您也可以使用这种语法。YYYY-MM-JJ HH-MM:

var now = DateTime.now();
var month = now.month.toString().padLeft(2, '0');
var day = now.day.toString().padLeft(2, '0');
var text = '${now.year}-$month-$day ${now.hour}:${now.minute}';

为DateTime提供一个简单的扩展方法如何?运行时可能不是很好，因为我们多次迭代字符串并遍历每个%格式选项。可能会浏览一次，贪婪地替换%。

extension DateTimeFormat on DateTime {

  /// Supports the following, inspired by: https://linux.die.net/man/3/strptime
  /// %Y: The year, including century (for example, 1991).
  /// %m: The month number (1-12).
  /// %d: The day of month (1-31).
  /// %H: The hour (0-23).
  /// %M: The minute (0-59).
  /// %S: The second (0-59).
  String format(String formatString) {
    var hourString = hour.toString();
    var dayString = day.toString();
    var monthString = month.toString();
    var minuteString = minute.toString();
    var secondString = second.toString();
    var yearString = year.toString();

    var map = {
      '%H': hourString.padLeft(3 - hourString.length, '0'), // the pad values here are the desired length + 1
      '%d': dayString.padLeft(3 - dayString.length, '0'),
      '%m': monthString.padLeft(3 - monthString.length, '0'),
      '%M': minuteString.padLeft(3 - minuteString.length, '0'),
      '%S': secondString.padLeft(3 - secondString.length, '0'),
      '%Y': yearString.padLeft(5 - yearString.length, '0'),
    };
    return map.entries.fold(formatString, (acc, entry) => acc.replaceAll(entry.key, entry.value));
  }
}

用法:

print(DateTime(2021, 10, 16, 4, 4, 4, 4, 4).format('%Y-%m-%d-%H-%M-%S'));
// '2021-10-16-04-04-04'

请随意提出修改建议。

这是我的简单解决方案。这并不需要任何依赖关系。

但是，日期将是字符串格式。如果你想要时间，那么改变子字符串的值

print(new DateTime.now()
            .toString()
            .substring(0,10)
     );   // 2020-06-10

使用这个函数

todayDate() {
    var now = new DateTime.now();
    var formatter = new DateFormat('dd-MM-yyyy');
    String formattedTime = DateFormat('kk:mm:a').format(now);
    String formattedDate = formatter.format(now);
    print(formattedTime);
    print(formattedDate);
  }

输出:

08:41:AM
21-12-2019

static String convertDateFormat(String dateTimeString, String oldFormat, String 
           newFormat) {
        DateFormat newDateFormat = DateFormat(newFormat);
        DateTime dateTime = DateFormat(oldFormat).parse(dateTimeString);
        String selectedDate = newDateFormat.format(dateTime);
        return selectedDate;
            }

这样调用这个方法

 convertDateFormat(inputDate, "dd-mm-yyyy", "d MMM yyyy");

使用字符串分割方法删除:00.000

var formatedTime = currentTime.toString().split(':')
Text(formatedTime[0])

=======或使用以下代码YYYY-MM-DD HH:MM:SS格式，不使用库====

var stringList =  DateTime.now().toIso8601String().split(new RegExp(r"[T\.]"));
var formatedDate = "${stringList[0]} ${stringList[1]}";