我有一个基本的Node.js应用程序，我试图使用Express框架启动。我有一个views文件夹，其中有一个index.html文件。但是我在加载网页时收到以下错误:
Error: Cannot find module 'html'
下面是我的代码。
var express = require('express');
var app = express.createServer();
app.use(express.staticProvider(__dirname + '/public'));
app.get('/', function(req, res) {
res.render('index.html');
});
app.listen(8080, '127.0.0.1')
我错过了什么?
当前回答
我不想依赖于ejs来简单地传递HTML文件，所以我只是自己写了一个小渲染器:
const Promise = require( "bluebird" );
const fs = Promise.promisifyAll( require( "fs" ) );
app.set( "view engine", "html" );
app.engine( ".html", ( filename, request, done ) => {
fs.readFileAsync( filename, "utf-8" )
.then( html => done( null, html ) )
.catch( done );
} );
其他回答
表达4.倍
res.sendFile(path [， options] [， fn])
发送.html文件，没有模板引擎…
//...
// Node modules
const path = require('path')
//...
// Set path to views directory
app.set('views', path.join(__dirname, 'views'))
/**
* App routes
*/
app.get('/', (req, res) => {
res.sendFile('index.html', { root: app.get('views') })
})
//...
.
├── node_modules
│
├── views
│ ├──index.html
└── app.js
这些答案很多都已经过时了。
使用快捷3.0.0和3.1.0，以下工作:
app.set('views', __dirname + '/views');
app.engine('html', require('ejs').renderFile);
请参阅下面的注释，了解表达式3.4+的替代语法和注意事项:
app.set('view engine', 'ejs');
然后你可以这样做:
app.get('/about', function (req, res)
{
res.render('about.html');
});
这里假设views子文件夹中有视图，并且已经安装了ejs节点模块。如果不是，在Node控制台中执行以下命令:
npm install ejs --save
如果你使用express framework到node.js
安装 npm EJS
然后添加配置文件
app.set('port', process.env.PORT || 3000);
app.set('views', __dirname + '/views');
app.set('view engine', 'ejs');
app.set('view engine', 'jade');
app.use(express.favicon());
app.use(express.logger('dev'));
app.use(express.bodyParser());
app.use(express.methodOverride());
app.use(app.router)
;
从exports模块form.js中呈现页面 HTML文件在视图目录 扩展ejs文件名称为 form.html.ejs
然后创建form.js
res.render(“form.html.ejs”);
你可以让jade包含一个普通的HTML页面:
在视图/ index.jade
include plain.html
在视图/ plain.html
<!DOCTYPE html>
...
而app.js仍然可以渲染jade:
res.render(index)
It is very sad that it is about 2020 still express hasn't added a way to render an HTML page without using sendFile method of the response object. Using sendFile is not a problem but passing argument to it in the form of path.join(__dirname, 'relative/path/to/file') doesn't feel right. Why should a user join __dirname to the file path? It should be done by default. Why can't the root of the server be by defalut the project directory? Also, installing a templating dependency just to render a static HTML file is again not correct. I don't know the correct way to tackle the issue, but if I had to serve a static HTML, then I would do something like:
const PORT = 8154;
const express = require('express');
const app = express();
app.use(express.static('views'));
app.listen(PORT, () => {
console.log(`Server is listening at port http://localhost:${PORT}`);
});
The above example assumes that the project structure has a views directory and the static HTML files are inside it. For example, let's say, the views directory has two HTML files named index.html and about.html, then to access them, we can visit: localhost:8153/index.html or just localhost:8153/ to load the index.html page and localhost:8153/about.html to load the about.html. We can use a similar approach to serve a react/angular app by storing the artifacts in the views directory or just using the default dist/<project-name> directory and configure it in the server js as follows:
app.use(express.static('dist/<project-name>'));
