我对编码有点困惑。据我所知,旧的ASCII字符每个字符占用一个字节。一个Unicode字符需要多少字节?

我假设一个Unicode字符可以包含任何语言的所有可能字符——我说的对吗?那么每个字符需要多少字节呢?

UTF-7、UTF-6、UTF-16等是什么意思?它们是Unicode的不同版本吗?

我读了维基百科上关于统一码的文章,但对我来说太难了。我期待看到一个简单的答案。


当前回答

从维基:

UTF-8, 8位可变宽度编码,最大限度地兼容ASCII; UTF-16,一种16位变宽编码; UTF-32, 32位,固定宽度编码。

这是三种最流行的不同编码。

在UTF-8中,每个字符被编码成1到4个字节(主要编码) 在UTF16中,每个字符被编码成1到2个16位的单词和 在UTF-32中,每个字符都被编码为一个32位的单词。

其他回答

你不会看到一个简单的答案,因为根本就没有答案。

首先,Unicode并没有包含“每一种语言的每一个字符”,尽管它确实尝试了。

Unicode本身是一种映射,它定义码点,码点是一个数字,通常与一个字符相关联。我说通常是因为有像组合字符这样的概念。你可能对口音或变音很熟悉。它们可以与其他字符一起使用,例如a或u来创建一个新的逻辑字符。因此,一个字符可以由一个或多个码位组成。

To be useful in computing systems we need to choose a representation for this information. Those are the various unicode encodings, such as utf-8, utf-16le, utf-32 etc. They are distinguished largely by the size of of their codeunits. UTF-32 is the simplest encoding, it has a codeunit that is 32bits, which means an individual codepoint fits comfortably into a codeunit. The other encodings will have situations where a codepoint will need multiple codeunits, or that particular codepoint can't be represented in the encoding at all (this is a problem for instance with UCS-2).

由于组合字符的灵活性,即使在给定的编码中,每个字符的字节数也可以根据字符和规范化形式而变化。这是一种用于处理具有多个表示的字符的协议(您可以说“带重音的'a'”是2个代码点,其中一个是组合字符或“带重音的'a'”是一个代码点)。

对于UTF-16,如果字符以0xD800或更大开头,则需要四个字节(两个代码单元);这样的字符称为“代理对”。更具体地说,代理对的形式是:

[0xD800 - 0xDBFF]  [0xDC00 - 0xDFF]

在[…]表示给定范围的双字节代码单元。任何<= 0xD7FF的值都是一个代码单元(两个字节)。任何>= 0xE000都是无效的(BOM标记除外)。

参见http://unicodebook.readthedocs.io/unicode_encodings.html,第7.5节。

看看这个Unicode代码转换器。例如,在“0x…”字段,然后单击Convert。十六进制数E2 80 89(3字节)出现在“UTF-8 code units”字段中。

在Unicode中,答案是不容易给出的。正如您已经指出的,问题在于编码。

对于任何没有变音符字符的英语句子,UTF-8的答案将是字符的字节数,而UTF-16的答案将是字符数乘以2。

(到目前为止)我们可以声明大小的唯一编码是UTF-32。每个字符总是32位,即使我想象代码点是为未来的UTF-64准备的:)

至少有两件事让它如此困难:

composed characters, where instead of using the character entity that is already accented/diacritic (À), a user decided to combine the accent and the base character (`A). code points. Code points are the method by which the UTF-encodings allow to encode more than the number of bits that gives them their name would usually allow. E.g. UTF-8 designates certain bytes which on their own are invalid, but when followed by a valid continuation byte will allow to describe a character beyond the 8-bit range of 0..255. See the Examples and Overlong Encodings below in the Wikipedia article on UTF-8. The excellent example given there is that the € character (code point U+20AC can be represented either as three-byte sequence E2 82 AC or four-byte sequence F0 82 82 AC. Both are valid, and this shows how complicated the answer is when talking about "Unicode" and not about a specific encoding of Unicode, such as UTF-8 or UTF-16. Strictly speaking, as pointed out in a comment, this doesn't seem to be the case any longer or was even based on a misunderstanding on my part. The quote from the updated Wikipedia article reads: Longer encodings are called overlong and are not valid UTF-8 representations of the code point.

在utf - 8:

1 byte:       0 -     7F     (ASCII)
2 bytes:     80 -    7FF     (all European plus some Middle Eastern)
3 bytes:    800 -   FFFF     (multilingual plane incl. the top 1792 and private-use)
4 bytes:  10000 - 10FFFF

在utf - 16:

2 bytes:      0 -   D7FF     (multilingual plane except the top 1792 and private-use )
4 bytes:   D800 - 10FFFF

在utf - 32:

4 bytes:      0 - 10FFFF

根据定义,10FFFF是最后一个unicode码位,这样定义是因为它是UTF-16的技术限制。

它也是UTF-8可以在4字节内编码的最大码点,但UTF-8编码背后的思想也适用于5字节和6字节编码,以覆盖码点,直到7FFFFFFF。只有UTF-32的一半。