列出dbname所有tabename和AUTO_INCREMENT

SELECT `AUTO_INCREMENT`,`TABLE_NAME`
FROM  INFORMATION_SCHEMA.TABLES
WHERE TABLE_SCHEMA = 'dbname' ORDER BY AUTO_INCREMENT desc

我相信你正在寻找MySQL的LAST_INSERT_ID()函数。如果在命令行中，只需执行以下命令:

LAST_INSERT_ID();

你也可以通过SELECT查询得到这个值:

SELECT LAST_INSERT_ID();

查询一个给定模式下的所有表的AUTO_INCREMENT的“使用率”百分比(bigint类型unsigned列除外):

SELECT 
  c.TABLE_NAME,
  c.COLUMN_TYPE,
  c.MAX_VALUE,
  t.AUTO_INCREMENT,
  IF (c.MAX_VALUE > 0, ROUND(100 * t.AUTO_INCREMENT / c.MAX_VALUE, 2), -1) AS "Usage (%)" 
FROM 
  (SELECT 
     TABLE_SCHEMA,
     TABLE_NAME,
     COLUMN_TYPE,
     CASE 
        WHEN COLUMN_TYPE LIKE 'tinyint(1)' THEN 127
        WHEN COLUMN_TYPE LIKE 'tinyint(1) unsigned' THEN 255
        WHEN COLUMN_TYPE LIKE 'smallint(%)' THEN 32767
        WHEN COLUMN_TYPE LIKE 'smallint(%) unsigned' THEN 65535
        WHEN COLUMN_TYPE LIKE 'mediumint(%)' THEN 8388607
        WHEN COLUMN_TYPE LIKE 'mediumint(%) unsigned' THEN 16777215
        WHEN COLUMN_TYPE LIKE 'int(%)' THEN 2147483647
        WHEN COLUMN_TYPE LIKE 'int(%) unsigned' THEN 4294967295
        WHEN COLUMN_TYPE LIKE 'bigint(%)' THEN 9223372036854775807
        WHEN COLUMN_TYPE LIKE 'bigint(%) unsigned' THEN 0
        ELSE 0
     END AS "MAX_VALUE" 
   FROM 
     INFORMATION_SCHEMA.COLUMNS
     WHERE EXTRA LIKE '%auto_increment%'
   ) c

   JOIN INFORMATION_SCHEMA.TABLES t ON (t.TABLE_SCHEMA = c.TABLE_SCHEMA AND t.TABLE_NAME = c.TABLE_NAME)

WHERE
 c.TABLE_SCHEMA = 'YOUR_SCHEMA' 
ORDER BY
 `Usage (%)` DESC;

如果你只是想知道这个数字，而不是在查询中得到它，那么你可以使用:

SHOW CREATE TABLE tablename;

您应该在底部看到auto_increment

尽管如果手动运行查询，methai的答案是正确的，但当2个并发事务/连接在生产环境(例如)的运行时实际执行此查询时，就会出现问题。

刚刚在MySQL工作台中手动尝试了2个连接同时打开:

CREATE TABLE translation (
  id BIGINT PRIMARY KEY AUTO_INCREMENT
);
# Suppose we have already 20 entries, we execute 2 new inserts:

事务1:

21 = SELECT `AUTO_INCREMENT` FROM INFORMATION_SCHEMA.TABLES
     WHERE TABLE_SCHEMA = 'DatabaseName' AND TABLE_NAME = 'translation';

insert into translation (id) values (21);

事务2:

21 = SELECT `AUTO_INCREMENT` FROM INFORMATION_SCHEMA.TABLES
     WHERE TABLE_SCHEMA = 'DatabaseName' AND TABLE_NAME = 'translation';

insert into translation (id) values (21);

# commit transaction 1;
# commit transaction 2;

插入事务1是可以的 事务2插入错误:错误代码:1062。重复输入'21'键'主'。

一个好的解决方案是jvdub的答案，因为每个事务/连接的2个插入将是:

事务1:

insert into translation (id) values (null);
21 = SELECT LAST_INSERT_ID();

事务2:

insert into translation (id) values (null);
22 = SELECT LAST_INSERT_ID();

# commit transaction 1;
# commit transaction 2;

但是我们必须在插入之后执行last_insert_id() ! 并且我们可以重用该id，以便在需要外键的其他表中插入它!

同样，我们不能执行下面的2个查询:

insert into translation (id) values ((SELECT AUTO_INCREMENT FROM
    information_schema.TABLES WHERE TABLE_SCHEMA=DATABASE()
    AND TABLE_NAME='translation'));

因为我们实际上感兴趣的是在其他表中抓取/重用ID或返回!

编辑:02/08/2021，检索值

要实际检索应用程序中的值(使用MyBatis在Java中完成的示例):

@Mapper
public interface ClientMapper {
    @Select("select last_insert_id()")
    Long getLastInsertedId();

    @Insert({...})
    void insertClientInfo(ClientInfo client);
}

然后在存储库中

public void insertClientInfo(ClientInfo clientInfo) {
    mapper.insertClientInfo(clientInfo);
    Long pk = mapper.getLastInsertedId();
    clientInfo.setId(pk);
}

如果列在sql server中是自动递增的，那么要查看当前自动递增的值，如果您想编辑该列的值，请使用以下查询。

-- to get current value
select ident_current('Table_Name')

-- to update current value
dbcc checkident ('[Table_Name]',reseed,"Your Value")