下面是基于@Blair Conrad的例子的几个简单函数

import os

def get_subdirs(dir):
    "Get a list of immediate subdirectories"
    return next(os.walk(dir))[1]

def get_subfiles(dir):
    "Get a list of immediate subfiles"
    return next(os.walk(dir))[2]

你可以用glob。glob

from glob import glob
glob("/path/to/directory/*/", recursive = True)

不要忘记*后面的/。

最简单的方法:

from pathlib import Path
from glob import glob

current_dir = Path.cwd()
all_sub_dir_paths = glob(str(current_dir) + '/*/') # returns list of sub directory paths

all_sub_dir_names = [Path(sub_dir).name for sub_dir in all_sub_dir_paths] 

这是简单的递归解

import os
def fn(dir=r"C:\Users\aryan\Downloads\opendatakit"):  # 1.Get file names from directory
    file_list = os.listdir(dir)
    res = []
    # print(file_list)
    for file in file_list:
        if os.path.isfile(os.path.join(dir, file)):
                res.append(file)
        else:
            result = fn(os.path.join(dir, file))
            if result:
                res.extend(fn(os.path.join(dir, file)))
    return res


res = fn()
print(res)
print(len(res))

这个函数，对于给定的父目录，递归地遍历它的所有目录，并打印它在其中找到的所有文件名。也有用。

import os

def printDirectoryFiles(directory):
   for filename in os.listdir(directory):  
        full_path=os.path.join(directory, filename)
        if not os.path.isdir(full_path): 
            print( full_path + "\n")


def checkFolders(directory):

    dir_list = next(os.walk(directory))[1]

    #print(dir_list)

    for dir in dir_list:           
        print(dir)
        checkFolders(directory +"/"+ dir) 

    printDirectoryFiles(directory)       

main_dir="C:/Users/S0082448/Desktop/carpeta1"

checkFolders(main_dir)


input("Press enter to exit ;")

这应该可以工作，因为它还创建了一个目录树;

import os
import pathlib

def tree(directory):
    print(f'+ {directory}')
    print("There are " + str(len(os.listdir(os.getcwd()))) + \
    " folders in this directory;")
    for path in sorted(directory.glob('*')):
        depth = len(path.relative_to(directory).parts)
        spacer = '    ' * depth
        print(f'{spacer}+ {path.name}')

这应该列出使用pathlib库的文件夹中的所有目录。path.relative_to(目录)。Parts获取相对于当前工作目录的元素。