正如其他答案所描述的，这种模式在python中是可以接受的:

def dostuff(self):
     from foo import bar
     ...

这将避免在文件被其他模块导入时执行import语句。只有当存在逻辑循环依赖时，这才会失败。

大多数循环导入实际上不是逻辑循环导入，而是会引发ImportError错误，这是因为import()在调用时计算整个文件的顶级语句的方式。

如果你确实想要你的导入在顶部，这些ImportErrors几乎总是可以避免的:

考虑这个循环导入:

应用一个

# profiles/serializers.py

from images.serializers import SimplifiedImageSerializer

class SimplifiedProfileSerializer(serializers.Serializer):
    name = serializers.CharField()

class ProfileSerializer(SimplifiedProfileSerializer):
    recent_images = SimplifiedImageSerializer(many=True)

应用程序B

# images/serializers.py

from profiles.serializers import SimplifiedProfileSerializer

class SimplifiedImageSerializer(serializers.Serializer):
    title = serializers.CharField()

class ImageSerializer(SimplifiedImageSerializer):
    profile = SimplifiedProfileSerializer()

来自David Beazleys的精彩演讲:模块和包:生存和死亡!PyCon 2015, 1:54:00，这里是一个处理python循环导入的方法:

try:
    from images.serializers import SimplifiedImageSerializer
except ImportError:
    import sys
    SimplifiedImageSerializer = sys.modules[__package__ + '.SimplifiedImageSerializer']

它尝试导入SimplifiedImageSerializer，如果ImportError被引发，因为它已经被导入，它将从importcache中拉出它。

PS:你必须用David Beazley的声音来阅读整篇文章。

我完全同意pythoneer的回答。但是我偶然发现了一些代码，它们在循环导入时存在缺陷，并在尝试添加单元测试时引起了问题。因此，为了快速修补它而不改变一切，你可以通过动态导入来解决这个问题。

# Hack to import something without circular import issue
def load_module(name):
    """Load module using imp.find_module"""
    names = name.split(".")
    path = None
    for name in names:
        f, path, info = imp.find_module(name, path)
        path = [path]
    return imp.load_module(name, f, path[0], info)
constants = load_module("app.constants")

同样，这不是一个永久性的修复，但可以帮助那些希望在不修改太多代码的情况下修复导入错误的人。

干杯!

循环导入可能令人困惑，因为导入做了两件事:

它执行导入的模块代码 将导入的模块添加到导入模块全局符号表中

前者只执行一次，而后者则在每个import语句中执行。循环导入会在导入模块使用已导入的模块和部分执行的代码时产生这种情况。因此，它将看不到import语句后创建的对象。下面的代码示例演示了它。

循环进口并不是要不惜一切代价避免的终极祸害。在一些框架中，比如Flask，它们是很自然的，调整你的代码来消除它们并不会让代码变得更好。

main.py

print 'import b'
import b
print 'a in globals() {}'.format('a' in globals())
print 'import a'
import a
print 'a in globals() {}'.format('a' in globals())
if __name__ == '__main__':
    print 'imports done'
    print 'b has y {}, a is b.a {}'.format(hasattr(b, 'y'), a is b.a)

b.by

print "b in, __name__ = {}".format(__name__)
x = 3
print 'b imports a'
import a
y = 5
print "b out"

a.py

print 'a in, __name__ = {}'.format(__name__)
print 'a imports b'
import b
print 'b has x {}'.format(hasattr(b, 'x'))
print 'b has y {}'.format(hasattr(b, 'y'))
print "a out"

Python main.py输出带有注释

import b
b in, __name__ = b    # b code execution started
b imports a
a in, __name__ = a    # a code execution started
a imports b           # b code execution is already in progress
b has x True
b has y False         # b defines y after a import,
a out
b out
a in globals() False  # import only adds a to main global symbol table 
import a
a in globals() True
imports done
b has y True, a is b.a True # all b objects are available

假设您正在运行一个名为request.py的测试python文件 在request.py中，您写入

import request

所以这也很可能是一个循环导入。

解决方案:

只需将测试文件更改为另一个名称，例如aaa.py，而不是request.py。

不要使用其他库已经使用过的名称。

去年在comp.lang.python上对此进行了很好的讨论。它很彻底地回答了你的问题。

Imports are pretty straightforward really. Just remember the following: 'import' and 'from xxx import yyy' are executable statements. They execute when the running program reaches that line. If a module is not in sys.modules, then an import creates the new module entry in sys.modules and then executes the code in the module. It does not return control to the calling module until the execution has completed. If a module does exist in sys.modules then an import simply returns that module whether or not it has completed executing. That is the reason why cyclic imports may return modules which appear to be partly empty. Finally, the executing script runs in a module named __main__, importing the script under its own name will create a new module unrelated to __main__. Take that lot together and you shouldn't get any surprises when importing modules.

模块a.py:

import b
print("This is from module a")

模块b.py

import a
print("This is from module b")

运行“Module a”将输出:

>>> 
'This is from module a'
'This is from module b'
'This is from module a'
>>> 

它输出了这3行，而由于循环导入，它应该输出不定式。 这里列出了运行“模块a”时逐行发生的事情:

The first line is import b. so it will visit module b The first line at module b is import a. so it will visit module a The first line at module a is import b but note that this line won't be executed again anymore, because every file in python execute an import line just for once, it does not matter where or when it is executed. so it will pass to the next line and print "This is from module a". After finish visiting whole module a from module b, we are still at module b. so the next line will print "This is from module b" Module b lines are executed completely. so we will go back to module a where we started module b. import b line have been executed already and won't be executed again. the next line will print "This is from module a" and program will be finished.