我正在使用这段代码:
$('body').click(function() {
$('.form_wrapper').hide();
});
$('.form_wrapper').click(function(event){
event.stopPropagation();
});
这个HTML:
<div class="form_wrapper">
<a class="agree" href="javascript:;">I Agree</a>
<a class="disagree" href="javascript:;">Disagree</a>
</div>
问题是，我有链接在div和当他们不再工作时，点击。
当前回答
var $container = $("#popup_container"); $container.click(function(e) { if (e.target.id == $container.attr("id")) { $(this).hide(); } }); #popup_container { background: rgba(200,200,200,0.6); width: 100vh; height: 100vh; position: fixed; display: flex; justify-content: center; align-items: center; } #popup { background: yellow; border: 1px solid black; position: absolute; width: 50%; height: 50%; display: flex; justify-content: center; align-items: center; } <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <div id="popup_container"> <div id="popup"> Popup </div> </div>
https://jsfiddle.net/041pj7re/
其他回答
根据文档，.blur()不仅仅适用于<input>标记。例如:
$('.form_wrapper').blur(function(){
$(this).hide();
});
这么多答案我都用不上。相反，我采取了公认的答案(工作得很好)，并缩短为以下(使用后代选择器):
$(document).mouseup(function(e)
{
if (!$(e.target).is("#targetSelector,#targetSelector *")) {
$('#targetSelector').hide();
}
});
因为它只以用户交互的速度运行，没有给变量赋值
$(document).click(function(event) {
if ( !$(event.target).hasClass('form_wrapper')) {
$(".form_wrapper").hide();
}
});
$(document).ready(function() {
$('.headings').click(function () {$('#sub1').css("display",""); });
$('.headings').click(function () {return false;});
$('#sub1').click(function () {return false;});
$('body').click(function () {$('#sub1').css("display","none");
})});
你最好这样写:
var mouse_is_inside = false;
$(document).ready(function()
{
$('.form_content').hover(function(){
mouse_is_inside=true;
}, function(){
mouse_is_inside=false;
});
$("body").mouseup(function(){
if(! mouse_is_inside) $('.form_wrapper').hide();
});
});
