我正在寻找一种方法来检测单击事件是否发生在组件之外,如本文所述。jQueryclosest()用于查看单击事件的目标是否将dom元素作为其父元素之一。如果存在匹配项,则单击事件属于其中一个子项,因此不被视为在组件之外。

因此,在我的组件中,我想将一个单击处理程序附加到窗口。当处理程序启动时,我需要将目标与组件的dom子级进行比较。

click事件包含类似“path”的财产,它似乎保存了事件经过的dom路径。我不知道该比较什么,或者如何最好地遍历它,我想肯定有人已经把它放在了一个聪明的效用函数中。。。不


当前回答

以上答案中没有一个对我有效,所以我最终做了如下:

从“React”导入React,{Component};

/**
 * Component that alerts if you click outside of it
 */
export default class OutsideAlerter extends Component {
  constructor(props) {
    super(props);

    this.handleClickOutside = this.handleClickOutside.bind(this);
  }

  componentDidMount() {
    document.addEventListener('mousedown', this.handleClickOutside);
  }

  componentWillUnmount() {
    document.removeEventListener('mousedown', this.handleClickOutside);
  }

  /**
   * Alert if clicked on outside of element
   */
  handleClickOutside(event) {
    if (!event.path || !event.path.filter(item => item.className=='classOfAComponent').length) {
      alert('You clicked outside of me!');
    }
  }

  render() {
    return <div>{this.props.children}</div>;
  }
}

OutsideAlerter.propTypes = {
  children: PropTypes.element.isRequired,
};

其他回答

将onClick处理程序添加到顶级容器中,并在用户单击时增加状态值。将该值传递给相关组件,每当该值发生变化时,您就可以执行操作。

在本例中,每当clickCount值更改时,我们都会调用this.closeDropdown()。

incrementClickCount方法在.app容器中激发,而不是在下拉列表中激发,因为我们使用event.stopPropagation()来防止事件冒泡。

您的代码可能最终看起来像这样:

class App extends Component {
    constructor(props) {
        super(props);
        this.state = {
            clickCount: 0
        };
    }
    incrementClickCount = () => {
        this.setState({
            clickCount: this.state.clickCount + 1
        });
    }
    render() {
        return (
            <div className="app" onClick={this.incrementClickCount}>
                <Dropdown clickCount={this.state.clickCount}/>
            </div>
        );
    }
}
class Dropdown extends Component {
    constructor(props) {
        super(props);
        this.state = {
            open: false
        };
    }
    componentDidUpdate(prevProps) {
        if (this.props.clickCount !== prevProps.clickCount) {
            this.closeDropdown();
        }
    }
    toggleDropdown = event => {
        event.stopPropagation();
        return (this.state.open) ? this.closeDropdown() : this.openDropdown();
    }
    render() {
        return (
            <div className="dropdown" onClick={this.toggleDropdown}>
                ...
            </div>
        );
    }
}

非侵入性方式无需添加另一个DIV EL。

注意:React可能会说findDomNode已弃用,但到目前为止,我还没有遇到任何问题

@异常:单击要忽略的类

@idException:单击时忽略的id

import React from "react"
import ReactDOM from "react-dom"
type Func1<T1, R> = (a1: T1) => R


export function closest(
    el: Element,
    fn: (el: Element) => boolean
  ): Element | undefined {
    let el_: Element | null = el;
  
    while (el_) {
      if (fn(el_)) {
        return el_;
      }
  
      el_ = el_.parentElement;
    }
  }
let instances: ClickOutside[] = []

type Props = {
  idException?: string,
  exceptions?: (string | Func1<MouseEvent, boolean>)[]
  handleClickOutside: Func1<MouseEvent, void>

}


export default class ClickOutside extends React.Component<Props> {
  static defaultProps = {
    exceptions: []
  };

  componentDidMount() {
    if (instances.length === 0) {
      document.addEventListener("mousedown", this.handleAll, true)
      window.parent.document.addEventListener(
        "mousedown",
        this.handleAll,
        true
      )
    }
    instances.push(this)
  }

  componentWillUnmount() {
    instances.splice(instances.indexOf(this), 1)
    if (instances.length === 0) {
      document.removeEventListener("mousedown", this.handleAll, true)
      window.parent.document.removeEventListener(
        "mousedown",
        this.handleAll,
        true
      )
    }
  }

  handleAll = (e: MouseEvent) => {

    const target: HTMLElement = e.target as HTMLElement
    if (!target) return

    instances.forEach(instance => {
      const { exceptions, handleClickOutside: onClickOutside, idException } = instance.props as Required<Props>
      let exceptionsCount = 0

      if (exceptions.length > 0) {
        const { functionExceptions, stringExceptions } = exceptions.reduce(
          (acc, exception) => {
            switch (typeof exception) {
              case "function":
                acc.functionExceptions.push(exception)
                break
              case "string":
                acc.stringExceptions.push(exception)
                break
            }

            return acc
          },
          { functionExceptions: [] as Func1<MouseEvent, boolean>[], stringExceptions: [] as string[] }
        )
        if (functionExceptions.length > 0) {
          exceptionsCount += functionExceptions.filter(
            exception => exception(e) === true
          ).length
        }

        if (exceptionsCount === 0 && stringExceptions.length > 0) {

          const el = closest(target, (e) => stringExceptions.some(ex => e.classList.contains(ex)))
          if (el) {
            exceptionsCount++
          }
        }
      }

      if (idException) {
        const target = e.target as HTMLDivElement
        if (document.getElementById(idException)!.contains(target)) {
          exceptionsCount++
        }
      }

      if (exceptionsCount === 0) {
        // eslint-disable-next-line react/no-find-dom-node
        const node = ReactDOM.findDOMNode(instance)

        if (node && !node.contains(target)) {
          onClickOutside(e)
        }
      }
    })
  };

  render() {
    return React.Children.only(this.props.children)
  }
}

用法

<ClickOutside {...{ handleClickOutside: () => { alert('Clicked Outside') } }}>
    <div >
        <div>Breathe</div>
    </div>
</ClickOutside>

我在discuss.reactjs.org上找到了一个解决方案,这要感谢Ben Alpert。单击我的树中的一个组件会导致一个重新阅读程序,在更新时删除了单击的元素。由于React的重读发生在调用文档正文处理程序之前,因此元素未被检测为“在”树中。

解决方案是在应用程序根元素上添加处理程序。

主要:

window.__myapp_container = document.getElementById('app')
React.render(<App/>, window.__myapp_container)

组件:

import { Component, PropTypes } from 'react';
import ReactDOM from 'react-dom';

export default class ClickListener extends Component {

  static propTypes = {
    children: PropTypes.node.isRequired,
    onClickOutside: PropTypes.func.isRequired
  }

  componentDidMount () {
    window.__myapp_container.addEventListener('click', this.handleDocumentClick)
  }

  componentWillUnmount () {
    window.__myapp_container.removeEventListener('click', this.handleDocumentClick)
  }

  /* using fat arrow to bind to instance */
  handleDocumentClick = (evt) => {
    const area = ReactDOM.findDOMNode(this.refs.area);

    if (!area.contains(evt.target)) {
      this.props.onClickOutside(evt)
    }
  }

  render () {
    return (
      <div ref='area'>
       {this.props.children}
      </div>
    )
  }
}
import ReactDOM from 'react-dom' ;

class SomeComponent {

  constructor(props) {
    // First, add this to your constructor
    this.handleClickOutside = this.handleClickOutside.bind(this);
  }

  componentWillMount() {
    document.addEventListener('mousedown', this.handleClickOutside, false); 
  }

  // Unbind event on unmount to prevent leaks
  componentWillUnmount() {
    window.removeEventListener('mousedown', this.handleClickOutside, false);
  }

  handleClickOutside(event) {
    if(!ReactDOM.findDOMNode(this).contains(event.path[0])){
       console.log("OUTSIDE");
    }
  }
}

我有一个需要有条件地将孩子插入模态的例子。像这样,贝娄。

const [view, setView] = useState(VIEWS.SomeView)

return (
    <Modal onClose={onClose}>
      {VIEWS.Result === view ? (
        <Result onDeny={() => setView(VIEWS.Details)} />
      ) : VIEWS.Details === view ? (
        <Details onDeny={() => setView(VIEWS.Result) /> />
      ) : null}
    </Modal>
  )

所以parent.contains(event.target)在这里不起作用,因为一旦分离了子级,parent(modal)就不再包含event.targe。

我的解决方案(到目前为止有效,没有任何问题)是这样写:

const listener = (event: MouseEvent) => {
   if (parentNodeRef && !event.path.includes(parentNodeRef)) callback()
}

若父级包含已经分离的树中的元素,那个么它不会触发回调。

编辑:event.path是新的,尚未在所有浏览器中退出。请改用composedPath。