我在我的方框中使用虚线样式的边框

.box {
    width: 300px;
    height: 200px;
    border: dotted 1px #f00;
    float: left;
}

我想增加边界上每个点之间的空间。


当前回答

这个技巧对水平和垂直边框都有效:

/*Horizontal*/
background-image: linear-gradient(to right, black 33%, rgba(255,255,255,0) 0%);
background-position: bottom;
background-size: 3px 1px;
background-repeat: repeat-x;

/*Vertical*/
background-image: linear-gradient(black 33%, rgba(255,255,255,0) 0%);
background-position: right;
background-size: 1px 3px;
background-repeat: repeat-y;

你可以用background-size调整大小,用线性梯度百分比调整比例。在这个例子中,我有一条1px的点和2px的间距的虚线。 这样你也可以使用多个背景来创建多个虚线边界。

在这个JSFiddle中尝试一下,或者看看代码片段示例:

div { padding: 10px 50px; } .dotted { border-top: 1px #333 dotted; } .dotted-gradient { background-image: linear-gradient(to right, #333 40%, rgba(255, 255, 255, 0) 20%); background-position: top; background-size: 3px 1px; background-repeat: repeat-x; } .dotted-spaced { background-image: linear-gradient(to right, #333 10%, rgba(255, 255, 255, 0) 0%); background-position: top; background-size: 10px 1px; background-repeat: repeat-x; } .left { float: left; padding: 40px 10px; background-color: #F0F0DA; } .left.dotted { border-left: 1px #333 dotted; border-top: none; } .left.dotted-gradient { background-image: linear-gradient(to bottom, #333 40%, rgba(255, 255, 255, 0) 20%); background-position: left; background-size: 1px 3px; background-repeat: repeat-y; } .left.dotted-spaced { background-image: linear-gradient(to bottom, #333 10%, rgba(255, 255, 255, 0) 0%); background-position: left; background-size: 1px 10px; background-repeat: repeat-y; } <div>no <br>border</div> <div class='dotted'>dotted <br>border</div> <div class='dotted-gradient'>dotted <br>with gradient</div> <div class='dotted-spaced'>dotted <br>spaced</div> <div class='left'>no <br>border</div> <div class='dotted left'>dotted <br>border</div> <div class='dotted-gradient left'>dotted <br>with gradient</div> <div class='dotted-spaced left'>dotted <br>spaced</div>

其他回答

你不能用纯CSS做到这一点——CSS3规范甚至对此有一个特定的引用:

注意:不能控制点和破折号的间距,也不能控制破折号的长度。实现被鼓励选择一个使角对称的间距。

但是,您可以使用边框图像或背景图像来实现此目的。

这个技巧对水平和垂直边框都有效:

/*Horizontal*/
background-image: linear-gradient(to right, black 33%, rgba(255,255,255,0) 0%);
background-position: bottom;
background-size: 3px 1px;
background-repeat: repeat-x;

/*Vertical*/
background-image: linear-gradient(black 33%, rgba(255,255,255,0) 0%);
background-position: right;
background-size: 1px 3px;
background-repeat: repeat-y;

你可以用background-size调整大小,用线性梯度百分比调整比例。在这个例子中,我有一条1px的点和2px的间距的虚线。 这样你也可以使用多个背景来创建多个虚线边界。

在这个JSFiddle中尝试一下,或者看看代码片段示例:

div { padding: 10px 50px; } .dotted { border-top: 1px #333 dotted; } .dotted-gradient { background-image: linear-gradient(to right, #333 40%, rgba(255, 255, 255, 0) 20%); background-position: top; background-size: 3px 1px; background-repeat: repeat-x; } .dotted-spaced { background-image: linear-gradient(to right, #333 10%, rgba(255, 255, 255, 0) 0%); background-position: top; background-size: 10px 1px; background-repeat: repeat-x; } .left { float: left; padding: 40px 10px; background-color: #F0F0DA; } .left.dotted { border-left: 1px #333 dotted; border-top: none; } .left.dotted-gradient { background-image: linear-gradient(to bottom, #333 40%, rgba(255, 255, 255, 0) 20%); background-position: left; background-size: 1px 3px; background-repeat: repeat-y; } .left.dotted-spaced { background-image: linear-gradient(to bottom, #333 10%, rgba(255, 255, 255, 0) 0%); background-position: left; background-size: 1px 10px; background-repeat: repeat-y; } <div>no <br>border</div> <div class='dotted'>dotted <br>border</div> <div class='dotted-gradient'>dotted <br>with gradient</div> <div class='dotted-spaced'>dotted <br>spaced</div> <div class='left'>no <br>border</div> <div class='dotted left'>dotted <br>border</div> <div class='dotted-gradient left'>dotted <br>with gradient</div> <div class='dotted-spaced left'>dotted <br>spaced</div>

我做了一个javascript函数,用svg创建点。你可以在javascript代码中调整点间距和大小。

var make_dotted_borders = function() { // EDIT THESE SETTINGS: var spacing = 8; var dot_width = 2; var dot_height = 2; //--------------------- var dotteds = document.getElementsByClassName("dotted"); for (var i = 0; i < dotteds.length; i++) { var width = dotteds[i].clientWidth + 1.5; var height = dotteds[i].clientHeight; var horizontal_count = Math.floor(width / spacing); var h_spacing_percent = 100 / horizontal_count; var h_subtraction_percent = ((dot_width / 2) / width) * 100; var vertical_count = Math.floor(height / spacing); var v_spacing_percent = 100 / vertical_count; var v_subtraction_percent = ((dot_height / 2) / height) * 100; var dot_container = document.createElement("div"); dot_container.classList.add("dot_container"); dot_container.style.display = getComputedStyle(dotteds[i], null).display; var clone = dotteds[i].cloneNode(true); dotteds[i].parentElement.replaceChild(dot_container, dotteds[i]); dot_container.appendChild(clone); for (var x = 0; x < horizontal_count; x++) { // The Top Dots var dot = document.createElement("div"); dot.classList.add("dot"); dot.style.width = dot_width + "px"; dot.style.height = dot_height + "px"; var left_percent = (h_spacing_percent * x) - h_subtraction_percent; dot.style.left = left_percent + "%"; dot.style.top = (-dot_height / 2) + "px"; dot_container.appendChild(dot); // The Bottom Dots var dot = document.createElement("div"); dot.classList.add("dot"); dot.style.width = dot_width + "px"; dot.style.height = dot_height + "px"; dot.style.left = (h_spacing_percent * x) - h_subtraction_percent + "%"; dot.style.top = height - (dot_height / 2) + "px"; dot_container.appendChild(dot); } for (var y = 1; y < vertical_count; y++) { // The Left Dots: var dot = document.createElement("div"); dot.classList.add("dot"); dot.style.width = dot_width + "px"; dot.style.height = dot_height + "px"; dot.style.left = (-dot_width / 2) + "px"; dot.style.top = (v_spacing_percent * y) - v_subtraction_percent + "%"; dot_container.appendChild(dot); } for (var y = 0; y < vertical_count + 1; y++) { // The Right Dots: var dot = document.createElement("div"); dot.classList.add("dot"); dot.style.width = dot_width + "px"; dot.style.height = dot_height + "px"; dot.style.left = width - (dot_width / 2) + "px"; if (y < vertical_count) { dot.style.top = (v_spacing_percent * y) - v_subtraction_percent + "%"; } else { dot.style.top = height - (dot_height / 2) + "px"; } dot_container.appendChild(dot); } } } make_dotted_borders(); div.dotted { display: inline-block; padding: 0.5em; } div.dot_container { position: relative; margin-left: 0.25em; margin-right: 0.25em; } div.dot { position: absolute; content: url('data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" height="100" width="100"><circle cx="50" cy="50" r="50" fill="black" /></svg>'); } <div class="dotted">Lorem Ipsum</div>

你可以创建一个画布(通过javascript)并在里面画一条虚线。在画布内,您可以控制多长破折号和之间的空间应该。

这是一个古老但仍然非常相关的话题。目前最上面的答案很好,但只适用于非常小的点。正如Bhojendra Rauniyar已经在评论中指出的,对于较大的点(>2px),点看起来是方形的,而不是圆形的。我发现这个页面搜索的是间隔点,而不是间隔方块(甚至破折号,就像这里的一些答案使用的那样)。

在此基础上,我使用了径向梯度。同样,使用Ukuser32的答案,可以很容易地为所有四个边框重复点属性。只有角落不完美。

div { padding: 1em; background-image: radial-gradient(circle at 2.5px, #000 1.25px, rgba(255,255,255,0) 2.5px), radial-gradient(circle, #000 1.25px, rgba(255,255,255,0) 2.5px), radial-gradient(circle at 2.5px, #000 1.25px, rgba(255,255,255,0) 2.5px), radial-gradient(circle, #000 1.25px, rgba(255,255,255,0) 2.5px); background-position: top, right, bottom, left; background-size: 15px 5px, 5px 15px; background-repeat: repeat-x, repeat-y; } <div>Some content with round, spaced dots as border</div>

径向梯度期望:

形状和可选位置 两个或更多的停止:一个颜色和半径

在这里,我想要一个直径为5像素(半径为2.5px)的点,点之间的直径为2倍(10px),加起来为15px。背景尺寸应该与这些相匹配。

这两个站点的定义是这样的点是漂亮的和光滑的:纯黑色的一半半径和比梯度到整个半径。