你可以使用process.env.PWD来获取当前应用程序的文件夹路径。

这个命令返回当前目录:

var currentPath = process.cwd();

例如，使用路径读取文件:

var fs = require('fs');
fs.readFile(process.cwd() + "\\text.txt", function(err, data)
{
    if(err)
        console.log(err)
    else
        console.log(data.toString());
});

当涉及到主脚本时，它非常简单:

process.argv[1]

来自Node.js文档:

process.argv 包含命令行参数的数组。第一个元素是“node”，第二个元素是JavaScript文件的路径。下一个元素将是任何额外的命令行参数。

如果你需要知道模块文件的路径，那么使用__filename。

Node.js 10支持ECMAScript模块，其中__dirname和__filename不再可用。

然后，要获得当前ES模块的路径，必须使用:

import { fileURLToPath } from 'url';

const __filename = fileURLToPath(import.meta.url);

对于包含当前模块的目录:

import { dirname } from 'path';
import { fileURLToPath } from 'url';

const __dirname = dirname(fileURLToPath(import.meta.url));

NodeJS公开了一个名为__dirname的全局变量。

__dirname返回JavaScript文件所在文件夹的完整路径。

因此，作为一个例子，对于Windows，如果我们用下面的行创建一个脚本文件:

console.log(__dirname);

然后使用以下命令运行脚本:

node ./innerFolder1/innerFolder2/innerFolder3/index.js

输出将是: C: \用户…<项目目录> \ innerFolder1 \ innerFolder2 \ innerFolder3

I know this is pretty old, and the original question I was responding to is marked as duplicate and directed here, but I ran into an issue trying to get jasmine-reporters to work and didn't like the idea that I had to downgrade in order for it to work. I found out that jasmine-reporters wasn't resolving the savePath correctly and was actually putting the reports folder output in jasmine-reporters directory instead of the root directory of where I ran gulp. In order to make this work correctly I ended up using process.env.INIT_CWD to get the initial Current Working Directory which should be the directory where you ran gulp. Hope this helps someone.

var reporters = require('jasmine-reporters');
var junitReporter = new reporters.JUnitXmlReporter({
  savePath: process.env.INIT_CWD + '/report/e2e/',
  consolidateAll: true,
  captureStdout: true
 });