我正在尝试开发一个系统,其中有不同的节点运行在不同的系统或在同一系统的不同端口上。
现在,所有节点都创建了一个套接字,将目标IP作为称为引导节点的特殊节点的IP。然后,节点创建自己的ServerSocket并开始侦听连接。
引导节点维护一个节点列表,并在查询时返回它们。
现在我需要的是节点必须将其IP注册到引导节点。我尝试使用cli.getInetAddress()一旦客户端连接到引导节点的ServerSocket,但这不起作用。
我需要客户端注册其PPP IP,如果可用;
否则,局域网IP(如果可用);
否则,它必须注册127.0.0.1,假设它是同一台计算机。
使用代码:
System.out.println(Inet4Address.getLocalHost().getHostAddress());
or
System.out.println(InetAddress.getLocalHost().getHostAddress());
我的PPP连接IP地址是:117.204.44.192,但上面返回我192.168.1.2
EDIT
我正在使用以下代码:
Enumeration e = NetworkInterface.getNetworkInterfaces();
while(e.hasMoreElements())
{
NetworkInterface n = (NetworkInterface) e.nextElement();
Enumeration ee = n.getInetAddresses();
while (ee.hasMoreElements())
{
InetAddress i = (InetAddress) ee.nextElement();
System.out.println(i.getHostAddress());
}
}
我能够获得所有网络接口相关的所有IP地址,但我如何区分它们?这是我得到的输出:
127.0.0.1
192.168.1.2
192.168.56.1
117.204.44.19
在这里发布来自https://issues.apache.org/jira/browse/JCS-40的测试IP歧义变通代码(InetAddress.getLocalHost()在Linux系统上是歧义的):
/**
* Returns an <code>InetAddress</code> object encapsulating what is most likely the machine's LAN IP address.
* <p/>
* This method is intended for use as a replacement of JDK method <code>InetAddress.getLocalHost</code>, because
* that method is ambiguous on Linux systems. Linux systems enumerate the loopback network interface the same
* way as regular LAN network interfaces, but the JDK <code>InetAddress.getLocalHost</code> method does not
* specify the algorithm used to select the address returned under such circumstances, and will often return the
* loopback address, which is not valid for network communication. Details
* <a href="http://bugs.sun.com/bugdatabase/view_bug.do?bug_id=4665037">here</a>.
* <p/>
* This method will scan all IP addresses on all network interfaces on the host machine to determine the IP address
* most likely to be the machine's LAN address. If the machine has multiple IP addresses, this method will prefer
* a site-local IP address (e.g. 192.168.x.x or 10.10.x.x, usually IPv4) if the machine has one (and will return the
* first site-local address if the machine has more than one), but if the machine does not hold a site-local
* address, this method will return simply the first non-loopback address found (IPv4 or IPv6).
* <p/>
* If this method cannot find a non-loopback address using this selection algorithm, it will fall back to
* calling and returning the result of JDK method <code>InetAddress.getLocalHost</code>.
* <p/>
*
* @throws UnknownHostException If the LAN address of the machine cannot be found.
*/
private static InetAddress getLocalHostLANAddress() throws UnknownHostException {
try {
InetAddress candidateAddress = null;
// Iterate all NICs (network interface cards)...
for (Enumeration ifaces = NetworkInterface.getNetworkInterfaces(); ifaces.hasMoreElements();) {
NetworkInterface iface = (NetworkInterface) ifaces.nextElement();
// Iterate all IP addresses assigned to each card...
for (Enumeration inetAddrs = iface.getInetAddresses(); inetAddrs.hasMoreElements();) {
InetAddress inetAddr = (InetAddress) inetAddrs.nextElement();
if (!inetAddr.isLoopbackAddress()) {
if (inetAddr.isSiteLocalAddress()) {
// Found non-loopback site-local address. Return it immediately...
return inetAddr;
}
else if (candidateAddress == null) {
// Found non-loopback address, but not necessarily site-local.
// Store it as a candidate to be returned if site-local address is not subsequently found...
candidateAddress = inetAddr;
// Note that we don't repeatedly assign non-loopback non-site-local addresses as candidates,
// only the first. For subsequent iterations, candidate will be non-null.
}
}
}
}
if (candidateAddress != null) {
// We did not find a site-local address, but we found some other non-loopback address.
// Server might have a non-site-local address assigned to its NIC (or it might be running
// IPv6 which deprecates the "site-local" concept).
// Return this non-loopback candidate address...
return candidateAddress;
}
// At this point, we did not find a non-loopback address.
// Fall back to returning whatever InetAddress.getLocalHost() returns...
InetAddress jdkSuppliedAddress = InetAddress.getLocalHost();
if (jdkSuppliedAddress == null) {
throw new UnknownHostException("The JDK InetAddress.getLocalHost() method unexpectedly returned null.");
}
return jdkSuppliedAddress;
}
catch (Exception e) {
UnknownHostException unknownHostException = new UnknownHostException("Failed to determine LAN address: " + e);
unknownHostException.initCause(e);
throw unknownHostException;
}
}
你的计算机可以有多个网络接口,每个网络接口有多个inetaddress。如果过滤掉任何本地地址,则提醒的地址是非本地地址,其中可以有一个、没有或多个。
不幸的是,Java中的网络API仍然使用(旧的)枚举而不是迭代器和流,我们可以通过将它们包装为流来进行对抗。所以我们要做的就是
所有网络接口及其地址的流,以及
过滤掉本地的
代码:
private Stream<InetAddress> getNonLocalIpAddresses() throws IOException {
return enumerationAsStream(NetworkInterface.getNetworkInterfaces())
.flatMap(networkInterface -> enumerationAsStream(networkInterface.getInetAddresses()))
.filter(inetAddress -> !inetAddress.isAnyLocalAddress())
.filter(inetAddress -> !inetAddress.isSiteLocalAddress())
.filter(inetAddress -> !inetAddress.isLoopbackAddress())
.filter(inetAddress -> !inetAddress.isLinkLocalAddress());
}
在我的机器上,这目前返回两个IPv6地址。
要获得这些inetaddress中的第一个:
private String getMyIp() throws IOException {
return getNonLocalIpAddresses()
.map(InetAddress::getHostAddress)
.findFirst()
.orElseThrow(NoSuchElementException::new);
}
将枚举包装为流的方法:
public static <T> Stream<T> enumerationAsStream(Enumeration<T> e) {
return StreamSupport.stream(
Spliterators.spliteratorUnknownSize(
new Iterator<>() {
public T next() { return e.nextElement(); }
public boolean hasNext() { return e.hasMoreElements(); }
}, Spliterator.ORDERED), false);
}
import java.net.DatagramSocket;
import java.net.InetAddress;
try(final DatagramSocket socket = new DatagramSocket()){
socket.connect(InetAddress.getByName("8.8.8.8"), 10002);
ip = socket.getLocalAddress().getHostAddress();
}
这种方式适用于有多个网络接口的情况。它总是返回首选出站IP。目的地8.8.8.8不需要可达。
Connect on a UDP socket has the following effect: it sets the destination for Send/Recv, discards all packets from other addresses, and - which is what we use - transfers the socket into "connected" state, settings its appropriate fields. This includes checking the existence of the route to the destination according to the system's routing table and setting the local endpoint accordingly. The last part seems to be undocumented officially but it looks like an integral trait of Berkeley sockets API (a side effect of UDP "connected" state) that works reliably in both Windows and Linux across versions and distributions.
因此,此方法将提供用于连接到指定远程主机的本地地址。没有建立真正的连接,因此指定的远端ip不可达。
编辑:
正如@macomgil所说,对于MacOS,你可以这样做:
Socket socket = new Socket();
socket.connect(new InetSocketAddress("google.com", 80));
System.out.println(socket.getLocalAddress());
一个Kotlin的例子,至少在Windows上可以工作,即使我的VPN是打开的。
(当VPN打开时,其他方法似乎失败了)
它只需要查找一次计算机的IP地址。从那时起,始终可以从存储的适配器信息中找到IP地址。
import java.net.NetworkInterface
import java.util.prefs.Preferences
class WindowsIP {
companion object {
val prefs = Preferences.userNodeForPackage(this::class.java) //Get the current IP address for the wifi adapter whose information
// has been stored by calling findWifiAdapter(currentIp) with the known current IP (from wifi properties or whatever)
fun getIpAddress(): String {
val wlanName = prefs.get("WlanName", "")
val wlanDisplName = prefs.get("WlanDisplName", "")
val addrCnt = prefs.getInt("wlanAddrCount", 0)
val nis = NetworkInterface.getNetworkInterfaces()
for (ni in nis) {
if (ni.name == wlanName && ni.displayName == wlanDisplName) {
var count = 0
for (addr in ni.inetAddresses) {
if (count++ == addrCnt) {
return addr.hostAddress
}
}
}
}
return "Unknown. Call findWifiAdapter() with current IP address"
}
fun findWifiAdapter(currentIP: String) { //Find the wifi adapter using the current IP address and store the information
val nis = NetworkInterface.getNetworkInterfaces()
for(ni in nis) {
var count = 0;
for(adr in ni.inetAddresses) {
if(adr.hostAddress == currentIP) {
prefs.put("WlanName", ni.name)
prefs.put("WlanDisplName", ni.displayName)
prefs.putInt("wlanAddrCount", count) //Probably always zero?
}
++count
}
}
}
}
}