对于那些喜欢处理小数字的人

const today = new Date();
const endDate = new Date(startDate.setDate(startDate.getDate() + 7));
const days = parseInt((endDate - today) / (1000 * 60 * 60 * 24));
const hours = parseInt(Math.abs(endDate - today) / (1000 * 60 * 60) % 24);
const minutes = parseInt(Math.abs(endDate.getTime() - today.getTime()) / (1000 * 60) % 60);
const seconds = parseInt(Math.abs(endDate.getTime() - today.getTime()) / (1000) % 60); 

这是我在节点中求解类似问题时得到的一些乐趣。

function formatTimeDiff(date1, date2) {
  return Array(3)
    .fill([3600, date1.getTime() - date2.getTime()])
    .map((v, i, a) => {
      a[i+1] = [a[i][0]/60, ((v[1] / (v[0] * 1000)) % 1) * (v[0] * 1000)];
      return `0${Math.floor(v[1] / (v[0] * 1000))}`.slice(-2);
    }).join(':');
}

const millis = 1000;
const utcEnd = new Date(1541424202 * millis);
const utcStart = new Date(1541389579 * millis);
const utcDiff = formatTimeDiff(utcEnd, utcStart);

console.log(`Dates:
  Start   : ${utcStart}
  Stop    : ${utcEnd}
  Elapsed : ${utcDiff}
  `);

/*
Outputs:

Dates:
  Start   : Mon Nov 05 2018 03:46:19 GMT+0000 (UTC)
  Stop    : Mon Nov 05 2018 13:23:22 GMT+0000 (UTC)
  Elapsed : 09:37:02
*/

你可以在https://repl.it/@GioCirque/TimeSpan-Formatting上看到它的运行

var startTime = new Date('2012/10/09 12:00'); 
var endTime = new Date('2013/10/09 12:00');
var difference = endTime.getTime() - startTime.getTime(); // This will give difference in milliseconds
var resultInMinutes = Math.round(difference / 60000);

您可以进行如下操作:

获取日期的差异(以毫秒为单位) 将毫秒转换为分钟i-e ms/1000/60

代码:

let dateOne = new Date("2020-07-10");
let dateTwo = new Date("2020-07-11");

let msDifference =  dateTwo - dateOne;
let minutes = Math.floor(msDifference/1000/60);
console.log("Minutes between two dates =",minutes);

你可以签出这段代码:

var today = new Date（）; var Christmas = new Date（today.getFullYear（） + “-12-25”）; var diffMs = （圣诞节 - 今天）;从现在到圣诞节之间的毫秒数 var diffDays = Math.floor（diffMs / 86400000）;日 var diffHrs = Math.floor（（diffMs % 86400000） / 3600000）;小时 var diffMins = Math.round（（（（diffMs x86400000） % 3600000） / 60000）;纪要 console.log（diffDays + “ days， ” + diffHrs + “ hours， ” + diffMins + “ minutes till Christmas =）”）;

或者var diffMins = Math.floor((…如果不想舍入分钟，则丢弃秒。

这是可行的

duration = moment.duration(moment(end_time).diff(moment(start_time)))