在Java中,我可以这样做

derp(new Runnable { public void run () { /* run this sometime later */ } })

然后在方法中“运行”代码。处理起来很麻烦(匿名内部类),但这是可以做到的。

Go是否有一些可以方便函数/回调作为参数传递的东西?


当前回答

是的,Go确实接受一类函数。

请参阅文章“Go中的第一类函数”以获得有用的链接。

其他回答

你也可以传递一个struct的函数,比如:

    package main
    // define struct
    type Apple struct {}
    
    // return apple's color
    func (Apple) GetColor() string {
         return "Red" 
    }
    
    func main () {
        // instantiate
        myApple := Apple{}
        
        // put the func in a variable
        theFunc := myApple.GetColor
        
        // execute the variable as a function
        color := theFunc()
    
        print(color)
    }

输出将为“红色”,检查操场

是的,考虑一下这些例子:

package main

import "fmt"

// convert types take an int and return a string value.
type convert func(int) string

// value implements convert, returning x as string.
func value(x int) string {
    return fmt.Sprintf("%v", x)
}

// quote123 passes 123 to convert func and returns quoted string.
func quote123(fn convert) string {
    return fmt.Sprintf("%q", fn(123))
}

func main() {
    var result string

    result = value(123)
    fmt.Println(result)
    // Output: 123

    result = quote123(value)
    fmt.Println(result)
    // Output: "123"

    result = quote123(func(x int) string { return fmt.Sprintf("%b", x) })
    fmt.Println(result)
    // Output: "1111011"

    foo := func(x int) string { return "foo" }
    result = quote123(foo)
    fmt.Println(result)
    // Output: "foo"

    _ = convert(foo) // confirm foo satisfies convert at runtime

    // fails due to argument type
    // _ = convert(func(x float64) string { return "" })
}

玩:http://play.golang.org/p/XNMtrDUDS0

参观:https://tour.golang.org/moretypes/25(函数闭包)

我希望下面的例子能更清楚地说明问题。

package main

type EmployeeManager struct{
    category            string
    city                string
    calculateSalary     func() int64
}


func NewEmployeeManager() (*EmployeeManager,error){

    return &EmployeeManager{
        category : "MANAGEMENT",
        city : "NY",
        calculateSalary: func() int64 {
            var calculatedSalary int64
            // some formula
            return calculatedSalary
        },
    },nil
}

func (self *EmployeeManager) emWithSalaryCalculation(){
    self.calculateSalary = func() int64 {
        var calculatedSalary int64
        // some new formula
        return calculatedSalary
    }
}

func updateEmployeeInfo(em EmployeeManager){
    // Some code
}

func processEmployee(){
    updateEmployeeInfo(struct {
        category        string
        city            string
        calculateSalary func() int64
    }{category: "", city: "", calculateSalary: func() int64 {
        var calculatedSalary int64
        // some new formula
        return calculatedSalary
    }})
}

这是我能想到的最简单的方法。

package main

import "fmt"

func main() {
    g := greeting
    getFunc(g)
}

func getFunc(f func()) {
    f()
}

func greeting() {
    fmt.Println("Hello")
}

下面是Go中的“Map”实现示例。希望这能有所帮助!!

func square(num int) int {
    return num * num
}

func mapper(f func(int) int, alist []int) []int {
    var a = make([]int, len(alist), len(alist))
    for index, val := range alist {

        a[index] = f(val)
    }
    return a
}

func main() {
    alist := []int{4, 5, 6, 7}
    result := mapper(square, alist)
    fmt.Println(result)

}