有没有一种简单的方法可以使用PHP从数组中删除元素,从而foreach($array)不再包含该元素?

我以为将其设置为null就可以了,但显然它不起作用。


当前回答

<?php
    $stack = ["fruit1", "fruit2", "fruit3", "fruit4"];
    $fruit = array_shift($stack);
    print_r($stack);

    echo $fruit;
?>

输出:

[
    [0] => fruit2
    [1] => fruit3
    [2] => fruit4
]

fruit1

其他回答

$key = array_search($needle, $array);
if ($key !== false) {
    unset($array[$key]);
}

我只想说,我有一个具有可变属性的特定对象(它基本上映射了一个表,我正在更改表中的列,因此反映表的对象中的属性也会发生变化):

class obj {
    protected $fields = array('field1','field2');
    protected $field1 = array();
    protected $field2 = array();
    protected loadfields(){}
    // This will load the $field1 and $field2 with rows of data for the column they describe
    protected function clearFields($num){
        foreach($fields as $field) {
            unset($this->$field[$num]);
            // This did not work the line below worked
            unset($this->{$field}[$num]); // You have to resolve $field first using {}
        }
    }
}

$fields的全部目的只是,所以当代码发生更改时,我不必查看代码中的任何地方,我只需查看类的开头并更改属性列表和$fields数组内容以反映新属性。

使用以下代码:

$arr = array('orange', 'banana', 'apple', 'raspberry');
$result = array_pop($arr);
print_r($result);
  // Our initial array
  $arr = array("blue", "green", "red", "yellow", "green", "orange", "yellow", "indigo", "red");
  print_r($arr);

  // Remove the elements who's values are yellow or red
  $arr = array_diff($arr, array("yellow", "red"));
  print_r($arr);

这是上面代码的输出:

Array
(
    [0] => blue
    [1] => green
    [2] => red
    [3] => yellow
    [4] => green
    [5] => orange
    [6] => yellow
    [7] => indigo
    [8] => red
)

Array
(
    [0] => blue
    [1] => green
    [4] => green
    [5] => orange
    [7] => indigo
)

现在,array_values()将很好地重新索引数字数组,但它将从数组中删除所有键字符串,并用数字替换它们。如果需要保留键名称(字符串),或者如果所有键都是数字,则重新索引数组,请使用array_merge():

$arr = array_merge(array_diff($arr, array("yellow", "red")));
print_r($arr);

输出

Array
(
    [0] => blue
    [1] => green
    [2] => green
    [3] => orange
    [4] => indigo
)

此外,对于命名元素:

unset($array["elementName"]);