我有一个关于新的Android 6.0 (Marshmallow)发布的问题。
是否有可能通过Intent或类似的东西来显示特定应用程序的“应用程序权限”屏幕?
使用以下代码可以在设置中显示应用程序的“应用程序信息”屏幕:
startActivity(
new Intent(
android.provider.Settings.ACTION_APPLICATION_DETAILS_SETTINGS,
Uri.fromParts("package", getPackageName(), null)
)
);
是否有类似的解决方案直接打开应用程序的“应用程序权限”屏幕?
我已经对此做了一些研究，但我无法找到解决方案。
当前回答
Xamarin form Android:
//---------------------------------------------------------
public void OpenSettings()
//---------------------------------------------------------
{
var intent = new Intent(Android.Provider.Settings.ActionApplicationDetailsSettings,
Android.Net.Uri.Parse("package:" + Forms.Context.PackageName));
Forms.Context.StartActivity(intent);
}
其他回答
Xamarin form Android:
//---------------------------------------------------------
public void OpenSettings()
//---------------------------------------------------------
{
var intent = new Intent(Android.Provider.Settings.ActionApplicationDetailsSettings,
Android.Net.Uri.Parse("package:" + Forms.Context.PackageName));
Forms.Context.StartActivity(intent);
}
根据Android文档
试试这个
Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setComponent(new ComponentName(appDetails.packageName,"com.android.packageinstaller.permission.ui.ManagePermissionsActivity"));
startActivity(intent);
打开特定应用程序的权限界面
if (ContextCompat.checkSelfPermission(
context, Manifest.permission.WRITE_EXTERNAL_STORAGE)
!= PackageManager.PERMISSION_GRANTED
) {
//Permission is not granted yet. Ask for permission.
val alertDialog = AlertDialog.Builder(context)
alertDialog.setMessage(context.getString(R.string.file_permission))
alertDialog.setPositiveButton("सेटिंग") { _, _ ->
val intent = Intent(
Settings.ACTION_APPLICATION_DETAILS_SETTINGS,
Uri.fromParts("package", BuildConfig.APPLICATION_ID, null)
)
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
context.startActivity(intent)
}
alertDialog.setNegativeButton("हाँ") { _, _ ->
ActivityCompat.requestPermissions(
context as Activity, arrayOf(
Manifest.permission.WRITE_EXTERNAL_STORAGE
), 1
)
}
alertDialog.show()
} else {}
如果你想在Kotlin中写更少的代码，你可以这样做:
fun Context.openAppSystemSettings() {
startActivity(Intent().apply {
action = Settings.ACTION_APPLICATION_DETAILS_SETTINGS
data = Uri.fromParts("package", packageName, null)
})
}
根据Martin Konecny的回答
Kotlin风格。
startActivity(Intent(Settings.ACTION_APPLICATION_DETAILS_SETTINGS).apply {
data = Uri.fromParts("package", packageName, null)
})
