理想情况下，我想自动完成只是神奇地为我所有的别名工作。这可能吗?

是的，对于complete-alias项目(在Linux上)，这是可能的。对Mac的支持是实验性的，但用户已经报告成功。

我也遇到了这个问题，并提出了这个代码片段。这将自动为您提供所有别名的补全。在声明所有(或任何)别名后运行它。

# wrap_alias takes three arguments:
# $1: The name of the alias
# $2: The command used in the alias
# $3: The arguments in the alias all in one string
# Generate a wrapper completion function (completer) for an alias
# based on the command and the given arguments, if there is a
# completer for the command, and set the wrapper as the completer for
# the alias.
function wrap_alias() {
  [[ "$#" == 3 ]] || return 1

  local alias_name="$1"
  local aliased_command="$2"
  local alias_arguments="$3"
  local num_alias_arguments=$(echo "$alias_arguments" | wc -w)

  # The completion currently being used for the aliased command.
  local completion=$(complete -p $aliased_command 2> /dev/null)

  # Only a completer based on a function can be wrapped so look for -F
  # in the current completion. This check will also catch commands
  # with no completer for which $completion will be empty.
  echo $completion | grep -q -- -F || return 0

  local namespace=alias_completion::

  # Extract the name of the completion function from a string that
  # looks like: something -F function_name something
  # First strip the beginning of the string up to the function name by
  # removing "* -F " from the front.
  local completion_function=${completion##* -F }
  # Then strip " *" from the end, leaving only the function name.
  completion_function=${completion_function%% *}

  # Try to prevent an infinite loop by not wrapping a function
  # generated by this function. This can happen when the user runs
  # this twice for an alias like ls='ls --color=auto' or alias l='ls'
  # and alias ls='l foo'
  [[ "${completion_function#$namespace}" != $completion_function ]] && return 0

  local wrapper_name="${namespace}${alias_name}"

  eval "
function ${wrapper_name}() {
  let COMP_CWORD+=$num_alias_arguments
  args=( \"${alias_arguments}\" )
  COMP_WORDS=( $aliased_command \${args[@]} \${COMP_WORDS[@]:1} )
  $completion_function
  }
"

  # To create the new completion we use the old one with two
  # replacements:
  # 1) Replace the function with the wrapper.
  local new_completion=${completion/-F * /-F $wrapper_name }
  # 2) Replace the command being completed with the alias.
  new_completion="${new_completion% *} $alias_name"

  eval "$new_completion"
}

# For each defined alias, extract the necessary elements and use them
# to call wrap_alias.
eval "$(alias -p | sed -e 's/alias \([^=][^=]*\)='\''\([^ ][^ ]*\) *\(.*\)'\''/wrap_alias \1 \2 '\''\3'\'' /')"

unset wrap_alias

我有一个别名g='git'，结合我的git别名，我键入如下内容

$ g co <branchname>

对于我的特定用例，更简单的解决方法是在git-completion中添加一行代码。

就在这条线下面:

__git_complete git _git

我添加了这一行来处理我的单个'g'别名:

__git_complete g _git

您只需要找到完整的命令并复制具有别名的行即可。

我有别名d-m=“码头机”。d-m是docker-machine的别名。

所以在Mac上(通过brew)，补全文件在cd ' brew——prefix ' /etc/bash_completion.d/。 对于我的案例，我编辑了名为docker-machine的文件。 在最下面是:

complete -F _docker_machine docker-machine

所以我添加了另一行，用我的别名:

complete -F _docker_machine docker-machine
complete -F _docker_machine d-m

您还可以尝试使用Git别名。例如，在我的~/。gitconfig文件，我有一个看起来像这样的部分:

[alias]
        co = checkout

所以你可以输入git com <TAB>，这应该扩展到git co master，这是git checkout命令。

我知道这个问题是关于bash的，但如果你使用zsh，这个改变@hesky-fisher回答将修复它。

From

# For each defined alias, extract the necessary elements and use them
# to call wrap_alias.
eval "$(alias -p | sed -e 's/alias \([^=][^=]*\)='\''\([^ ][^ ]*\) *\(.*\)'\''/wrap_alias \1 \2 '\''\3'\'' /')"

to:

# For each defined alias, extract the necessary elements and use them
# to call wrap_alias.
eval "$(alias | sd '^([^=]+)=(.+)' 'wrap_alias $1=$2')"

你需要sd(这可以用sed代替，但sd在我看来更好)

这样做是因为zsh没有别名-p，并且zsh中的别名输出不输出

alias <something>=<value>

就像在狂欢，但是

<something>=<value>

顺便说一下，我把初始化代码放在。zlogin文件中