我正在寻找一个简单的公共方法或操作符,允许我重复一些字符串n次。我知道我可以使用for循环来写这个,但我希望在必要时避免for循环,并且应该在某个地方存在一个简单的直接方法。

String str = "abc";
String repeated = str.repeat(3);

repeated.equals("abcabcabc");

相关:

重复字符串javascript 通过重复给定次数的另一个字符串创建NSString

编辑

当它们不是完全必要的时候,我尽量避免使用for循环,因为:

They add to the number of lines of code even if they are tucked away in another function. Someone reading my code has to figure out what I am doing in that for loop. Even if it is commented and has meaningful variables names, they still have to make sure it is not doing anything "clever". Programmers love to put clever things in for loops, even if I write it to "only do what it is intended to do", that does not preclude someone coming along and adding some additional clever "fix". They are very often easy to get wrong. For loops involving indexes tend to generate off by one bugs. For loops often reuse the same variables, increasing the chance of really hard to find scoping bugs. For loops increase the number of places a bug hunter has to look.


当前回答

public static String rep(int a,String k)

       {
           if(a<=0)
                return "";
           else 
           {a--;
               return k+rep(a,k);
       }

你可以使用这种递归方法实现你想要的目标。

其他回答

如果担心性能问题,只需在循环中使用StringBuilder,并在循环退出时执行. tostring()。见鬼,编写自己的Util类并重用它。最多5行代码。

Commons only StringUtils.repeat()

用法:

String str = "abc";
String repeated = StringUtils.repeat(str, 3);

repeated.equals("abcabcabc");
repeated = str + str + str;

有时候简单是最好的。每个阅读代码的人都可以看到发生了什么。

编译器会在幕后用StringBuilder为你做一些奇特的事情。

public static String rep(int a,String k)

       {
           if(a<=0)
                return "";
           else 
           {a--;
               return k+rep(a,k);
       }

你可以使用这种递归方法实现你想要的目标。

如果你只知道输出字符串的长度(它可能不能被输入字符串的长度整除),那么使用这个方法:

static String repeat(String s, int length) {
    return s.length() >= length ? s.substring(0, length) : repeat(s + s, length);
}

使用演示:

for (int i = 0; i < 50; i++)
    System.out.println(repeat("_/‾\\", i));

不要使用空s,长度为> 0,因为在这种情况下不可能得到想要的结果。