我使用以下函数格式化请求。它类似于@AntonioHerraizS，只不过它也会在主体中漂亮地打印JSON对象，并且它标记了请求的所有部分。

format_json = functools.partial(json.dumps, indent=2, sort_keys=True)
indent = functools.partial(textwrap.indent, prefix='  ')

def format_prepared_request(req):
    """Pretty-format 'requests.PreparedRequest'

    Example:
        res = requests.post(...)
        print(format_prepared_request(res.request))

        req = requests.Request(...)
        req = req.prepare()
        print(format_prepared_request(res.request))
    """
    headers = '\n'.join(f'{k}: {v}' for k, v in req.headers.items())
    content_type = req.headers.get('Content-Type', '')
    if 'application/json' in content_type:
        try:
            body = format_json(json.loads(req.body))
        except json.JSONDecodeError:
            body = req.body
    else:
        body = req.body
    s = textwrap.dedent("""
    REQUEST
    =======
    endpoint: {method} {url}
    headers:
    {headers}
    body:
    {body}
    =======
    """).strip()
    s = s.format(
        method=req.method,
        url=req.url,
        headers=indent(headers),
        body=indent(body),
    )
    return s

我有一个类似的函数来格式化响应:

def format_response(resp):
    """Pretty-format 'requests.Response'"""
    headers = '\n'.join(f'{k}: {v}' for k, v in resp.headers.items())
    content_type = resp.headers.get('Content-Type', '')
    if 'application/json' in content_type:
        try:
            body = format_json(resp.json())
        except json.JSONDecodeError:
            body = resp.text
    else:
        body = resp.text
    s = textwrap.dedent("""
    RESPONSE
    ========
    status_code: {status_code}
    headers:
    {headers}
    body:
    {body}
    ========
    """).strip()

    s = s.format(
        status_code=resp.status_code,
        headers=indent(headers),
        body=indent(body),
    )
    return s

注意:这个答案已经过时了。请求的新版本支持直接获取请求内容，如AntonioHerraizS的回答文档。

从请求中获取请求的真实原始内容是不可能的，因为它只处理更高级别的对象，比如头和方法类型。Requests使用urllib3发送请求，但是urllib3也不处理原始数据——它使用httplib。下面是一个典型的请求堆栈跟踪:

-> r= requests.get("http://google.com")
  /usr/local/lib/python2.7/dist-packages/requests/api.py(55)get()
-> return request('get', url, **kwargs)
  /usr/local/lib/python2.7/dist-packages/requests/api.py(44)request()
-> return session.request(method=method, url=url, **kwargs)
  /usr/local/lib/python2.7/dist-packages/requests/sessions.py(382)request()
-> resp = self.send(prep, **send_kwargs)
  /usr/local/lib/python2.7/dist-packages/requests/sessions.py(485)send()
-> r = adapter.send(request, **kwargs)
  /usr/local/lib/python2.7/dist-packages/requests/adapters.py(324)send()
-> timeout=timeout
  /usr/local/lib/python2.7/dist-packages/requests/packages/urllib3/connectionpool.py(478)urlopen()
-> body=body, headers=headers)
  /usr/local/lib/python2.7/dist-packages/requests/packages/urllib3/connectionpool.py(285)_make_request()
-> conn.request(method, url, **httplib_request_kw)
  /usr/lib/python2.7/httplib.py(958)request()
-> self._send_request(method, url, body, headers)

在httplib机制内部，我们可以看到HTTPConnection。_send_request间接使用HTTPConnection。_send_output，它最终创建原始请求和主体(如果存在的话)，并使用HTTPConnection。分别发送。发送最终到达套接字。

由于没有钩子来做你想做的事情，作为最后的手段，你可以monkey patch httplib来获取内容。这是一个脆弱的解决方案，如果更改了httplib，您可能需要对其进行调整。如果你打算使用这个解决方案来分发软件，你可能会考虑打包httplib而不是使用系统的，这很简单，因为它是一个纯python模块。

唉，话不多说，解决方案:

import requests
import httplib

def patch_send():
    old_send= httplib.HTTPConnection.send
    def new_send( self, data ):
        print data
        return old_send(self, data) #return is not necessary, but never hurts, in case the library is changed
    httplib.HTTPConnection.send= new_send

patch_send()
requests.get("http://www.python.org")

它产生输出:

GET / HTTP/1.1
Host: www.python.org
Accept-Encoding: gzip, deflate, compress
Accept: */*
User-Agent: python-requests/2.1.0 CPython/2.7.3 Linux/3.2.0-23-generic-pae

因为v1.2.3 Requests添加了PreparedRequest对象。根据文档，“它包含将被发送到服务器的确切字节”。

你可以用它来打印一个请求，像这样:

import requests

req = requests.Request('POST','http://stackoverflow.com',headers={'X-Custom':'Test'},data='a=1&b=2')
prepared = req.prepare()

def pretty_print_POST(req):
    """
    At this point it is completely built and ready
    to be fired; it is "prepared".

    However pay attention at the formatting used in 
    this function because it is programmed to be pretty 
    printed and may differ from the actual request.
    """
    print('{}\n{}\r\n{}\r\n\r\n{}'.format(
        '-----------START-----------',
        req.method + ' ' + req.url,
        '\r\n'.join('{}: {}'.format(k, v) for k, v in req.headers.items()),
        req.body,
    ))

pretty_print_POST(prepared)

生产:

-----------START-----------
POST http://stackoverflow.com/
Content-Length: 7
X-Custom: Test

a=1&b=2

然后你可以用这个发送实际的请求:

s = requests.Session()
s.send(prepared)

这些链接指向可用的最新文档，因此它们的内容可能会发生变化: 高级-准备好的请求和API -低级类

下面是一个代码，它是相同的，但有响应头:

import socket
def patch_requests():
    old_readline = socket._fileobject.readline
    if not hasattr(old_readline, 'patched'):
        def new_readline(self, size=-1):
            res = old_readline(self, size)
            print res,
            return res
        new_readline.patched = True
        socket._fileobject.readline = new_readline
patch_requests()

我花了很长时间找这个，所以我把它留在这里，如果有人需要的话。

更好的想法是使用requests_toolbelt库，它可以将请求和响应都转储为字符串，以便打印到控制台。它处理了上面的解决方案不能很好处理的文件和编码的所有棘手情况。

其实很简单:

import requests
from requests_toolbelt.utils import dump

resp = requests.get('https://httpbin.org/redirect/5')
data = dump.dump_all(resp)
print(data.decode('utf-8'))

来源:https://toolbelt.readthedocs.org/en/latest/dumputils.html

你可以通过输入:

pip install requests_toolbelt

import requests

response = requests.post('http://httpbin.org/post', data={'key1': 'value1'})
print(response.request.url)
print(response.request.body)
print(response.request.headers)

响应对象有一个.request属性，它是被发送的PreparedRequest对象。