如何删除JavaScript对象中未定义或空的所有属性?

(这个问题与数组的问题类似)


当前回答

除了删除属性,还可以使用非空键创建一个新对象。

const removeEmpty = (obj) => {
  return Object.keys(obj).filter(key => obj[key]).reduce(
    (newObj, key) => {
      newObj[key] = obj[key]
      return newObj
    }, {}
  )
}

其他回答

如果有人需要欧文(和埃里克)答案的递归版本,这里是:

/**
 * Delete all null (or undefined) properties from an object.
 * Set 'recurse' to true if you also want to delete properties in nested objects.
 */
function delete_null_properties(test, recurse) {
    for (var i in test) {
        if (test[i] === null) {
            delete test[i];
        } else if (recurse && typeof test[i] === 'object') {
            delete_null_properties(test[i], recurse);
        }
    }
}

你可以剪短一点!条件

var r = {a: null, b: undefined, c:1};
for(var k in r)
   if(!r[k]) delete r[k];

使用时请记住:as @分色announcement in comments:如果值为空字符串、false或0,这也会删除属性

你可以循环遍历对象:

Var检验= { test1:空, test2:“somestring”, test3: 3, } 函数clean(obj) { for (var propName in obj) { if (obj[propName] === null || obj[propName] === undefined) { 删除obj [propName]; } } 返回obj } console.log(测试); console.log(清洁(测试));

如果你担心这个属性删除不会运行到对象的proptype链,你还可以:

function clean(obj) {
  var propNames = Object.getOwnPropertyNames(obj);
  for (var i = 0; i < propNames.length; i++) {
    var propName = propNames[i];
    if (obj[propName] === null || obj[propName] === undefined) {
      delete obj[propName];
    }
  }
}

关于null和undefined的一些注意事项:

test.test1 === null; // true
test.test1 == null; // true

test.notaprop === null; // false
test.notaprop == null; // true

test.notaprop === undefined; // true
test.notaprop == undefined; // true

您可能正在寻找delete关键字。

var obj = { };
obj.theProperty = 1;
delete obj.theProperty;

删除空字段对象

for (const objectKey of Object.keys(data)) {
      if (data[objectKey] === null || data[objectKey] === '' || data[objectKey] === 'null' || data[objectKey] === undefined) {
        delete data[objectKey];
      }
    }