它是可能的,在PHP中,在不使用递归或引用的情况下扁平化(bi/multi)维数组?
我只对值感兴趣,所以键可以忽略,我认为在array_map()和array_values()的行。
它是可能的,在PHP中,在不使用递归或引用的情况下扁平化(bi/multi)维数组?
我只对值感兴趣,所以键可以忽略,我认为在array_map()和array_values()的行。
当前回答
您可以使用标准PHP库(SPL)来“隐藏”递归。
$a = array(1,2,array(3,4, array(5,6,7), 8), 9);
$it = new RecursiveIteratorIterator(new RecursiveArrayIterator($a));
foreach($it as $v) {
echo $v, " ";
}
打印
1 2 3 4 5 6 7 8 9
其他回答
如果你想保留中间键:
function flattenArray(array &$result, $value, string $key = "")
{
if (!is_array($value)) {
$result[$key] = $value;
return $result;
}
foreach ($value as $subKey => $subArray) {
$newKey = $key !== "" ? $key . "_" . $subKey : $subKey;
flattenArray($result, $subArray, $newKey);
}
return $result;
}
$nestedArray = [
"name" => "John",
"pets" => [
["id" => 1, "name" => "snooop"],
["id" => 2, "name" => "medor"],
],
"job" => ["title" => "developper"],
];
$intermediateResult = [];
$flattened = flattenArray($intermediateResult, $nestedArray);
var_dump($flattened);
这将输出:
array(6) {
["name"]=>
string(4) "John"
["pets_0_id"]=>
int(1)
["pets_0_name"]=>
string(6) "snooop"
["pets_1_id"]=>
int(2)
["pets_1_name"]=>
string(5) "medor"
["job_title"]=>
string(10) "developper"
}
看到https://ideone.com/KXLtzZ stdout
从PHP v7.4开始,可以使用展开操作符并合并数组。简单有效。
$flatArr = array_merge(...$originalArray);
试试下面这个简单的函数:
function _flatten_array($arr) {
while ($arr) {
list($key, $value) = each($arr);
is_array($value) ? $arr = $value : $out[$key] = $value;
unset($arr[$key]);
}
return (array)$out;
}
所以从这里:
array (
'und' =>
array (
'profiles' =>
array (
0 =>
array (
'commerce_customer_address' =>
array (
'und' =>
array (
0 =>
array (
'first_name' => 'First name',
'last_name' => 'Last name',
'thoroughfare' => 'Address 1',
'premise' => 'Address 2',
'locality' => 'Town/City',
'administrative_area' => 'County',
'postal_code' => 'Postcode',
),
),
),
),
),
),
)
你会得到:
array (
'first_name' => 'First name',
'last_name' => 'Last name',
'thoroughfare' => 'Address 1',
'premise' => 'Address 2',
'locality' => 'Town/City',
'administrative_area' => 'County',
'postal_code' => 'Postcode',
)
这个解是非递归的。注意,元素的顺序会有些混合。
function flatten($array) {
$return = array();
while(count($array)) {
$value = array_shift($array);
if(is_array($value))
foreach($value as $sub)
$array[] = $sub;
else
$return[] = $value;
}
return $return;
}
诀窍是通过引用传递源数组和目标数组。
function flatten_array(&$arr, &$dst) {
if(!isset($dst) || !is_array($dst)) {
$dst = array();
}
if(!is_array($arr)) {
$dst[] = $arr;
} else {
foreach($arr as &$subject) {
flatten_array($subject, $dst);
}
}
}
$recursive = array('1', array('2','3',array('4',array('5','6')),'7',array(array(array('8'),'9'),'10')));
echo "Recursive: \r\n";
print_r($recursive);
$flat = null;
flatten_array($recursive, $flat);
echo "Flat: \r\n";
print_r($flat);
// If you change line 3 to $dst[] = &$arr; , you won't waste memory,
// since all you're doing is copying references, and imploding the array
// into a string will be both memory efficient and fast:)
echo "String:\r\n";
echo implode(',',$flat);