试着使用这个查询:

SELECT name, COUNT(*) value_count FROM company_master GROUP BY name HAVING value_count > 1;

SELECT ColumnA, COUNT( * )
FROM Table
GROUP BY ColumnA
HAVING COUNT( * ) > 1

SELECT varchar_col
FROM table
GROUP BY varchar_col
HAVING COUNT(*) > 1;

我的最后一个查询在这里合并了一些有用的答案-组合group by, count和GROUP_CONCAT。

SELECT GROUP_CONCAT(id), `magento_simple`, COUNT(*) c 
FROM product_variant 
GROUP BY `magento_simple` HAVING c > 1;

这提供了两个示例的id(逗号分隔)、我需要的条形码以及重复的数量。

相应地更改表和列。

作为利维克的答案的一个变体，它可以让你找到重复结果的id，我使用了以下方法:

SELECT * FROM table1 WHERE column1 IN (SELECT column1 AS duplicate_value FROM table1 GROUP BY column1 HAVING COUNT(*) > 1)

SELECT t.*,(select count(*) from city as tt
  where tt.name=t.name) as count
  FROM `city` as t
  where (
     select count(*) from city as tt
     where tt.name=t.name
  ) > 1 order by count desc

用你的表格替换城市。 将name替换为字段名