一个Kotlin的例子，至少在Windows上可以工作，即使我的VPN是打开的。 (当VPN打开时，其他方法似乎失败了) 它只需要查找一次计算机的IP地址。从那时起，始终可以从存储的适配器信息中找到IP地址。

import java.net.NetworkInterface
import java.util.prefs.Preferences

class WindowsIP {
    companion object {
        val prefs = Preferences.userNodeForPackage(this::class.java)  //Get the current IP address for the wifi adapter whose information
        // has been stored by calling findWifiAdapter(currentIp) with the known current IP (from wifi properties or whatever)
        fun getIpAddress(): String {
            val wlanName = prefs.get("WlanName", "")
            val wlanDisplName = prefs.get("WlanDisplName", "")
            val addrCnt = prefs.getInt("wlanAddrCount", 0)
            val nis = NetworkInterface.getNetworkInterfaces()
            for (ni in nis) {
                if (ni.name == wlanName && ni.displayName == wlanDisplName) {
                    var count = 0
                    for (addr in ni.inetAddresses) {
                        if (count++ == addrCnt) {
                            return addr.hostAddress
                        }
                    }
                }
            }
            return "Unknown. Call findWifiAdapter() with current IP address"
        }

        fun findWifiAdapter(currentIP: String) {  //Find the wifi adapter using the current IP address and store the information
                val nis = NetworkInterface.getNetworkInterfaces()
                for(ni in nis) {
                    var count = 0;
                    for(adr in ni.inetAddresses) {
                        if(adr.hostAddress == currentIP) {
                            prefs.put("WlanName", ni.name)
                            prefs.put("WlanDisplName", ni.displayName)
                            prefs.putInt("wlanAddrCount", count)  //Probably always zero?
                        }
                        ++count
                    }
                }
        }
    }
}

首先导入类

import java.net.InetAddress;

在课堂上

  InetAddress iAddress = InetAddress.getLocalHost();
  String currentIp = iAddress.getHostAddress();
  System.out.println("Current IP address : " +currentIp); //gives only host address

一个相当简单的方法似乎很有效……

String getPublicIPv4() throws UnknownHostException, SocketException{
    Enumeration<NetworkInterface> e = NetworkInterface.getNetworkInterfaces();
    String ipToReturn = null;
    while(e.hasMoreElements())
    {
        NetworkInterface n = (NetworkInterface) e.nextElement();
        Enumeration<InetAddress> ee = n.getInetAddresses();
        while (ee.hasMoreElements())
        {
            InetAddress i = (InetAddress) ee.nextElement();
            String currentAddress = i.getHostAddress();
            logger.trace("IP address "+currentAddress+ " found");
            if(!i.isSiteLocalAddress()&&!i.isLoopbackAddress() && validate(currentAddress)){
                ipToReturn = currentAddress;    
            }else{
                System.out.println("Address not validated as public IPv4");
            }

        }
    }

    return ipToReturn;
}

private static final Pattern IPv4RegexPattern = Pattern.compile(
        "^(([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\.){3}([01]?\\d\\d?|2[0-4]\\d|25[0-5])$");

public static boolean validate(final String ip) {
    return IPv4RegexPattern.matcher(ip).matches();
}

你的计算机可以有多个网络接口，每个网络接口有多个inetaddress。如果过滤掉任何本地地址，则提醒的地址是非本地地址，其中可以有一个、没有或多个。

不幸的是，Java中的网络API仍然使用(旧的)枚举而不是迭代器和流，我们可以通过将它们包装为流来进行对抗。所以我们要做的就是

所有网络接口及其地址的流，以及 过滤掉本地的

代码:

private Stream<InetAddress> getNonLocalIpAddresses() throws IOException {
    return enumerationAsStream(NetworkInterface.getNetworkInterfaces())
        .flatMap(networkInterface -> enumerationAsStream(networkInterface.getInetAddresses()))
        .filter(inetAddress -> !inetAddress.isAnyLocalAddress())
        .filter(inetAddress -> !inetAddress.isSiteLocalAddress())
        .filter(inetAddress -> !inetAddress.isLoopbackAddress())
        .filter(inetAddress -> !inetAddress.isLinkLocalAddress());
}

在我的机器上，这目前返回两个IPv6地址。

要获得这些inetaddress中的第一个:

private String getMyIp() throws IOException {
    return getNonLocalIpAddresses()
        .map(InetAddress::getHostAddress)
        .findFirst()
        .orElseThrow(NoSuchElementException::new);
}

将枚举包装为流的方法:

public static <T> Stream<T> enumerationAsStream(Enumeration<T> e) {
    return StreamSupport.stream(
        Spliterators.spliteratorUnknownSize(
            new Iterator<>() {
                public T next() { return e.nextElement();  }
                public boolean hasNext() { return e.hasMoreElements(); }
            }, Spliterator.ORDERED), false);
}

如果您的机器是网络的一部分，那么它将获取您的网络的IP地址

try {
    System.out.println(InetAddress.getLocalHost().getHostAddress());
} catch (UnknownHostException e) {
    e.printStackTrace();
}

编辑1:更新后的代码，因为之前的链接，不再存在

import java.io.*;
import java.net.*;

public class GetMyIP {
    public static void main(String[] args) {
        URL url = null;
        BufferedReader in = null;
        String ipAddress = "";
        try {
            url = new URL("http://bot.whatismyipaddress.com");
            in = new BufferedReader(new InputStreamReader(url.openStream()));
            ipAddress = in.readLine().trim();
            /* IF not connected to internet, then
             * the above code will return one empty
             * String, we can check it's length and
             * if length is not greater than zero, 
             * then we can go for LAN IP or Local IP
             * or PRIVATE IP
             */
            if (!(ipAddress.length() > 0)) {
                try {
                    InetAddress ip = InetAddress.getLocalHost();
                    System.out.println((ip.getHostAddress()).trim());
                    ipAddress = (ip.getHostAddress()).trim();
                } catch(Exception exp) {
                    ipAddress = "ERROR";
                }
            }
        } catch (Exception ex) {
            // This try will give the Private IP of the Host.
            try {
                InetAddress ip = InetAddress.getLocalHost();
                System.out.println((ip.getHostAddress()).trim());
                ipAddress = (ip.getHostAddress()).trim();
            } catch(Exception exp) {
                ipAddress = "ERROR";
            }
            //ex.printStackTrace();
        }
        System.out.println("IP Address: " + ipAddress);
    }
}

实际版本:这停止工作

希望这段代码可以帮助你实现这一点:

// Method to get the IP Address of the Host.
private String getIP()
{
    // This try will give the Public IP Address of the Host.
    try
    {
        URL url = new URL("http://automation.whatismyip.com/n09230945.asp");
        BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream()));
        String ipAddress = new String();
        ipAddress = (in.readLine()).trim();
        /* IF not connected to internet, then
         * the above code will return one empty
         * String, we can check it's length and
         * if length is not greater than zero, 
         * then we can go for LAN IP or Local IP
         * or PRIVATE IP
         */
        if (!(ipAddress.length() > 0))
        {
            try
            {
                InetAddress ip = InetAddress.getLocalHost();
                System.out.println((ip.getHostAddress()).trim());
                return ((ip.getHostAddress()).trim());
            }
            catch(Exception ex)
            {
                return "ERROR";
            }
        }
        System.out.println("IP Address is : " + ipAddress);

        return (ipAddress);
    }
    catch(Exception e)
    {
        // This try will give the Private IP of the Host.
        try
        {
            InetAddress ip = InetAddress.getLocalHost();
            System.out.println((ip.getHostAddress()).trim());
            return ((ip.getHostAddress()).trim());
        }
        catch(Exception ex)
        {
            return "ERROR";
        }
    }
}