我如何获得当前的AUTO_INCREMENT值为一个表在MySQL?


当前回答

列出dbname所有tabename和AUTO_INCREMENT

SELECT `AUTO_INCREMENT`,`TABLE_NAME`
FROM  INFORMATION_SCHEMA.TABLES
WHERE TABLE_SCHEMA = 'dbname' ORDER BY AUTO_INCREMENT desc

其他回答

你可以使用这个查询来获取所有的表数据:

SHOW TABLE STATUS FROM `DatabaseName` WHERE `name` LIKE 'TableName' ;

你可以通过使用这个查询来获得确切的信息:

SELECT `AUTO_INCREMENT`
FROM  INFORMATION_SCHEMA.TABLES
WHERE TABLE_SCHEMA = 'DatabaseName'
AND   TABLE_NAME   = 'TableName';

我相信你正在寻找MySQL的LAST_INSERT_ID()函数。如果在命令行中,只需执行以下命令:

LAST_INSERT_ID();

你也可以通过SELECT查询得到这个值:

SELECT LAST_INSERT_ID();

如果你只是想知道这个数字,而不是在查询中得到它,那么你可以使用:

SHOW CREATE TABLE tablename;

您应该在底部看到auto_increment

查询一个给定模式下的所有表的AUTO_INCREMENT的“使用率”百分比(bigint类型unsigned列除外):

SELECT 
  c.TABLE_NAME,
  c.COLUMN_TYPE,
  c.MAX_VALUE,
  t.AUTO_INCREMENT,
  IF (c.MAX_VALUE > 0, ROUND(100 * t.AUTO_INCREMENT / c.MAX_VALUE, 2), -1) AS "Usage (%)" 
FROM 
  (SELECT 
     TABLE_SCHEMA,
     TABLE_NAME,
     COLUMN_TYPE,
     CASE 
        WHEN COLUMN_TYPE LIKE 'tinyint(1)' THEN 127
        WHEN COLUMN_TYPE LIKE 'tinyint(1) unsigned' THEN 255
        WHEN COLUMN_TYPE LIKE 'smallint(%)' THEN 32767
        WHEN COLUMN_TYPE LIKE 'smallint(%) unsigned' THEN 65535
        WHEN COLUMN_TYPE LIKE 'mediumint(%)' THEN 8388607
        WHEN COLUMN_TYPE LIKE 'mediumint(%) unsigned' THEN 16777215
        WHEN COLUMN_TYPE LIKE 'int(%)' THEN 2147483647
        WHEN COLUMN_TYPE LIKE 'int(%) unsigned' THEN 4294967295
        WHEN COLUMN_TYPE LIKE 'bigint(%)' THEN 9223372036854775807
        WHEN COLUMN_TYPE LIKE 'bigint(%) unsigned' THEN 0
        ELSE 0
     END AS "MAX_VALUE" 
   FROM 
     INFORMATION_SCHEMA.COLUMNS
     WHERE EXTRA LIKE '%auto_increment%'
   ) c

   JOIN INFORMATION_SCHEMA.TABLES t ON (t.TABLE_SCHEMA = c.TABLE_SCHEMA AND t.TABLE_NAME = c.TABLE_NAME)

WHERE
 c.TABLE_SCHEMA = 'YOUR_SCHEMA' 
ORDER BY
 `Usage (%)` DESC;

列出dbname所有tabename和AUTO_INCREMENT

SELECT `AUTO_INCREMENT`,`TABLE_NAME`
FROM  INFORMATION_SCHEMA.TABLES
WHERE TABLE_SCHEMA = 'dbname' ORDER BY AUTO_INCREMENT desc