使用react路由器v4 / v5嵌套路由

我目前正在努力使用react路由器v4嵌套路由。

中的路由配置是最接近的例子 React-Router v4文档。

我想把我的应用程序分成2个不同的部分。

一个前台和一个管理区域。

我在想这样的事情:

<Match pattern="/" component={Frontpage}>
  <Match pattern="/home" component={HomePage} />
  <Match pattern="/about" component={AboutPage} />
</Match>
<Match pattern="/admin" component={Backend}>
  <Match pattern="/home" component={Dashboard} />
  <Match pattern="/users" component={UserPage} />
</Match>
<Miss component={NotFoundPage} />

前端的布局和风格与管理区域不同。在frontpage中，home, about，还有一个应该是子路由。

/home应该呈现在Frontpage组件中，/admin/home应该呈现在Backend组件中。

我尝试了一些其他的变化，但我总是以不点击/home或/admin/home结束。

最终解决方案:

这是我现在使用的最终解决方案。这个例子还有一个全局错误组件，就像传统的404页面一样。

import React, { Component } from 'react';
import { Switch, Route, Redirect, Link } from 'react-router-dom';

const Home = () => <div><h1>Home</h1></div>;
const User = () => <div><h1>User</h1></div>;
const Error = () => <div><h1>Error</h1></div>

const Frontend = props => {
  console.log('Frontend');
  return (
    <div>
      <h2>Frontend</h2>
      <p><Link to="/">Root</Link></p>
      <p><Link to="/user">User</Link></p>
      <p><Link to="/admin">Backend</Link></p>
      <p><Link to="/the-route-is-swiggity-swoute">Swiggity swooty</Link></p>
      <Switch>
        <Route exact path='/' component={Home}/>
        <Route path='/user' component={User}/>
        <Redirect to={{
          state: { error: true }
        }} />
      </Switch>
      <footer>Bottom</footer>
    </div>
  );
}

const Backend = props => {
  console.log('Backend');
  return (
    <div>
      <h2>Backend</h2>
      <p><Link to="/admin">Root</Link></p>
      <p><Link to="/admin/user">User</Link></p>
      <p><Link to="/">Frontend</Link></p>
      <p><Link to="/admin/the-route-is-swiggity-swoute">Swiggity swooty</Link></p>
      <Switch>
        <Route exact path='/admin' component={Home}/>
        <Route path='/admin/user' component={User}/>
        <Redirect to={{
          state: { error: true }
        }} />
      </Switch>
      <footer>Bottom</footer>
    </div>
  );
}

class GlobalErrorSwitch extends Component {
  previousLocation = this.props.location

  componentWillUpdate(nextProps) {
    const { location } = this.props;

    if (nextProps.history.action !== 'POP'
      && (!location.state || !location.state.error)) {
        this.previousLocation = this.props.location
    };
  }

  render() {
    const { location } = this.props;
    const isError = !!(
      location.state &&
      location.state.error &&
      this.previousLocation !== location // not initial render
    )

    return (
      <div>
        {          
          isError
          ? <Route component={Error} />
          : <Switch location={isError ? this.previousLocation : location}>
              <Route path="/admin" component={Backend} />
              <Route path="/" component={Frontend} />
            </Switch>}
      </div>
    )
  }
}

class App extends Component {
  render() {
    return <Route component={GlobalErrorSwitch} />
  }
}

export default App;

当前回答

React Router v5的完整答案。


const Router = () => {
  return (
    <Switch>
      <Route path={"/"} component={LandingPage} exact />
      <Route path={"/games"} component={Games} />
      <Route path={"/game-details/:id"} component={GameDetails} />
      <Route
        path={"/dashboard"}
        render={({ match: { path } }) => (
          <Dashboard>
            <Switch>
              <Route
                exact
                path={path + "/"}
                component={DashboardDefaultContent}
              />
              <Route path={`${path}/inbox`} component={Inbox} />
              <Route
                path={`${path}/settings-and-privacy`}
                component={SettingsAndPrivacy}
              />
              <Redirect exact from={path + "/*"} to={path} />
            </Switch>
          </Dashboard>
        )}
      />
      <Route path="/not-found" component={NotFound} />
      <Redirect exact from={"*"} to={"/not-found"} />
    </Switch>
  );
};

export default Router;

const Dashboard = ({ children }) => {
  return (
    <Grid
      container
      direction="row"
      justify="flex-start"
      alignItems="flex-start"
    >
      <DashboardSidebarNavigation />
      {children}
    </Grid>
  );
};

export default Dashboard;

Github回购在这里。https://github.com/webmasterdevlin/react-router-5-demo

2020-08-30 12:35:35

其他回答

我更喜欢使用react函数。这个解决方案很简短，可读性更强

const MainAppRoutes = () => (
    <Switch>
        <Route exact path='/' component={HomePage} />
        {AdminRoute()}                  
        {SampleRoute("/sample_admin")}  
    </Switch>
);

/*first implementation: without params*/
const AdminRoute = () => ([
    <Route path='/admin/home' component={AdminHome} />,
    <Route path='/admin/about' component={AdminAbout} />
]);

/*second implementation: with params*/
const SampleRoute = (main) => ([
    <Route path={`${main}`} component={MainPage} />,
    <Route path={`${main}/:id`} component={MainPage} />
]);

2021-08-22 09:12:44

React Router v5的完整答案。


const Router = () => {
  return (
    <Switch>
      <Route path={"/"} component={LandingPage} exact />
      <Route path={"/games"} component={Games} />
      <Route path={"/game-details/:id"} component={GameDetails} />
      <Route
        path={"/dashboard"}
        render={({ match: { path } }) => (
          <Dashboard>
            <Switch>
              <Route
                exact
                path={path + "/"}
                component={DashboardDefaultContent}
              />
              <Route path={`${path}/inbox`} component={Inbox} />
              <Route
                path={`${path}/settings-and-privacy`}
                component={SettingsAndPrivacy}
              />
              <Redirect exact from={path + "/*"} to={path} />
            </Switch>
          </Dashboard>
        )}
      />
      <Route path="/not-found" component={NotFound} />
      <Redirect exact from={"*"} to={"/not-found"} />
    </Switch>
  );
};

export default Router;

const Dashboard = ({ children }) => {
  return (
    <Grid
      container
      direction="row"
      justify="flex-start"
      alignItems="flex-start"
    >
      <DashboardSidebarNavigation />
      {children}
    </Grid>
  );
};

export default Dashboard;

Github回购在这里。https://github.com/webmasterdevlin/react-router-5-demo

2020-08-30 12:35:35

**这段代码适用于v6**

index.js

ReactDOM.render(
  <React.StrictMode>
    <BrowserRouter>
      <Routes>
        <Route path="/" element={<App />}>
          <Route path="login" element={<Login />} />
          <Route path="home" element={<Home />} />
        </Route>
      </Routes>
    </BrowserRouter>
  </React.StrictMode>,
  document.getElementById('root')
);

App.js:

function App(props) {
  useEffect(() => {
    console.log('reloaded');
// Checking, if Parent component re-rendering or not *it should not be, in the sense of performance*, this code doesn't re-render parent component while loading children
  });
  return (
    <div className="App">
      <Link to="login">Login</Link>
      <Link to="home">Home</Link>
      <Outlet /> // This line is important, otherwise we will be shown with empty component
    </div>
  );
}

const Login = () => {
    return (
        <div>
            Login Component
        </div>
    )
};

home.js:

const Home= () => {
    return (
        <div>
            Home Component
        </div>
    )
};

2022-01-07 08:56:49

像这样的东西。

import React from 'react'; import { BrowserRouter as Router, Route, NavLink, Switch, Link } from 'react-router-dom'; import '../assets/styles/App.css'; const Home = () => <NormalNavLinks> <h1>HOME</h1> </NormalNavLinks>; const About = () => <NormalNavLinks> <h1>About</h1> </NormalNavLinks>; const Help = () => <NormalNavLinks> <h1>Help</h1> </NormalNavLinks>; const AdminHome = () => <AdminNavLinks> <h1>root</h1> </AdminNavLinks>; const AdminAbout = () => <AdminNavLinks> <h1>Admin about</h1> </AdminNavLinks>; const AdminHelp = () => <AdminNavLinks> <h1>Admin Help</h1> </AdminNavLinks>; const AdminNavLinks = (props) => ( <div> <h2>Admin Menu</h2> <NavLink exact to="/admin">Admin Home</NavLink> <NavLink to="/admin/help">Admin Help</NavLink> <NavLink to="/admin/about">Admin About</NavLink> <Link to="/">Home</Link> {props.children} </div> ); const NormalNavLinks = (props) => ( <div> <h2>Normal Menu</h2> <NavLink exact to="/">Home</NavLink> <NavLink to="/help">Help</NavLink> <NavLink to="/about">About</NavLink> <Link to="/admin">Admin</Link> {props.children} </div> ); const App = () => ( <Router> <div> <Switch> <Route exact path="/" component={Home}/> <Route path="/help" component={Help}/> <Route path="/about" component={About}/> <Route exact path="/admin" component={AdminHome}/> <Route path="/admin/help" component={AdminHelp}/> <Route path="/admin/about" component={AdminAbout}/> </Switch> </div> </Router> ); export default App;

2017-06-01 18:23:00

在react-router-v4中，不嵌套<Routes />。相反，将它们放在另一个<Component />中。

例如

<Route path='/topics' component={Topics}>
  <Route path='/topics/:topicId' component={Topic} />
</Route>

应该成为

<Route path='/topics' component={Topics} />

with

const Topics = ({ match }) => (
  <div>
    <h2>Topics</h2>
    <Link to={`${match.url}/exampleTopicId`}>
      Example topic
    </Link>
    <Route path={`${match.path}/:topicId`} component={Topic}/>
  </div>
)

下面是一个直接来自react-router文档的基本示例。

2017-04-09 19:35:43

使用react路由器v4 / v5嵌套路由

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