如果给出格式为YYYYMMDD的出生日期,如何以年计算年龄?是否可以使用Date()函数?

我正在寻找一个比我现在使用的更好的解决方案:

Var dob = '19800810'; var年=数字(dob.)substr (0, 4)); var月=数字(dob.)Substr (4, 2)) - 1; var day =数字(dob.)2) substr(6日); var today = new Date(); var age = today.getFullYear() -年份; if (today.getMonth() < month || (today.getMonth() == month && today.getDate() < day)) { 年龄——; } 警报(年龄);


当前回答

let dt = dob;

        let age = '';

        let bY = Number(moment(dt).format('YYYY')); 
        let bM = Number(moment(dt).format('MM')); 
        let bD = Number(moment(dt).format('DD')); 

        let tY = Number(moment().format('YYYY')); 
        let tM = Number(moment().format('MM')); 
        let tD = Number(moment().format('DD')); 


        age += (tY - bY) + ' Y ';

        if (tM < bM) {
            age += (tM - bM + 12) + ' M ';
            tY = tY - 1;
        } else {
            age += (tM - bM) + ' M '
        }

        if (tD < bD) {
            age += (tD - bD + 30) + ' D ';
            tM = tM - 1;
        } else {
            age += (tD - bD) + ' D '
        }
        
        //AGE MONTH DAYS
        console.log(age);

其他回答

伙计们,这对我来说再合适不过了。

getAge(birthday) {
    const millis = Date.now() - Date.parse(birthday);
    return new Date(millis).getFullYear() - 1970;
}

这是我的修改:

  function calculate_age(date) {
     var today = new Date();
     var today_month = today.getMonth() + 1; //STRANGE NUMBERING //January is 0!
     var age = today.getYear() - date.getYear();

     if ((today_month > date.getMonth() || ((today_month == date.getMonth()) && (today.getDate() < date.getDate())))) {
       age--;
     }

    return age;
  };

看这个例子,你从这里得到完整的年、月、日信息

function getAge(dateString) {
    var today = new Date();
    var birthDate = new Date(dateString);
    var age = today.getFullYear() - birthDate.getFullYear();
    var m = today.getMonth() - birthDate.getMonth();
    var da = today.getDate() - birthDate.getDate();
    if (m < 0 || (m === 0 && today.getDate() < birthDate.getDate())) {
        age--;
    }
    if(m<0){
        m +=12;
    }
    if(da<0){
        da +=30;
    }
    return age+" years "+ Math.abs(m) + "months"+ Math.abs(da) + " days";
}
alert('age: ' + getAge("1987/08/31"));    
[http://jsfiddle.net/tapos00/2g70ue5y/][1]

我在这里测试的所有答案(大约一半)都认为2000-02-29到2001-02-28是0年,而从2000-02-29到2001-03-01最有可能是1年,即1年零1天。这里有一个getYearDiff函数来修复这个问题。它只适用于d0 < d1:

function getYearDiff(d0, d1) {

    d1 = d1 || new Date();

    var m = d0.getMonth();
    var years = d1.getFullYear() - d0.getFullYear();

    d0.setFullYear(d0.getFullYear() + years);

    if (d0.getMonth() != m) d0.setDate(0);

    return d0 > d1? --years : years;
}

以下是计算年龄的简单方法:

//dob date dd/mm/yy 
var d = 01/01/1990


//today
//date today string format 
var today = new Date(); // i.e wed 04 may 2016 15:12:09 GMT
//todays year
var todayYear = today.getFullYear();
// today month
var todayMonth = today.getMonth();
//today date
var todayDate = today.getDate();

//dob
//dob parsed as date format   
var dob = new Date(d);
// dob year
var dobYear = dob.getFullYear();
// dob month
var dobMonth = dob.getMonth();
//dob date
var dobDate = dob.getDate();

var yearsDiff = todayYear - dobYear ;
var age;

if ( todayMonth < dobMonth ) 
 { 
  age = yearsDiff - 1; 
 }
else if ( todayMonth > dobMonth ) 
 {
  age = yearsDiff ; 
 }

else //if today month = dob month
 { if ( todayDate < dobDate ) 
  {
   age = yearsDiff - 1;
  }
    else 
    {
     age = yearsDiff;
    }
 }