有人知道一种方法(lodash如果可能的话)通过对象键分组对象数组，然后根据分组创建一个新的对象数组吗?例如，我有一个汽车对象数组:
const cars = [
{
'make': 'audi',
'model': 'r8',
'year': '2012'
}, {
'make': 'audi',
'model': 'rs5',
'year': '2013'
}, {
'make': 'ford',
'model': 'mustang',
'year': '2012'
}, {
'make': 'ford',
'model': 'fusion',
'year': '2015'
}, {
'make': 'kia',
'model': 'optima',
'year': '2012'
},
];
我想创建一个新的汽车对象数组，由make分组:
const cars = {
'audi': [
{
'model': 'r8',
'year': '2012'
}, {
'model': 'rs5',
'year': '2013'
},
],
'ford': [
{
'model': 'mustang',
'year': '2012'
}, {
'model': 'fusion',
'year': '2015'
}
],
'kia': [
{
'model': 'optima',
'year': '2012'
}
]
}
@metakungfu answer略有不同，主要区别在于它从结果对象中省略了原始键，因为在某些情况下对象本身不再需要它，因为它现在在父对象中可用。
const groupBy = (_k, a) => a.reduce((r, {[_k]:k, ...p}) => ({
...r, ...{[k]: (
r[k] ? [...r[k], {...p}] : [{...p}]
)}
}), {});
考虑到您的原始输入对象:
console.log(groupBy('make', cars));
会导致:
{
audi: [
{ model: 'r8', year: '2012' },
{ model: 'rs5', year: '2013' }
],
ford: [
{ model: 'mustang', year: '2012' },
{ model: 'fusion', year: '2015' }
],
kia: [
{ model: 'optima', year: '2012' }
]
}
另一个解决方案:
Var汽车= [
{“使”:“奥迪”,“模型”:“r8”,“年”:“2012”},{“使”:“奥迪”,“模型”:“生活费”,“年”:“2013”},
{“使”:“福特”,“模型”:“野马”,“年”:“2012”},{“使”:“福特”,“模型”:“融合”,“年”:“2015”},
{'make': 'kia'，'model': 'optima'，'year': '2012'}，
];
const reducedCars =汽车。Reduce ((acc， {make, model, year}) => (
｛
acc,
[make]: acc[make] ?[…Acc [make]， {model, year}]: [{model, year}]，
｝
), {});
console.log (reducedCars);
我用REAL GROUP BY作为JS数组的例子和这个任务完全一样
const inputArray = [
{ Phase: "Phase 1", Step: "Step 1", Task: "Task 1", Value: "5" },
{ Phase: "Phase 1", Step: "Step 1", Task: "Task 2", Value: "10" },
{ Phase: "Phase 1", Step: "Step 2", Task: "Task 1", Value: "15" },
{ Phase: "Phase 1", Step: "Step 2", Task: "Task 2", Value: "20" },
{ Phase: "Phase 2", Step: "Step 1", Task: "Task 1", Value: "25" },
{ Phase: "Phase 2", Step: "Step 1", Task: "Task 2", Value: "30" },
{ Phase: "Phase 2", Step: "Step 2", Task: "Task 1", Value: "35" },
{ Phase: "Phase 2", Step: "Step 2", Task: "Task 2", Value: "40" }
];
var outObject = inputArray.reduce(function(a, e) {
// GROUP BY estimated key (estKey), well, may be a just plain key
// a -- Accumulator result object
// e -- sequentally checked Element, the Element that is tested just at this itaration
// new grouping name may be calculated, but must be based on real value of real field
let estKey = (e['Phase']);
(a[estKey] ? a[estKey] : (a[estKey] = null || [])).push(e);
return a;
}, {});
console.log(outObject);
您正在寻找_.groupBy()。
如果需要，从对象中删除分组的属性应该很简单:
Const cars = [{
“做”:“奥迪”,
“模型”:“r8”,
“年”:“2012”
},{
“做”:“奥迪”,
“模型”:“生活费”,
“年”:“2013”
},{
“做”:“福特”,
“模型”:“野马”,
“年”:“2012”
},{
“做”:“福特”,
“模型”:“融合”,
“年”:“2015”
},{
“做”:“克钦独立军”,
“模型”:“最佳状态”,
“年”:“2012”
});
Const分组= _。groupBy(cars, car => car.make);
console.log(分组);
< script src = " https://cdn.jsdelivr.net/lodash/4.17.2/lodash.min.js " > < /脚本>
同意除非经常使用这些库，否则不需要外部库。虽然有类似的解决方案，但我发现其中一些很难遵循。如果您试图理解正在发生的事情，这里有一个带有注释的解决方案的要点。
const cars = [{
'make': 'audi',
'model': 'r8',
'year': '2012'
}, {
'make': 'audi',
'model': 'rs5',
'year': '2013'
}, {
'make': 'ford',
'model': 'mustang',
'year': '2012'
}, {
'make': 'ford',
'model': 'fusion',
'year': '2015'
}, {
'make': 'kia',
'model': 'optima',
'year': '2012'
}, ];
/**
* Groups an array of objects by a key an returns an object or array grouped by provided key.
* @param array - array to group objects by key.
* @param key - key to group array objects by.
* @param removeKey - remove the key and it's value from the resulting object.
* @param outputType - type of structure the output should be contained in.
*/
const groupBy = (
inputArray,
key,
removeKey = false,
outputType = {},
) => {
return inputArray.reduce(
(previous, current) => {
// Get the current value that matches the input key and remove the key value for it.
const {
[key]: keyValue
} = current;
// remove the key if option is set
removeKey && keyValue && delete current[key];
// If there is already an array for the user provided key use it else default to an empty array.
const {
[keyValue]: reducedValue = []
} = previous;
// Create a new object and return that merges the previous with the current object
return Object.assign(previous, {
[keyValue]: reducedValue.concat(current)
});
},
// Replace the object here to an array to change output object to an array
outputType,
);
};
console.log(groupBy(cars, 'make', true))
