这个功能已经内置在Enum中:

>>> from enum import Enum
>>> class Build(Enum):
...   debug = 200
...   build = 400
... 
>>> Build['debug']
<Build.debug: 200>

成员名是大小写敏感的，所以如果用户输入被转换，你需要确保大小写匹配:

an_enum = input('Which type of build?')
build_type = Build[an_enum.lower()]

更改你的类签名为:

class BuildType(str, Enum):

对@rogueleaderr的回答进行了改进:

class QuestionType(enum.Enum):
    MULTI_SELECT = "multi"
    SINGLE_SELECT = "single"

    @classmethod
    def from_str(cls, label):
        if label in ('single', 'singleSelect'):
            return cls.SINGLE_SELECT
        elif label in ('multi', 'multiSelect'):
            return cls.MULTI_SELECT
        else:
            raise NotImplementedError

另一个选择(特别有用，如果你的字符串不映射1-1到你的enum情况)是添加一个static方法到你的enum，例如:

class QuestionType(enum.Enum):
    MULTI_SELECT = "multi"
    SINGLE_SELECT = "single"

    @staticmethod
    def from_str(label):
        if label in ('single', 'singleSelect'):
            return QuestionType.SINGLE_SELECT
        elif label in ('multi', 'multiSelect'):
            return QuestionType.MULTI_SELECT
        else:
            raise NotImplementedError

然后你可以输入question_type = questiontype。from_str('singleSelect')

我的类似java的解决方案。希望它能帮助到某人…

from enum import Enum, auto


class SignInMethod(Enum):
    EMAIL = auto(),
    GOOGLE = auto()

    @classmethod
    def value_of(cls, value):
        for k, v in cls.__members__.items():
            if k == value:
                return v
        else:
            raise ValueError(f"'{cls.__name__}' enum not found for '{value}'")


sim = SignInMethod.value_of('EMAIL')
assert sim == SignInMethod.EMAIL
assert sim.name == 'EMAIL'
assert isinstance(sim, SignInMethod)
# SignInMethod.value_of("invalid sign-in method")  # should raise `ValueError`

我只是想通知这在python 3.6中不起作用

class MyEnum(Enum):
    a = 'aaa'
    b = 123

print(MyEnum('aaa'), MyEnum(123))

你必须像这样以元组的形式给出数据

MyEnum(('aaa',))

编辑: 事实证明这是错误的。感谢一位指出我错误的评论者