如果你想在shell脚本中使用类似$0的东西，试试这个:

var path = require('path');

var command = getCurrentScriptPath();

console.log(`Usage: ${command} <foo> <bar>`);

function getCurrentScriptPath () {
    // Relative path from current working directory to the location of this script
    var pathToScript = path.relative(process.cwd(), __filename);

    // Check if current working dir is the same as the script
    if (process.cwd() === __dirname) {
        // E.g. "./foobar.js"
        return '.' + path.sep + pathToScript;
    } else {
        // E.g. "foo/bar/baz.js"
        return pathToScript;
    }
}

如果你想在shell脚本中使用类似$0的东西，试试这个:

var path = require('path');

var command = getCurrentScriptPath();

console.log(`Usage: ${command} <foo> <bar>`);

function getCurrentScriptPath () {
    // Relative path from current working directory to the location of this script
    var pathToScript = path.relative(process.cwd(), __filename);

    // Check if current working dir is the same as the script
    if (process.cwd() === __dirname) {
        // E.g. "./foobar.js"
        return '.' + path.sep + pathToScript;
    } else {
        // E.g. "foo/bar/baz.js"
        return pathToScript;
    }
}

NodeJS公开了一个名为__dirname的全局变量。

__dirname返回JavaScript文件所在文件夹的完整路径。

因此，作为一个例子，对于Windows，如果我们用下面的行创建一个脚本文件:

console.log(__dirname);

然后使用以下命令运行脚本:

node ./innerFolder1/innerFolder2/innerFolder3/index.js

输出将是: C: \用户…<项目目录> \ innerFolder1 \ innerFolder2 \ innerFolder3

如果你使用pkg来打包你的应用，你会发现这个表达式很有用:

appDirectory = require('path').dirname(process.pkg ? process.execPath : (require.main ? require.main.filename : process.argv[0]));

process.pkg tells if the app has been packaged by pkg. process.execPath holds the full path of the executable, which is /usr/bin/node or similar for direct invocations of scripts (node test.js), or the packaged app. require.main.filename holds the full path of the main script, but it's empty when Node runs in interactive mode. __dirname holds the full path of the current script, so I'm not using it (although it may be what OP asks; then better use appDirectory = process.pkg ? require('path').dirname(process.execPath) : (__dirname || require('path').dirname(process.argv[0])); noting that in interactive mode __dirname is empty. For interactive mode, use either process.argv[0] to get the path to the Node executable or process.cwd() to get the current directory.

你可以使用process.env.PWD来获取当前应用程序的文件夹路径。

我又看了一遍文件后找到的。我要找的是__filename和__dirname模块级变量。

__filename是当前模块的文件名。这是当前模块文件的解析绝对路径。(例:/ home /凯尔/一些/ dir / file.js) __dirname是当前模块的目录名。(例:/ home /凯尔/一些/ dir)