人们使用什么技巧来管理交互式R会话的可用内存?我使用下面的函数[基于Petr Pikal和David Hinds在2004年发布的r-help列表]来列出(和/或排序)最大的对象，并偶尔rm()其中一些对象。但到目前为止最有效的解决办法是……在64位Linux下运行，有充足的内存。
大家还有什么想分享的妙招吗?请每人寄一份。
# improved list of objects
.ls.objects <- function (pos = 1, pattern, order.by,
decreasing=FALSE, head=FALSE, n=5) {
napply <- function(names, fn) sapply(names, function(x)
fn(get(x, pos = pos)))
names <- ls(pos = pos, pattern = pattern)
obj.class <- napply(names, function(x) as.character(class(x))[1])
obj.mode <- napply(names, mode)
obj.type <- ifelse(is.na(obj.class), obj.mode, obj.class)
obj.size <- napply(names, object.size)
obj.dim <- t(napply(names, function(x)
as.numeric(dim(x))[1:2]))
vec <- is.na(obj.dim)[, 1] & (obj.type != "function")
obj.dim[vec, 1] <- napply(names, length)[vec]
out <- data.frame(obj.type, obj.size, obj.dim)
names(out) <- c("Type", "Size", "Rows", "Columns")
if (!missing(order.by))
out <- out[order(out[[order.by]], decreasing=decreasing), ]
if (head)
out <- head(out, n)
out
}
# shorthand
lsos <- function(..., n=10) {
.ls.objects(..., order.by="Size", decreasing=TRUE, head=TRUE, n=n)
}
我喜欢Dirk的.ls.objects()脚本，但我总是眯着眼睛数大小列中的字符。所以我做了一些丑陋的hack，使它呈现出漂亮的格式大小:
.ls.objects <- function (pos = 1, pattern, order.by,
decreasing=FALSE, head=FALSE, n=5) {
napply <- function(names, fn) sapply(names, function(x)
fn(get(x, pos = pos)))
names <- ls(pos = pos, pattern = pattern)
obj.class <- napply(names, function(x) as.character(class(x))[1])
obj.mode <- napply(names, mode)
obj.type <- ifelse(is.na(obj.class), obj.mode, obj.class)
obj.size <- napply(names, object.size)
obj.prettysize <- sapply(obj.size, function(r) prettyNum(r, big.mark = ",") )
obj.dim <- t(napply(names, function(x)
as.numeric(dim(x))[1:2]))
vec <- is.na(obj.dim)[, 1] & (obj.type != "function")
obj.dim[vec, 1] <- napply(names, length)[vec]
out <- data.frame(obj.type, obj.size,obj.prettysize, obj.dim)
names(out) <- c("Type", "Size", "PrettySize", "Rows", "Columns")
if (!missing(order.by))
out <- out[order(out[[order.by]], decreasing=decreasing), ]
out <- out[c("Type", "PrettySize", "Rows", "Columns")]
names(out) <- c("Type", "Size", "Rows", "Columns")
if (head)
out <- head(out, n)
out
}
使用knitr和将脚本放在Rmd块中也可以获得一些好处。
我通常将代码划分为不同的块，并选择将检查点保存到缓存或RDS文件中
在那里，你可以设置一个块被保存到“缓存”，或者你可以决定运行或不运行一个特定的块。这样，在第一次运行时，你只能处理“第一部分”，而在另一次执行时，你只能选择“第二部分”，等等。
例子:
part1
```{r corpus, warning=FALSE, cache=TRUE, message=FALSE, eval=TRUE}
corpusTw <- corpus(twitter) # build the corpus
```
part2
```{r trigrams, warning=FALSE, cache=TRUE, message=FALSE, eval=FALSE}
dfmTw <- dfm(corpusTw, verbose=TRUE, removeTwitter=TRUE, ngrams=3)
```
作为一个副作用，这也可以让你在可重复性方面省去一些麻烦:)
基于@德克和@托尼的回答，我做了一个小小的更新。结果是在漂亮的大小值之前输出[1]，所以我取出了捕获。解决问题的输出:
.ls.objects <- function (pos = 1, pattern, order.by,
decreasing=FALSE, head=FALSE, n=5) {
napply <- function(names, fn) sapply(names, function(x)
fn(get(x, pos = pos)))
names <- ls(pos = pos, pattern = pattern)
obj.class <- napply(names, function(x) as.character(class(x))[1])
obj.mode <- napply(names, mode)
obj.type <- ifelse(is.na(obj.class), obj.mode, obj.class)
obj.prettysize <- napply(names, function(x) {
format(utils::object.size(x), units = "auto") })
obj.size <- napply(names, utils::object.size)
obj.dim <- t(napply(names, function(x)
as.numeric(dim(x))[1:2]))
vec <- is.na(obj.dim)[, 1] & (obj.type != "function")
obj.dim[vec, 1] <- napply(names, length)[vec]
out <- data.frame(obj.type, obj.size, obj.prettysize, obj.dim)
names(out) <- c("Type", "Size", "PrettySize", "Rows", "Columns")
if (!missing(order.by))
out <- out[order(out[[order.by]], decreasing=decreasing), ]
if (head)
out <- head(out, n)
return(out)
}
# shorthand
lsos <- function(..., n=10) {
.ls.objects(..., order.by="Size", decreasing=TRUE, head=TRUE, n=n)
}
lsos()
