我想暂停shell脚本中的输入,并提示用户进行选择。标准的是、否或取消类型问题。如何在典型的bash提示符中完成此操作?


当前回答

您可以使用内置的read命令;使用-p选项向用户提示问题。

从BASH4开始,您现在可以使用-i建议答案:

read -e -p "Enter the path to the file: " -i "/usr/local/etc/" FILEPATH
echo $FILEPATH

(但请记住使用“readline”选项-e以允许使用箭头键进行行编辑)

如果你想要一个“是/否”的逻辑,你可以这样做:

read -e -p "
List the content of your home dir ? [Y/n] " YN

[[ $YN == "y" || $YN == "Y" || $YN == "" ]] && ls -la ~/

其他回答

echo "Please enter some input: "
read input_variable
echo "You entered: $input_variable"
inquire ()  {
  echo  -n "$1 [y/n]? "
  read answer
  finish="-1"
  while [ "$finish" = '-1' ]
  do
    finish="1"
    if [ "$answer" = '' ];
    then
      answer=""
    else
      case $answer in
        y | Y | yes | YES ) answer="y";;
        n | N | no | NO ) answer="n";;
        *) finish="-1";
           echo -n 'Invalid response -- please reenter:';
           read answer;;
       esac
    fi
  done
}

... other stuff

inquire "Install now?"

...

这个问题有很多很好的答案,但从我看来,没有一个是我的理想,那就是:

简单一点,只需要几行外壳使用单个y/n键(无需按enter键)如果只按回车键,则默认为yes也可以使用大写的Y/N

这是我的版本,它具有这些财产:

read -n1 -p "Continue? (Y/n) " confirm

if ! echo $confirm | grep '^[Yy]\?$'; then
  exit 1
fi

如果要在两个分支上运行代码,可以修改该条件,使其仅在“yes”上运行(只需删除if语句中的!)或添加else。

这是我整理的东西:

#!/bin/sh

promptyn () {
    while true; do
        read -p "$1 " yn
        case $yn in
            [Yy]* ) return 0;;
            [Nn]* ) return 1;;
            * ) echo "Please answer yes or no.";;
        esac
    done
}

if promptyn "is the sky blue?"; then
    echo "yes"
else
    echo "no"
fi

我是一个初学者,所以要谨慎对待,但它似乎奏效了。

仅单个按键

这里有一个更长但可重复使用的模块化方法:

返回0=yes和1=no无需按enter键-仅需一个字符可以按enter键接受默认选择可以禁用默认选项以强制选择适用于zsh和bash。

按enter键时默认为“否”

请注意,N是大写的。此处按enter键,接受默认值:

$ confirm "Show dangerous command" && echo "rm *"
Show dangerous command [y/N]?

还要注意,[y/N]?已自动追加。默认的“no”被接受,因此不会有任何回音。

重新提示,直到给出有效响应:

$ confirm "Show dangerous command" && echo "rm *"
Show dangerous command [y/N]? X
Show dangerous command [y/N]? y
rm *

按回车键时默认为“是”

请注意,Y是大写的:

$ confirm_yes "Show dangerous command" && echo "rm *"
Show dangerous command [Y/n]?
rm *

上面,我刚刚按了回车键,所以命令运行了。

输入时无默认值-需要y或n

$ get_yes_keypress "Here you cannot press enter. Do you like this [y/n]? "
Here you cannot press enter. Do you like this [y/n]? k
Here you cannot press enter. Do you like this [y/n]?
Here you cannot press enter. Do you like this [y/n]? n
$ echo $?
1

这里,返回了1或false。请注意,使用此较低级别的函数,您需要提供自己的[y/n]?促使

Code

# Read a single char from /dev/tty, prompting with "$*"
# Note: pressing enter will return a null string. Perhaps a version terminated with X and then remove it in caller?
# See https://unix.stackexchange.com/a/367880/143394 for dealing with multi-byte, etc.
function get_keypress {
  local REPLY IFS=
  >/dev/tty printf '%s' "$*"
  [[ $ZSH_VERSION ]] && read -rk1  # Use -u0 to read from STDIN
  # See https://unix.stackexchange.com/q/383197/143394 regarding '\n' -> ''
  [[ $BASH_VERSION ]] && </dev/tty read -rn1
  printf '%s' "$REPLY"
}

# Get a y/n from the user, return yes=0, no=1 enter=$2
# Prompt using $1.
# If set, return $2 on pressing enter, useful for cancel or defualting
function get_yes_keypress {
  local prompt="${1:-Are you sure [y/n]? }"
  local enter_return=$2
  local REPLY
  # [[ ! $prompt ]] && prompt="[y/n]? "
  while REPLY=$(get_keypress "$prompt"); do
    [[ $REPLY ]] && printf '\n' # $REPLY blank if user presses enter
    case "$REPLY" in
      Y|y)  return 0;;
      N|n)  return 1;;
      '')   [[ $enter_return ]] && return "$enter_return"
    esac
  done
}

# Credit: http://unix.stackexchange.com/a/14444/143394
# Prompt to confirm, defaulting to NO on <enter>
# Usage: confirm "Dangerous. Are you sure?" && rm *
function confirm {
  local prompt="${*:-Are you sure} [y/N]? "
  get_yes_keypress "$prompt" 1
}    

# Prompt to confirm, defaulting to YES on <enter>
function confirm_yes {
  local prompt="${*:-Are you sure} [Y/n]? "
  get_yes_keypress "$prompt" 0
}