我认为你想知道变量名和它的值。您可以使用关联数组来实现这一点。

为数组键使用变量名:

$vars = array('FooBar' => 'a string');

当你想获取变量名时，使用array_keys($vars)，它将返回一个数组，这些变量名是你的$vars数组中使用的键。

使用此方法将用户变量从全局变量分离到当前的检查变量。

function get_user_var_defined () 
{
    return array_slice($GLOBALS,8,count($GLOBALS)-8);     
}

function get_var_name ($var) 
{
    $vuser = get_user_var_defined(); 
    foreach($vuser as $key=>$value) 
    {
        if($var===$value) return $key ; 
    }
}

我就是这么做的

function getVar(&$var) {
    $tmp = $var; // store the variable value
    $var = '_$_%&33xc$%^*7_r4'; // give the variable a new unique value
    $name = array_search($var, $GLOBALS); // search $GLOBALS for that unique value and return the key(variable)
    $var = $tmp; // restore the variable old value
    return $name;
}

使用

$city  = "San Francisco";
echo getVar($city); // city

注意:一些PHP 7版本将不能正常工作，因为array_search与$GLOBALS的错误，但所有其他版本都可以正常工作。

请看这个https://3v4l.org/UMW7V

您可能会考虑改变您的方法，并使用一个变量变量名?

$var_name = "FooBar";
$$var_name = "a string";

然后你就可以

print($var_name);

得到

FooBar

这里是PHP变量手册的链接

我知道这个问题很老了，而且已经有人回答了，但我其实是在找这个。我把这个答案贴出来是为了给大家节省一点时间来完善一些答案。

选项1:

$data = array('$FooBar');  

$vars = [];  
$vars = preg_replace('/^\\$/', '', $data); 

$varname = key(compact($vars));  
echo $varname;

打印:

FooBar

不管出于什么原因，你会发现自己处于这样的情况下，它确实有效。

． 选项2:

$FooBar = "a string";  

$varname = trim(array_search($FooBar, $GLOBALS), " \t.");  
echo $varname;

如果$FooBar拥有一个唯一的值，它将打印'FooBar'。如果$FooBar为空或空，它将打印找到的第一个空字符串或空字符串的名称。

它可以这样使用:

if (isset($FooBar) && !is_null($FooBar) && !empty($FooBar)) {
    $FooBar = "a string";
    $varname = trim(array_search($FooBar, $GLOBALS), " \t.");
}

似乎没有人提到这是a)困难和b)不明智的根本原因:

A "variable" is just a symbol pointing at something else. In PHP, it internally points to something called a "zval", which can actually be used for multiple variables simultaneously, either because they have the same value (PHP implements something called "copy-on-write" so that $foo = $bar doesn't need to allocate extra memory straight away) or because they have been assigned (or passed to a function) by reference (e.g. $foo =& $bar). So a zval has no name. When you pass a parameter to a function you are creating a new variable (even if it's a reference). You could pass something anonymous, like "hello", but once inside your function, it's whatever variable you name it as. This is fairly fundamental to code separation: if a function relied on what a variable used to be called, it would be more like a goto than a properly separate function. Global variables are generally considered a bad idea. A lot of the examples here assume that the variable you want to "reflect" can be found in $GLOBALS, but this will only be true if you've structured your code badly and variables aren't scoped to some function or object. Variable names are there to help programmers read their code. Renaming variables to better suit their purpose is a very common refactoring practice, and the whole point is that it doesn't make any difference.

现在，我理解这种调试的愿望(尽管一些建议的用法远远超出了这一点)，但作为一种通用的解决方案，它实际上并没有你想象的那么有用:如果你的调试函数说你的变量是“$file”，那仍然可能是你代码中数十个“$file”变量中的任何一个，或者一个你称为“$filename”的变量，但传递给一个参数为“$file”的函数。

更有用的信息是在代码中调用调试函数的位置。因为你可以在你的编辑器中快速找到它，你可以看到你为自己输出的变量，甚至可以一次性将整个表达式传递给它(例如debug('$foo + $bar = ')。($foo + $bar))。

为此，你可以在调试函数的顶部使用这段代码:

$backtrace = debug_backtrace();
echo '# Debug function called from ' . $backtrace[0]['file'] . ' at line ' . $backtrace[0]['line'];