是否有一个简单的方法来填充我的c#对象与JSON对象通过AJAX传递?
这是使用JSON.stringify从页面传递给c# WEBMETHOD的JSON对象
{
"user": {
"name": "asdf",
"teamname": "b",
"email": "c",
"players": ["1", "2"]
}
}
接收JSON对象的c# webmethod
[WebMethod]
public static void SaveTeam(Object user)
{
}
c#类，表示传递给WebMethod的JSON对象的对象结构
public class User
{
public string name { get; set; }
public string teamname { get; set; }
public string email { get; set; }
public Array players { get; set; }
}
当前回答
如果您使用的是。net 3.5或更高版本，为了保持您的选择余地，这里有一个封装好的示例，您可以使用泛型直接从框架中使用。正如其他人所提到的，如果不仅仅是简单的对象，那么就应该使用JSON.net。
public static string Serialize<T>(T obj)
{
DataContractJsonSerializer serializer = new DataContractJsonSerializer(obj.GetType());
MemoryStream ms = new MemoryStream();
serializer.WriteObject(ms, obj);
string retVal = Encoding.UTF8.GetString(ms.ToArray());
return retVal;
}
public static T Deserialize<T>(string json)
{
T obj = Activator.CreateInstance<T>();
MemoryStream ms = new MemoryStream(Encoding.Unicode.GetBytes(json));
DataContractJsonSerializer serializer = new DataContractJsonSerializer(obj.GetType());
obj = (T)serializer.ReadObject(ms);
ms.Close();
return obj;
}
你需要:
using System.Runtime.Serialization;
using System.Runtime.Serialization.Json;
其他回答
在c#中使用JSON的一个好方法是使用JSON。网
快速入门和来自JSON的API文档。官方网站帮助你使用它。
下面是如何使用它的例子:
public class User
{
public User(string json)
{
JObject jObject = JObject.Parse(json);
JToken jUser = jObject["user"];
name = (string) jUser["name"];
teamname = (string) jUser["teamname"];
email = (string) jUser["email"];
players = jUser["players"].ToArray();
}
public string name { get; set; }
public string teamname { get; set; }
public string email { get; set; }
public Array players { get; set; }
}
// Use
private void Run()
{
string json = @"{""user"":{""name"":""asdf"",""teamname"":""b"",""email"":""c"",""players"":[""1"",""2""]}}";
User user = new User(json);
Console.WriteLine("Name : " + user.name);
Console.WriteLine("Teamname : " + user.teamname);
Console.WriteLine("Email : " + user.email);
Console.WriteLine("Players:");
foreach (var player in user.players)
Console.WriteLine(player);
}
对于您的代码示例，您应该不需要做任何其他事情。
如果你将JSON字符串传递给你的web方法，它将自动解析JSON字符串并创建一个填充的User对象作为你的SaveTeam方法的参数。
一般来说，你可以使用如下所示的JavascriptSerializer类，或者为了获得更大的灵活性，可以使用任何一个Json框架(Jayrock Json是一个很好的框架)来轻松地操作Json。
JavaScriptSerializer jss= new JavaScriptSerializer();
User user = jss.Deserialize<User>(jsonResponse);
下面的两个例子使用了其中之一
JavaScriptSerializer在System.Web.Script.Serialization或 Json。在System.Web.Helpers下解码
例1:使用System.Web.Script.Serialization
using Microsoft.VisualStudio.TestTools.UnitTesting;
using System.Web.Script.Serialization;
namespace Tests
{
[TestClass]
public class JsonTests
{
[TestMethod]
public void Test()
{
var json = "{\"user\":{\"name\":\"asdf\",\"teamname\":\"b\",\"email\":\"c\",\"players\":[\"1\",\"2\"]}}";
JavaScriptSerializer serializer = new JavaScriptSerializer();
dynamic jsonObject = serializer.Deserialize<dynamic>(json);
dynamic x = jsonObject["user"]; // result is Dictionary<string,object> user with fields name, teamname, email and players with their values
x = jsonObject["user"]["name"]; // result is asdf
x = jsonObject["user"]["players"]; // result is object[] players with its values
}
}
}
用法:JSON对象到自定义c#对象
using System;
using Microsoft.VisualStudio.TestTools.UnitTesting;
using System.Web.Script.Serialization;
using System.Linq;
namespace Tests
{
[TestClass]
public class JsonTests
{
[TestMethod]
public void TestJavaScriptSerializer()
{
var json = "{\"user\":{\"name\":\"asdf\",\"teamname\":\"b\",\"email\":\"c\",\"players\":[\"1\",\"2\"]}}";
User user = new User(json);
Console.WriteLine("Name : " + user.name);
Console.WriteLine("Teamname : " + user.teamname);
Console.WriteLine("Email : " + user.email);
Console.WriteLine("Players:");
foreach (var player in user.players)
Console.WriteLine(player);
}
}
public class User {
public User(string json) {
JavaScriptSerializer serializer = new JavaScriptSerializer();
var jsonObject = serializer.Deserialize<dynamic>(json);
name = (string)jsonObject["user"]["name"];
teamname = (string)jsonObject["user"]["teamname"];
email = (string)jsonObject["user"]["email"];
players = jsonObject["user"]["players"];
}
public string name { get; set; }
public string teamname { get; set; }
public string email { get; set; }
public Array players { get; set; }
}
}
例2:使用System.Web.Helpers
using Microsoft.VisualStudio.TestTools.UnitTesting;
using System.Web.Helpers;
namespace Tests
{
[TestClass]
public class JsonTests
{
[TestMethod]
public void TestJsonDecode()
{
var json = "{\"user\":{\"name\":\"asdf\",\"teamname\":\"b\",\"email\":\"c\",\"players\":[\"1\",\"2\"]}}";
dynamic jsonObject = Json.Decode(json);
dynamic x = jsonObject.user; // result is dynamic json object user with fields name, teamname, email and players with their values
x = jsonObject.user.name; // result is asdf
x = jsonObject.user.players; // result is dynamic json array players with its values
}
}
}
用法:JSON对象到自定义c#对象
using System;
using Microsoft.VisualStudio.TestTools.UnitTesting;
using System.Web.Helpers;
using System.Linq;
namespace Tests
{
[TestClass]
public class JsonTests
{
[TestMethod]
public void TestJsonDecode()
{
var json = "{\"user\":{\"name\":\"asdf\",\"teamname\":\"b\",\"email\":\"c\",\"players\":[\"1\",\"2\"]}}";
User user = new User(json);
Console.WriteLine("Name : " + user.name);
Console.WriteLine("Teamname : " + user.teamname);
Console.WriteLine("Email : " + user.email);
Console.WriteLine("Players:");
foreach (var player in user.players)
Console.WriteLine(player);
}
}
public class User {
public User(string json) {
var jsonObject = Json.Decode(json);
name = (string)jsonObject.user.name;
teamname = (string)jsonObject.user.teamname;
email = (string)jsonObject.user.email;
players = (DynamicJsonArray) jsonObject.user.players;
}
public string name { get; set; }
public string teamname { get; set; }
public string email { get; set; }
public Array players { get; set; }
}
}
这段代码需要添加System.Web.Helpers命名空间，
% ProgramFiles % Microsoft ASP.NET喝ASP。网网络 布林{版本Assemblies喝System.Web.Helpers.dll
Or
% ProgramFiles (x86) % \ Microsoft ASP.NET \ ASP。网网络 页面{VERSION} \总成\ System.Web.Helpers.dll
希望这能有所帮助!
JSON。Net是最好的选择，但是，取决于对象的形状以及是否存在循环依赖关系，你可以使用JavaScriptSerializer或DataContractSerializer。
既然我们都喜欢一行代码
Newtonsoft比java脚本序列化器更快。 ．.． 这个依赖于Newtonsoft的NuGet包，这个包很流行，比默认的序列化器更好。
如果我们有类，那么使用下面。
Mycustomclassname oMycustomclassname = Newtonsoft.Json.JsonConvert.DeserializeObject<Mycustomclassname>(jsonString);
没有类则使用动态
var oMycustomclassname = Newtonsoft.Json.JsonConvert.DeserializeObject<dynamic>(jsonString);
