我如何找到一个Bash脚本位于该脚本内部的目录的路径?
我想用Bash脚本作为另一个应用程序的启动器,我想将工作目录更改为Bash脚本所在的目录,所以我可以在该目录中的文件上运行,如下:
$ ./application
当前回答
使用“0”字母:
#!/usr/bin/env bash
echo "The script you are running has basename $( basename -- "$0"; ), dirname $( dirname -- "$0"; )";
echo "The present working directory is $( pwd; )";
使用 pwd 单独不会工作,如果您不从它包含的目录中运行脚本。
[matt@server1 ~]$ pwd
/home/matt
[matt@server1 ~]$ ./test2.sh
The script you are running has basename test2.sh, dirname .
The present working directory is /home/matt
[matt@server1 ~]$ cd /tmp
[matt@server1 tmp]$ ~/test2.sh
The script you are running has basename test2.sh, dirname /home/matt
The present working directory is /tmp
其他回答
使用“0”字母:
#!/usr/bin/env bash
echo "The script you are running has basename $( basename -- "$0"; ), dirname $( dirname -- "$0"; )";
echo "The present working directory is $( pwd; )";
使用 pwd 单独不会工作,如果您不从它包含的目录中运行脚本。
[matt@server1 ~]$ pwd
/home/matt
[matt@server1 ~]$ ./test2.sh
The script you are running has basename test2.sh, dirname .
The present working directory is /home/matt
[matt@server1 ~]$ cd /tmp
[matt@server1 tmp]$ ~/test2.sh
The script you are running has basename test2.sh, dirname /home/matt
The present working directory is /tmp
您可以使用 $BASH_SOURCE:
#!/usr/bin/env bash
scriptdir="$( dirname -- "$BASH_SOURCE"; )";
请注意,您需要使用 #!/bin/bash 而不是 #!/bin/sh 因为它是一个 Bash 扩展。
您可以从脚本本身中获取一个Bash脚本的源目录,随之而来:
script_path=$(dirname "$(readlink -f "$0")")"/"
echo "$script_path"
样品输出:
/home/username/desktop/
$_ 值得提到为 $0 的替代品。 如果您正在运行来自 Bash 的脚本,可将接受的答案缩短到:
DIR="$( dirname "$_" )"
请注意,这应该是您的脚本中的第一个声明。
我会用这样的东西:
# Retrieve the full pathname of the called script
scriptPath=$(which $0)
# Check whether the path is a link or not
if [ -L $scriptPath ]; then
# It is a link then retrieve the target path and get the directory name
sourceDir=$(dirname $(readlink -f $scriptPath))
else
# Otherwise just get the directory name of the script path
sourceDir=$(dirname $scriptPath)
fi
