从一个表中查找另一个表中不存在的记录

我有以下两个表(在MySQL):

Phone_book
+----+------+--------------+
| id | name | phone_number |
+----+------+--------------+
| 1  | John | 111111111111 |
+----+------+--------------+
| 2  | Jane | 222222222222 |
+----+------+--------------+

Call
+----+------+--------------+
| id | date | phone_number |
+----+------+--------------+
| 1  | 0945 | 111111111111 |
+----+------+--------------+
| 2  | 0950 | 222222222222 |
+----+------+--------------+
| 3  | 1045 | 333333333333 |
+----+------+--------------+

我如何找出哪些电话是由电话号码不在电话簿中的人打的?期望的输出将是:

Call
+----+------+--------------+
| id | date | phone_number |
+----+------+--------------+
| 3  | 1045 | 333333333333 |
+----+------+--------------+

当前回答

另外,

select id from call
minus
select id from phone_number

2017-08-21 11:55:32

其他回答

SELECT name, phone_number FROM Call a
WHERE a.phone_number NOT IN (SELECT b.phone_number FROM Phone_book b)

2015-12-09 16:17:24

另外,

select id from call
minus
select id from phone_number

2017-08-21 11:55:32

我认为

SELECT CALL.* FROM CALL LEFT JOIN Phone_book ON 
CALL.id = Phone_book.id WHERE Phone_book.name IS NULL

2012-02-15 12:39:13

有几种不同的方法来做到这一点，不同的效率，这取决于你的查询优化器有多好，以及你的两个表的相对大小:

这是最短的语句，如果你的电话簿很短，可能是最快的:

SELECT  *
FROM    Call
WHERE   phone_number NOT IN (SELECT phone_number FROM Phone_book)

或者(感谢Alterlife)

SELECT *
FROM   Call
WHERE  NOT EXISTS
  (SELECT *
   FROM   Phone_book
   WHERE  Phone_book.phone_number = Call.phone_number)

或者(感谢WOPR)

SELECT * 
FROM   Call
LEFT OUTER JOIN Phone_Book
  ON (Call.phone_number = Phone_book.phone_number)
  WHERE Phone_book.phone_number IS NULL

(忽略这一点，正如其他人所说，通常最好只选择你想要的列，而不是“*”)

2008-12-15 09:35:14

SELECT t1.ColumnID,
CASE 
    WHEN NOT EXISTS( SELECT t2.FieldText  
                     FROM Table t2 
                     WHERE t2.ColumnID = t1.ColumnID) 
    THEN t1.FieldText
    ELSE t2.FieldText
END FieldText       
FROM Table1 t1, Table2 t2

2013-10-24 14:53:22

从一个表中查找另一个表中不存在的记录

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