我通过AJAX加载元素。其中一些只有当你向下滚动页面时才能看到。有什么方法可以知道元素现在是否在页面的可见部分?
当前回答
一个基于这个答案的例子,检查一个元素是否有75%可见(即小于25%的元素在屏幕之外)。
function isScrolledIntoView(el) {
// check for 75% visible
var percentVisible = 0.75;
var elemTop = el.getBoundingClientRect().top;
var elemBottom = el.getBoundingClientRect().bottom;
var elemHeight = el.getBoundingClientRect().height;
var overhang = elemHeight * (1 - percentVisible);
var isVisible = (elemTop >= -overhang) && (elemBottom <= window.innerHeight + overhang);
return isVisible;
}
其他回答
这里有一种使用Mootools实现相同目标的方法,可以是水平的、垂直的或两者都有。
Element.implement({
inVerticalView: function (full) {
if (typeOf(full) === "null") {
full = true;
}
if (this.getStyle('display') === 'none') {
return false;
}
// Window Size and Scroll
var windowScroll = window.getScroll();
var windowSize = window.getSize();
// Element Size and Scroll
var elementPosition = this.getPosition();
var elementSize = this.getSize();
// Calculation Variables
var docViewTop = windowScroll.y;
var docViewBottom = docViewTop + windowSize.y;
var elemTop = elementPosition.y;
var elemBottom = elemTop + elementSize.y;
if (full) {
return ((elemBottom >= docViewTop) && (elemTop <= docViewBottom)
&& (elemBottom <= docViewBottom) && (elemTop >= docViewTop) );
} else {
return ((elemBottom <= docViewBottom) && (elemTop >= docViewTop));
}
},
inHorizontalView: function(full) {
if (typeOf(full) === "null") {
full = true;
}
if (this.getStyle('display') === 'none') {
return false;
}
// Window Size and Scroll
var windowScroll = window.getScroll();
var windowSize = window.getSize();
// Element Size and Scroll
var elementPosition = this.getPosition();
var elementSize = this.getSize();
// Calculation Variables
var docViewLeft = windowScroll.x;
var docViewRight = docViewLeft + windowSize.x;
var elemLeft = elementPosition.x;
var elemRight = elemLeft + elementSize.x;
if (full) {
return ((elemRight >= docViewLeft) && (elemLeft <= docViewRight)
&& (elemRight <= docViewRight) && (elemLeft >= docViewLeft) );
} else {
return ((elemRight <= docViewRight) && (elemLeft >= docViewLeft));
}
},
inView: function(full) {
return this.inHorizontalView(full) && this.inVerticalView(full);
}});
jQuery Waypoints插件在这里做得非常好。
$('.entry').waypoint(function() {
alert('You have scrolled to an entry.');
});
在插件的站点上有一些例子。
用香草语回答:
function isScrolledIntoView(el) {
var rect = el.getBoundingClientRect();
var elemTop = rect.top;
var elemBottom = rect.bottom;
// Only completely visible elements return true:
var isVisible = (elemTop >= 0) && (elemBottom <= window.innerHeight);
// Partially visible elements return true:
//isVisible = elemTop < window.innerHeight && elemBottom >= 0;
return isVisible;
}
检查元素是否在屏幕上,而不是公认的检查div是否完全在屏幕上的方法(如果div比屏幕大,这将不起作用)。在纯Javascript中:
/**
* Checks if element is on the screen (Y axis only), returning true
* even if the element is only partially on screen.
*
* @param element
* @returns {boolean}
*/
function isOnScreenY(element) {
var screen_top_position = window.scrollY;
var screen_bottom_position = screen_top_position + window.innerHeight;
var element_top_position = element.offsetTop;
var element_bottom_position = element_top_position + element.offsetHeight;
return (inRange(element_top_position, screen_top_position, screen_bottom_position)
|| inRange(element_bottom_position, screen_top_position, screen_bottom_position));
}
/**
* Checks if x is in range (in-between) the
* value of a and b (in that order). Also returns true
* if equal to either value.
*
* @param x
* @param a
* @param b
* @returns {boolean}
*/
function inRange(x, a, b) {
return (x >= a && x <= b);
}
推特斯科特道丁的酷功能为我的要求- 这是用来查找元素是否刚刚滚动到屏幕上,即它的上边缘。
function isScrolledIntoView(elem)
{
var docViewTop = $(window).scrollTop();
var docViewBottom = docViewTop + $(window).height();
var elemTop = $(elem).offset().top;
return ((elemTop <= docViewBottom) && (elemTop >= docViewTop));
}