使用下面的PHP代码，文件名在URL参数“name”中

<?php

$fileName = $_GET['name'];

if (isset($fileName)) {


    $zip = new ZipArchive;
    $res = $zip->open($fileName);
    if ($res === TRUE) {
      $zip->extractTo('./');
      $zip->close();
      echo 'Extracted file "'.$fileName.'"';
    } else {
      echo 'Cannot find the file name "'.$fileName.'" (the file name should include extension (.zip, ...))';
    }
}
else {
    echo 'Please set file name in the "name" param';
}

?>

请不要这样做(将GET var作为系统调用的一部分)。用ZipArchive代替。

所以，你的代码应该是这样的:

$zipArchive = new ZipArchive();
$result = $zipArchive->open($_GET["master"]);
if ($result === TRUE) {
    $zipArchive ->extractTo("my_dir");
    $zipArchive ->close();
    // Do something else on success
} else {
    // Do something on error
}

为了回答你的问题，你的错误是“something $var something else”应该是“something $var something else”(双引号)。

简单地尝试这个yourDestinationDir是目的地提取到或删除-d yourDestinationDir提取到根目录。

$master = 'someDir/zipFileName';
$data = system('unzip -d yourDestinationDir '.$master.'.zip');

只改变

system('unzip $master.zip');

到这个

system('unzip ' . $master . '.zip');

或者这个

系统(“{$大师}. zip解压缩”);

使用下面的PHP代码，文件名在URL参数“name”中

<?php

$fileName = $_GET['name'];

if (isset($fileName)) {


    $zip = new ZipArchive;
    $res = $zip->open($fileName);
    if ($res === TRUE) {
      $zip->extractTo('./');
      $zip->close();
      echo 'Extracted file "'.$fileName.'"';
    } else {
      echo 'Cannot find the file name "'.$fileName.'" (the file name should include extension (.zip, ...))';
    }
}
else {
    echo 'Please set file name in the "name" param';
}

?>

使用getcwd()在同一目录中进行解压缩

<?php
$unzip = new ZipArchive;
$out = $unzip->open('wordpress.zip');
if ($out === TRUE) {
  $unzip->extractTo(getcwd());
  $unzip->close();
  echo 'File unzipped';
} else {
  echo 'Error';
}
?>