如何删除JavaScript对象中未定义或空的所有属性?
(这个问题与数组的问题类似)
如何删除JavaScript对象中未定义或空的所有属性?
(这个问题与数组的问题类似)
当前回答
如果您更喜欢纯/函数方法
const stripUndef = obj =>
Object.keys(obj)
.reduce((p, c) => ({ ...p, ...(x[c] === undefined ? { } : { [c]: x[c] })}), {});
其他回答
ES6 arrow function and ternary operator:
Object.entries(obj).reduce((acc, entry) => {
const [key, value] = entry
if (value !== undefined) acc[key] = value;
return acc;
}, {})
const obj = {test:undefined, test1:1 ,test12:0, test123:false};
const newObj = Object.entries(obj).reduce((acc, entry) => {
const [key, value] = entry
if (value !== undefined) acc[key] = value;
return acc;
}, {})
console.log(newObj)
您可能正在寻找delete关键字。
var obj = { };
obj.theProperty = 1;
delete obj.theProperty;
下面是一个综合递归函数(最初基于@chickens的函数),它将:
递归删除你告诉它的默认值=[undefined, null, ", NaN] 正确处理常规对象、数组和Date对象
const cleanEmpty = function(obj, defaults = [undefined, null, NaN, '']) {
if (!defaults.length) return obj
if (defaults.includes(obj)) return
if (Array.isArray(obj))
return obj
.map(v => v && typeof v === 'object' ? cleanEmpty(v, defaults) : v)
.filter(v => !defaults.includes(v))
return Object.entries(obj).length
? Object.entries(obj)
.map(([k, v]) => ([k, v && typeof v === 'object' ? cleanEmpty(v, defaults) : v]))
.reduce((a, [k, v]) => (defaults.includes(v) ? a : { ...a, [k]: v}), {})
: obj
}
用法:
// based off the recursive cleanEmpty function by @chickens. // This one can also handle Date objects correctly // and has a defaults list for values you want stripped. const cleanEmpty = function(obj, defaults = [undefined, null, NaN, '']) { if (!defaults.length) return obj if (defaults.includes(obj)) return if (Array.isArray(obj)) return obj .map(v => v && typeof v === 'object' ? cleanEmpty(v, defaults) : v) .filter(v => !defaults.includes(v)) return Object.entries(obj).length ? Object.entries(obj) .map(([k, v]) => ([k, v && typeof v === 'object' ? cleanEmpty(v, defaults) : v])) .reduce((a, [k, v]) => (defaults.includes(v) ? a : { ...a, [k]: v}), {}) : obj } // testing console.log('testing: undefined \n', cleanEmpty(undefined)) console.log('testing: null \n',cleanEmpty(null)) console.log('testing: NaN \n',cleanEmpty(NaN)) console.log('testing: empty string \n',cleanEmpty('')) console.log('testing: empty array \n',cleanEmpty([])) console.log('testing: date object \n',cleanEmpty(new Date(1589339052 * 1000))) console.log('testing: nested empty arr \n',cleanEmpty({ 1: { 2 :null, 3: [] }})) console.log('testing: comprehensive obj \n', cleanEmpty({ a: 5, b: 0, c: undefined, d: { e: null, f: [{ a: undefined, b: new Date(), c: '' }] }, g: NaN, h: null })) console.log('testing: different defaults \n', cleanEmpty({ a: 5, b: 0, c: undefined, d: { e: null, f: [{ a: undefined, b: '', c: new Date() }] }, g: [0, 1, 2, 3, 4], h: '', }, [undefined, null]))
你可以循环遍历对象:
Var检验= { test1:空, test2:“somestring”, test3: 3, } 函数clean(obj) { for (var propName in obj) { if (obj[propName] === null || obj[propName] === undefined) { 删除obj [propName]; } } 返回obj } console.log(测试); console.log(清洁(测试));
如果你担心这个属性删除不会运行到对象的proptype链,你还可以:
function clean(obj) {
var propNames = Object.getOwnPropertyNames(obj);
for (var i = 0; i < propNames.length; i++) {
var propName = propNames[i];
if (obj[propName] === null || obj[propName] === undefined) {
delete obj[propName];
}
}
}
关于null和undefined的一些注意事项:
test.test1 === null; // true
test.test1 == null; // true
test.notaprop === null; // false
test.notaprop == null; // true
test.notaprop === undefined; // true
test.notaprop == undefined; // true
使用ramda#pickBy你将删除所有null, undefined和false值:
const obj = {a:1, b: undefined, c: null, d: 1}
R.pickBy(R.identity, obj)
正如@manroe指出的,要保留假值,请使用isNil():
const obj = {a:1, b: undefined, c: null, d: 1, e: false}
R.pickBy(v => !R.isNil(v), obj)