我想暂停shell脚本中的输入,并提示用户进行选择。标准的是、否或取消类型问题。如何在典型的bash提示符中完成此操作?
当前回答
在这种情况下,我已经多次使用case语句,使用case语句是一种很好的方法。可以实现while循环,该循环模拟case块,利用布尔条件,以便更好地控制程序,并满足许多其他要求。在满足所有条件后,可以使用中断,将控制权传递回程序的主要部分。此外,为了满足其他条件,当然可以在控制结构中添加条件语句:case语句和可能的while循环。
使用案例陈述来满足您的请求的示例
#! /bin/sh
# For potential users of BSD, or other systems who do not
# have a bash binary located in /bin the script will be directed to
# a bourne-shell, e.g. /bin/sh
# NOTE: It would seem best for handling user entry errors or
# exceptions, to put the decision required by the input
# of the prompt in a case statement (case control structure),
echo Would you like us to perform the option: "(Y|N)"
read inPut
case $inPut in
# echoing a command encapsulated by
# backticks (``) executes the command
"Y") echo `Do something crazy`
;;
# depending on the scenario, execute the other option
# or leave as default
"N") echo `execute another option`
;;
esac
exit
其他回答
这是我在脚本/函数中通常需要的:
如果按ENTER键,默认答案为“是”也接受z(如果你在QWERTZ布局上搞混了)接受其他语言(“ja”、“Oui”、…)如果您在函数内部,请处理正确的出口
while true; do
read -p "Continue [Y/n]? " -n 1 -r -e yn
case "${yn:-Y}" in
[YyZzOoJj]* ) echo; break ;;
[Nn]* ) [[ "$0" = "$BASH_SOURCE" ]] && exit 1 || return 1 ;; # handle exits from shell or function but don't exit interactive shell
* ) echo "Please answer yes or no.";;
esac
done
echo "and off we go!"
用最少的行数实现这一点的最简单方法如下:
read -p "<Your Friendly Message here> : y/n/cancel" CONDITION;
if [ "$CONDITION" == "y" ]; then
# do something here!
fi
if只是一个例子:如何处理这个变量取决于您。
针对其他人:
您不需要在BASH4中指定大小写,只需使用',,'使var小写即可。此外,我强烈不喜欢将代码放在读取块内,获取结果并在读取块IMO外处理它。还包括一个“q”表示退出IMO。最后,为什么键入“yes”只需使用-n1并按y。
示例:用户可以按y/n和q退出。
ans=''
while true; do
read -p "So is MikeQ the greatest or what (y/n/q) ?" -n1 ans
case ${ans,,} in
y|n|q) break;;
*) echo "Answer y for yes / n for no or q for quit.";;
esac
done
echo -e "\nAnswer = $ans"
if [[ "${ans,,}" == "q" ]] ; then
echo "OK Quitting, we will assume that he is"
exit 0
fi
if [[ "${ans,,}" == "y" ]] ; then
echo "MikeQ is the greatest!!"
else
echo "No? MikeQ is not the greatest?"
fi
我注意到,对于这样简单的用户输入,没有人发布显示多行回声菜单的答案,所以我的做法如下:
#!/bin/bash
function ask_user() {
echo -e "
#~~~~~~~~~~~~#
| 1.) Yes |
| 2.) No |
| 3.) Quit |
#~~~~~~~~~~~~#\n"
read -e -p "Select 1: " choice
if [ "$choice" == "1" ]; then
do_something
elif [ "$choice" == "2" ]; then
do_something_else
elif [ "$choice" == "3" ]; then
clear && exit 0
else
echo "Please select 1, 2, or 3." && sleep 3
clear && ask_user
fi
}
ask_user
发布这种方法是希望有人发现它有用且省时。
echo "Please enter some input: "
read input_variable
echo "You entered: $input_variable"