我使用curl来获取http报头以查找http状态代码并返回响应。我使用命令获取http头信息

curl -I http://localhost

为了得到响应,我使用命令

curl http://localhost

一旦使用了-I标志,我就只得到了头信息,响应就不再存在了。是否有一种方法可以同时获得http响应和头/http状态码在一个命令?


当前回答

要获得响应代码和响应:

$ curl -kv https://www.example.org

要得到响应代码:

$ curl -kv https://www.example.org 2>&1 | grep -i 'HTTP/1.1 ' | awk '{print $3}'| sed -e 's/^[ \t]*//'

2>&1:错误存储在输出中,用于解析 Grep:从输出中过滤响应代码行 Awk:从响应代码行中过滤响应代码 Sed:删除前导空白

其他回答

根据我的经验,我们通常这样使用旋度

curl -f http://localhost:1234/foo || exit 1

curl: (22) The requested URL returned error: 400 Bad Request

这样我们就可以在curl失败时使用管道,并且它还显示状态代码。

对于编程使用,我使用以下代码:

curlwithcode() {
    code=0
    # Run curl in a separate command, capturing output of -w "%{http_code}" into statuscode
    # and sending the content to a file with -o >(cat >/tmp/curl_body)
    statuscode=$(curl -w "%{http_code}" \
        -o >(cat >/tmp/curl_body) \
        "$@"
    ) || code="$?"

    body="$(cat /tmp/curl_body)"
    echo "statuscode : $statuscode"
    echo "exitcode : $code"
    echo "body : $body"
}

curlwithcode https://api.github.com/users/tj

显示如下信息:

statuscode : 200
exitcode : 0
body : {
  "login": "tj",
  "id": 25254,
  ...
}

我发现这个问题是因为我想要独立访问响应和内容,以便为用户添加一些错误处理。

Curl允许您自定义输出。您可以打印HTTP状态代码以std输出并将内容写入另一个文件。

curl -s -o response.txt -w "%{http_code}" http://example.com

这允许您检查返回代码,然后决定是否值得打印、处理、记录响应等。

http_response=$(curl -s -o response.txt -w "%{http_code}" http://example.com)
if [ $http_response != "200" ]; then
    # handle error
else
    echo "Server returned:"
    cat response.txt    
fi

%{http_code}是一个由curl代替的变量。你可以做更多的事情,或者发送代码到stderr,等等。参见curl手册和——write-out选项。

-w, --write-out Make curl display information on stdout after a completed transfer. The format is a string that may contain plain text mixed with any number of variables. The format can be specified as a literal "string", or you can have curl read the format from a file with "@filename" and to tell curl to read the format from stdin you write "@-". The variables present in the output format will be substituted by the value or text that curl thinks fit, as described below. All variables are specified as %{variable_name} and to output a normal % you just write them as %%. You can output a newline by using \n, a carriage return with \r and a tab space with \t. The output will be written to standard output, but this can be switched to standard error by using %{stderr}.

https://man7.org/linux/man-pages/man1/curl.1.html

在末尾追加一行“http_code:200”,然后grep关键字“http_code:”并提取响应代码。

result=$(curl -w "\nhttp_code:%{http_code}" http://localhost)

echo "result: ${result}"   #the curl result with "http_code:" at the end

http_code=$(echo "${result}" | grep 'http_code:' | sed 's/http_code://g') 

echo "HTTP_CODE: ${http_code}"  #the http response code

在这种情况下,您仍然可以使用非静默模式/ verbose模式来获取有关请求的更多信息,例如curl响应体。

-i选项是你想要的:

curl -i http://localhost

在输出中包含协议头(H/F)

或者你可以使用verbose选项:

curl -v http://localhost

-v,——verbose使操作更健谈