如何在Python中漂亮地打印深度为~4的字典?我尝试用pprint()进行漂亮的打印,但它不起作用:
import pprint
pp = pprint.PrettyPrinter(indent=4)
pp.pprint(mydict)
我只是想要一个缩进(“\t”)为每个嵌套,这样我就会得到这样的东西:
key1
value1
value2
key2
value1
value2
等。
我该怎么做呢?
如何在Python中漂亮地打印深度为~4的字典?我尝试用pprint()进行漂亮的打印,但它不起作用:
import pprint
pp = pprint.PrettyPrinter(indent=4)
pp.pprint(mydict)
我只是想要一个缩进(“\t”)为每个嵌套,这样我就会得到这样的东西:
key1
value1
value2
key2
value1
value2
等。
我该怎么做呢?
当前回答
我不确定你到底想要什么样的格式,但你可以从这样一个函数开始:
def pretty(d, indent=0):
for key, value in d.items():
print('\t' * indent + str(key))
if isinstance(value, dict):
pretty(value, indent+1)
else:
print('\t' * (indent+1) + str(value))
其他回答
正如其他人所发布的,你可以使用递归/dfs打印嵌套的字典数据,并递归调用如果它是一个字典;否则打印数据。
def print_json(data):
if type(data) == dict:
for k, v in data.items():
print k
print_json(v)
else:
print data
我不确定你到底想要什么样的格式,但你可以从这样一个函数开始:
def pretty(d, indent=0):
for key, value in d.items():
print('\t' * indent + str(key))
if isinstance(value, dict):
pretty(value, indent+1)
else:
print('\t' * (indent+1) + str(value))
下面是我根据sth的注释写的函数。它的工作原理与json相同。转储与缩进,但我使用制表符而不是缩进的空间。在Python 3.2+中,您可以直接将缩进指定为'\t',但在2.7中不能。
def pretty_dict(d):
def pretty(d, indent):
for i, (key, value) in enumerate(d.iteritems()):
if isinstance(value, dict):
print '{0}"{1}": {{'.format( '\t' * indent, str(key))
pretty(value, indent+1)
if i == len(d)-1:
print '{0}}}'.format( '\t' * indent)
else:
print '{0}}},'.format( '\t' * indent)
else:
if i == len(d)-1:
print '{0}"{1}": "{2}"'.format( '\t' * indent, str(key), value)
else:
print '{0}"{1}": "{2}",'.format( '\t' * indent, str(key), value)
print '{'
pretty(d,indent=1)
print '}'
Ex:
>>> dict_var = {'a':2, 'b':{'x':3, 'y':{'t1': 4, 't2':5}}}
>>> pretty_dict(dict_var)
{
"a": "2",
"b": {
"y": {
"t2": "5",
"t1": "4"
},
"x": "3"
}
}
最python化的方法之一是使用已经构建的pprint模块。
定义打印深度所需的参数与您预期的深度相同
import pprint
pp = pprint.PrettyPrinter(depth=4)
pp.pprint(mydict)
就是这样!
至于已经做了什么,我没有看到任何漂亮的打印机,至少模仿python解释器的输出非常简单的格式,所以这里是我的:
class Formatter(object):
def __init__(self):
self.types = {}
self.htchar = '\t'
self.lfchar = '\n'
self.indent = 0
self.set_formater(object, self.__class__.format_object)
self.set_formater(dict, self.__class__.format_dict)
self.set_formater(list, self.__class__.format_list)
self.set_formater(tuple, self.__class__.format_tuple)
def set_formater(self, obj, callback):
self.types[obj] = callback
def __call__(self, value, **args):
for key in args:
setattr(self, key, args[key])
formater = self.types[type(value) if type(value) in self.types else object]
return formater(self, value, self.indent)
def format_object(self, value, indent):
return repr(value)
def format_dict(self, value, indent):
items = [
self.lfchar + self.htchar * (indent + 1) + repr(key) + ': ' +
(self.types[type(value[key]) if type(value[key]) in self.types else object])(self, value[key], indent + 1)
for key in value
]
return '{%s}' % (','.join(items) + self.lfchar + self.htchar * indent)
def format_list(self, value, indent):
items = [
self.lfchar + self.htchar * (indent + 1) + (self.types[type(item) if type(item) in self.types else object])(self, item, indent + 1)
for item in value
]
return '[%s]' % (','.join(items) + self.lfchar + self.htchar * indent)
def format_tuple(self, value, indent):
items = [
self.lfchar + self.htchar * (indent + 1) + (self.types[type(item) if type(item) in self.types else object])(self, item, indent + 1)
for item in value
]
return '(%s)' % (','.join(items) + self.lfchar + self.htchar * indent)
要初始化它:
pretty = Formatter()
它可以支持为已定义的类型添加格式化器,你只需要为它创建一个函数,然后用set_formater将它绑定到你想要的类型:
from collections import OrderedDict
def format_ordereddict(self, value, indent):
items = [
self.lfchar + self.htchar * (indent + 1) +
"(" + repr(key) + ', ' + (self.types[
type(value[key]) if type(value[key]) in self.types else object
])(self, value[key], indent + 1) + ")"
for key in value
]
return 'OrderedDict([%s])' % (','.join(items) +
self.lfchar + self.htchar * indent)
pretty.set_formater(OrderedDict, format_ordereddict)
由于历史原因,我保留了之前的漂亮打印机,它是一个函数而不是一个类,但它们都可以以同样的方式使用,类版本只是允许更多:
def pretty(value, htchar='\t', lfchar='\n', indent=0):
nlch = lfchar + htchar * (indent + 1)
if type(value) is dict:
items = [
nlch + repr(key) + ': ' + pretty(value[key], htchar, lfchar, indent + 1)
for key in value
]
return '{%s}' % (','.join(items) + lfchar + htchar * indent)
elif type(value) is list:
items = [
nlch + pretty(item, htchar, lfchar, indent + 1)
for item in value
]
return '[%s]' % (','.join(items) + lfchar + htchar * indent)
elif type(value) is tuple:
items = [
nlch + pretty(item, htchar, lfchar, indent + 1)
for item in value
]
return '(%s)' % (','.join(items) + lfchar + htchar * indent)
else:
return repr(value)
使用它:
>>> a = {'list':['a','b',1,2],'dict':{'a':1,2:'b'},'tuple':('a','b',1,2),'function':pretty,'unicode':u'\xa7',("tuple","key"):"valid"}
>>> a
{'function': <function pretty at 0x7fdf555809b0>, 'tuple': ('a', 'b', 1, 2), 'list': ['a', 'b', 1, 2], 'dict': {'a': 1, 2: 'b'}, 'unicode': u'\xa7', ('tuple', 'key'): 'valid'}
>>> print(pretty(a))
{
'function': <function pretty at 0x7fdf555809b0>,
'tuple': (
'a',
'b',
1,
2
),
'list': [
'a',
'b',
1,
2
],
'dict': {
'a': 1,
2: 'b'
},
'unicode': u'\xa7',
('tuple', 'key'): 'valid'
}
相对于其他版本:
This solution looks directly for object type, so you can pretty print almost everything, not only list or dict. Doesn't have any dependancy. Everything is put inside a string, so you can do whatever you want with it. The class and the function has been tested and works with Python 2.7 and 3.4. You can have all type of objects inside, this is their representations and not theirs contents that being put in the result (so string have quotes, Unicode string are fully represented ...). With the class version, you can add formatting for every object type you want or change them for already defined ones. key can be of any valid type. Indent and Newline character can be changed for everything we'd like. Dict, List and Tuples are pretty printed.