下面的代码片段下载一个文件。

该文件以其文件名保存为指定的url。

import requests

url = "http://example.com/image.jpg"
filename = url.split("/")[-1]
r = requests.get(url, timeout=0.5)

if r.status_code == 200:
    with open(filename, 'wb') as f:
        f.write(r.content)

这里有一个更友好的答案，仍然使用流媒体。

只需定义这些函数并调用getImage()。默认情况下，它将使用与url相同的文件名并写入当前目录，但两者都可以更改。

import requests
from StringIO import StringIO
from PIL import Image

def createFilename(url, name, folder):
    dotSplit = url.split('.')
    if name == None:
        # use the same as the url
        slashSplit = dotSplit[-2].split('/')
        name = slashSplit[-1]
    ext = dotSplit[-1]
    file = '{}{}.{}'.format(folder, name, ext)
    return file

def getImage(url, name=None, folder='./'):
    file = createFilename(url, name, folder)
    with open(file, 'wb') as f:
        r = requests.get(url, stream=True)
        for block in r.iter_content(1024):
            if not block:
                break
            f.write(block)

def getImageFast(url, name=None, folder='./'):
    file = createFilename(url, name, folder)
    r = requests.get(url)
    i = Image.open(StringIO(r.content))
    i.save(file)

if __name__ == '__main__':
    # Uses Less Memory
    getImage('http://www.example.com/image.jpg')
    # Faster
    getImageFast('http://www.example.com/image.jpg')

getImage()的请求内容基于这里的答案，getImageFast()的请求内容基于上面的答案。

下载图像

import requests
Picture_request = requests.get(url)

这是一个非常简单的代码

import requests

response = requests.get("https://i.imgur.com/ExdKOOz.png") ## Making a variable to get image.

file = open("sample_image.png", "wb") ## Creates the file for image
file.write(response.content) ## Saves file content
file.close()

我同样需要使用请求下载图像。我首先尝试了Martijn Pieters的答案，效果很好。但是当我对这个简单的函数做了一个概要时，我发现与urllib和urllib2相比，它使用了太多的函数调用。

然后我尝试了请求模块作者推荐的方法:

import requests
from PIL import Image
# python2.x, use this instead  
# from StringIO import StringIO
# for python3.x,
from io import StringIO

r = requests.get('https://example.com/image.jpg')
i = Image.open(StringIO(r.content))

这大大减少了函数调用的数量，从而加快了我的应用程序的速度。 下面是我的分析器的代码和结果。

#!/usr/bin/python
import requests
from StringIO import StringIO
from PIL import Image
import profile

def testRequest():
    image_name = 'test1.jpg'
    url = 'http://example.com/image.jpg'

    r = requests.get(url, stream=True)
    with open(image_name, 'wb') as f:
        for chunk in r.iter_content():
            f.write(chunk)

def testRequest2():
    image_name = 'test2.jpg'
    url = 'http://example.com/image.jpg'

    r = requests.get(url)
    
    i = Image.open(StringIO(r.content))
    i.save(image_name)

if __name__ == '__main__':
    profile.run('testUrllib()')
    profile.run('testUrllib2()')
    profile.run('testRequest()')

testRequest的结果:

343080 function calls (343068 primitive calls) in 2.580 seconds

和testRequest2的结果:

3129 function calls (3105 primitive calls) in 0.024 seconds

我是这么做的

import requests
from PIL import Image
from io import BytesIO

url = 'your_url'
files = {'file': ("C:/Users/shadow/Downloads/black.jpeg", open('C:/Users/shadow/Downloads/black.jpeg', 'rb'),'image/jpg')}
response = requests.post(url, files=files)

img = Image.open(BytesIO(response.content))
img.show()