有没有办法在Python中返回当前目录中所有子目录的列表?

我知道您可以对文件执行此操作,但我需要获得目录列表。


当前回答

import os

d = '.'
[os.path.join(d, o) for o in os.listdir(d) 
                    if os.path.isdir(os.path.join(d,o))]

其他回答

下面这个类将能够获得一个给定目录中的文件,文件夹和所有子文件夹的列表

import os
import json

class GetDirectoryList():
    def __init__(self, path):
        self.main_path = path
        self.absolute_path = []
        self.relative_path = []


    def get_files_and_folders(self, resp, path):
        all = os.listdir(path)
        resp["files"] = []
        for file_folder in all:
            if file_folder != "." and file_folder != "..":
                if os.path.isdir(path + "/" + file_folder):
                    resp[file_folder] = {}
                    self.get_files_and_folders(resp=resp[file_folder], path= path + "/" + file_folder)
                else:
                    resp["files"].append(file_folder)
                    self.absolute_path.append(path.replace(self.main_path + "/", "") + "/" + file_folder)
                    self.relative_path.append(path + "/" + file_folder)
        return resp, self.relative_path, self.absolute_path

    @property
    def get_all_files_folder(self):
        self.resp = {self.main_path: {}}
        all = self.get_files_and_folders(self.resp[self.main_path], self.main_path)
        return all

if __name__ == '__main__':
    mylib = GetDirectoryList(path="sample_folder")
    file_list = mylib.get_all_files_folder
    print (json.dumps(file_list))

而样本目录看起来像

sample_folder/
    lib_a/
        lib_c/
            lib_e/
                __init__.py
                a.txt
            __init__.py
            b.txt
            c.txt
        lib_d/
            __init__.py
        __init__.py
        d.txt
    lib_b/
        __init__.py
        e.txt
    __init__.py

结果

[
  {
    "files": [
      "__init__.py"
    ],
    "lib_b": {
      "files": [
        "__init__.py",
        "e.txt"
      ]
    },
    "lib_a": {
      "files": [
        "__init__.py",
        "d.txt"
      ],
      "lib_c": {
        "files": [
          "__init__.py",
          "c.txt",
          "b.txt"
        ],
        "lib_e": {
          "files": [
            "__init__.py",
            "a.txt"
          ]
        }
      },
      "lib_d": {
        "files": [
          "__init__.py"
        ]
      }
    }
  },
  [
    "sample_folder/lib_b/__init__.py",
    "sample_folder/lib_b/e.txt",
    "sample_folder/__init__.py",
    "sample_folder/lib_a/lib_c/lib_e/__init__.py",
    "sample_folder/lib_a/lib_c/lib_e/a.txt",
    "sample_folder/lib_a/lib_c/__init__.py",
    "sample_folder/lib_a/lib_c/c.txt",
    "sample_folder/lib_a/lib_c/b.txt",
    "sample_folder/lib_a/lib_d/__init__.py",
    "sample_folder/lib_a/__init__.py",
    "sample_folder/lib_a/d.txt"
  ],
  [
    "lib_b/__init__.py",
    "lib_b/e.txt",
    "sample_folder/__init__.py",
    "lib_a/lib_c/lib_e/__init__.py",
    "lib_a/lib_c/lib_e/a.txt",
    "lib_a/lib_c/__init__.py",
    "lib_a/lib_c/c.txt",
    "lib_a/lib_c/b.txt",
    "lib_a/lib_d/__init__.py",
    "lib_a/__init__.py",
    "lib_a/d.txt"
  ]
]

使用python-os-walk实现。(http://www.pythonforbeginners.com/code-snippets-source-code/python-os-walk/)

import os

print("root prints out directories only from what you specified")
print("dirs prints out sub-directories from root")
print("files prints out all files from root and directories")
print("*" * 20)

for root, dirs, files in os.walk("/var/log"):
    print(root)
    print(dirs)
    print(files)

由于我在使用Python 3.4和Windows UNC路径时偶然发现了这个问题,下面是这个环境的一个变体:

from pathlib import WindowsPath

def SubDirPath (d):
    return [f for f in d.iterdir() if f.is_dir()]

subdirs = SubDirPath(WindowsPath(r'\\file01.acme.local\home$'))
print(subdirs)

Pathlib是Python 3.4中的新功能,它使得在不同操作系统下使用路径更加容易: https://docs.python.org/3.4/library/pathlib.html

有很多很好的答案,但如果你来这里寻找一个简单的方法来获得所有文件或文件夹的列表。你可以利用linux和mac上提供的find操作系统,它比os.walk快得多

import os
all_files_list = os.popen("find path/to/my_base_folder -type f").read().splitlines()
all_sub_directories_list = os.popen("find path/to/my_base_folder -type d").read().splitlines()

OR

import os

def get_files(path):
    all_files_list = os.popen(f"find {path} -type f").read().splitlines()
    return all_files_list

def get_sub_folders(path):
    all_sub_directories_list = os.popen(f"find {path} -type d").read().splitlines()
    return all_sub_directories_list

我们可以使用os.walk()来获取所有文件夹的列表

import os

path = os.getcwd()

pathObject = os.walk(path)

这个pathObject是一个对象,我们可以通过

arr = [x for x in pathObject]

arr is of type [('current directory', [array of folder in current directory], [files in current directory]),('subdirectory', [array of folder in subdirectory], [files in subdirectory]) ....]

我们可以通过遍历arr并打印中间的数组来获得所有子目录的列表

for i in arr:
   for j in i[1]:
      print(j)

这将打印所有子目录。

获取所有文件:

for i in arr:
   for j in i[2]:
      print(i[0] + "/" + j)