如何删除JavaScript对象中未定义或空的所有属性?

(这个问题与数组的问题类似)


当前回答

删除空字段对象

for (const objectKey of Object.keys(data)) {
      if (data[objectKey] === null || data[objectKey] === '' || data[objectKey] === 'null' || data[objectKey] === undefined) {
        delete data[objectKey];
      }
    }

其他回答

来piggypack本的回答如何解决这个问题使用lodash的_。pickBy,你也可以在姐妹库中解决这个问题:Underscore.js的_.pick。

var obj = {name: 'John', age: null};

var compacted = _.pick(obj, function(value) {
  return value !== null && value !== undefined;
});

参见:JSFiddle示例

您可能正在寻找delete关键字。

var obj = { };
obj.theProperty = 1;
delete obj.theProperty;

Oneliner:

let obj = { a: 0, b: "string", c: undefined, d: null };

Object.keys(obj).map(k => obj[k] == undefined ? delete obj[k] : obj[k] );

控制台.log(卷);

Obj将是{a: 0, b: "string"}

这可以使用递归来解决。JavaScript对象可以是一个数组,也可以有一个包含空值的数组作为值。

function removeNullValues(obj) {
  // Check weather obj is an array
  if (Array.isArray(obj)) {
    // Creating copy of obj so that index is maintained after splice
    obj.slice(0).forEach((val) => {
      if (val === null) {
        obj.splice(obj.indexOf(val), 1);
      } else if (typeof val === 'object') {
        // Check if array has an object
        removeNullValues(val);
      }
    });
  } else if (typeof obj === 'object') {
    // Check for object
    Object.keys(obj).forEach((key) => {
      if (obj[key] === null) {
        delete obj[key];
      } else if (typeof obj[key] === 'object') {
        removeNullValues(obj[key]);
      }
    });
  }
  return obj;
}

清洁物体到位

// General cleanObj function
const cleanObj = (valsToRemoveArr, obj) => {
   Object.keys(obj).forEach( (key) =>
      if (valsToRemoveArr.includes(obj[key])){
         delete obj[key]
      }
   })
}

cleanObj([undefined, null], obj)

纯函数

const getObjWithoutVals = (dontReturnValsArr, obj) => {
    const cleanObj = {}
    Object.entries(obj).forEach( ([key, val]) => {
        if(!dontReturnValsArr.includes(val)){
            cleanObj[key]= val
        } 
    })
    return cleanObj
}

//To get a new object without `null` or `undefined` run: 
const nonEmptyObj = getObjWithoutVals([undefined, null], obj)