap(this.contentResolver, uri)

代码示例:

val bitmap = context.getBitmap(uri)

提示:你也可以更新活动/片段的扩展，所以你不需要 根本不需要写上下文。再加一点合成糖)

* For getting bitmap from uri. Work for me perfectly.
    
    
    public static Bitmap decodeUriToBitmap(Context mContext, Uri sendUri) {
          Bitmap getBitmap = null;
          try {
            InputStream image_stream;
            try {
              image_stream = mContext.getContentResolver().openInputStream(sendUri);
              getBitmap = BitmapFactory.decodeStream(image_stream);
            } catch (FileNotFoundException e) {
              e.printStackTrace();
            }
          } catch (Exception e) {
            e.printStackTrace();
          }
          return getBitmap;
        }

ContentResolver cr = context.getContentResolver();
try (InputStream input = cr.openInputStream(url)) {
    Bitmap bitmap = BitmapFactory.decodeStream(input);
}

你可以像这样从uri中检索位图

Bitmap bitmap = null;
try {
    bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
} catch (IOException e) {
    e.printStackTrace();
}