我惊奇地发现,今天我找不到任何简单的方法来用Java将InputStream的内容写入OutputStream。显然,编写字节缓冲区代码并不难,但我怀疑我只是缺少了一些可以使我的工作更简单(并且代码更清晰)的东西。
那么,给定一个InputStream in和一个OutputStream out,是否有一种更简单的方法来编写下面的代码?
byte[] buffer = new byte[1024];
int len = in.read(buffer);
while (len != -1) {
out.write(buffer, 0, len);
len = in.read(buffer);
}
JDK使用相同的代码,因此似乎没有“更简单”的方法,没有笨重的第三方库(可能不会做任何不同的事情)。下面是直接从java.nio.file.Files.java中复制的:
// buffer size used for reading and writing
private static final int BUFFER_SIZE = 8192;
/**
* Reads all bytes from an input stream and writes them to an output stream.
*/
private static long copy(InputStream source, OutputStream sink) throws IOException {
long nread = 0L;
byte[] buf = new byte[BUFFER_SIZE];
int n;
while ((n = source.read(buf)) > 0) {
sink.write(buf, 0, n);
nread += n;
}
return nread;
}
我使用ByteStreamKt。copyTo(src, dst, buffer.length)方法
这是我的代码
public static void replaceCurrentDb(Context context, Uri newDbUri) {
try {
File currentDb = context.getDatabasePath(DATABASE_NAME);
if (currentDb.exists()) {
InputStream src = context.getContentResolver().openInputStream(newDbUri);
FileOutputStream dst = new FileOutputStream(currentDb);
final byte[] buffer = new byte[8 * 1024];
ByteStreamsKt.copyTo(src, dst, buffer.length);
src.close();
dst.close();
Toast.makeText(context, "SUCCESS! Your selected file is set as current menu.", Toast.LENGTH_LONG).show();
}
else
Log.e("DOWNLOAD:::: Database", " fail, database not found");
}
catch (IOException e) {
Toast.makeText(context, "Data Download FAIL.", Toast.LENGTH_LONG).show();
Log.e("DOWNLOAD FAIL!!!", "fail, reason:", e);
}
}