多维数组转换为对象。此代码用于转换必应搜索API的尝试和捕获方法。

try {
        // Perform the Web request and get the JSON response
        $context = stream_context_create($options);
        $results = file_get_contents($url . "?cc=" . $country . "&category=" . $type, false, $context);
        $results = json_decode($results);
        return response()->json($results);
    } catch (\Exception $e) {
        $results = array('value' => array(
                (object) array(
                    "name" => "Unable to Retrive News",
                    "url" => "http://www.sample.com/",
                    "image" => (object) array("thumbnail" => (object) array("contentUrl" => "")),
                    "publishedAt" => "",
                    "description" => "")
            )
        );
        $results = (object) $results;
        return response()->json($results);
    }

一个衬套

$object= json_decode(json_encode($result_array, JSON_FORCE_OBJECT));

你也可以使用ArrayObject，例如:

<?php
    $arr = array("test",
                 array("one"=>1,"two"=>2,"three"=>3), 
                 array("one"=>1,"two"=>2,"three"=>3)
           );
    $o = new ArrayObject($arr);
    echo $o->offsetGet(2)["two"],"\n";
    foreach ($o as $key=>$val){
        if (is_array($val)) {
            foreach($val as $k => $v) {
               echo $k . ' => ' . $v,"\n";
            }
        }
        else
        {
               echo $val,"\n";
        }
    }
?>

//Output:
  2
  test
  one => 1
  two => 2
  three => 3
  one => 1
  two => 2
  three => 3

你可以使用反射:

<?php

$array = ['name'=>'maria','age'=>33];

class Person {

    public $name;
    public $age;

    public function __construct(string $name, string $age){
        $this->name  = $name;
        $this->age = $age;
    }
}

function arrayToObject(array $array, string $class_name){

    $r = new ReflectionClass($class_name);
    $object = $r->newInstanceWithoutConstructor();
    $list = $r->getProperties();
    foreach($list as $prop){
      $prop->setAccessible(true);
      if(isset($array[$prop->name]))
        $prop->setValue($object, $array[$prop->name]);
    } 

    return $object;

}

$pessoa1 = arrayToObject($array, 'Person');
var_dump($pessoa1);

使用json_encode是有问题的，因为它处理非UTF-8数据的方式。值得注意的是，json_encode/json_encode方法也将非关联数组作为数组。这可能是你想要的，也可能不是。我最近需要重新创建这个解决方案的功能，但没有使用json_ functions。这是我想到的:

/**
 * Returns true if the array has only integer keys
 */
function isArrayAssociative(array $array) {
    return (bool)count(array_filter(array_keys($array), 'is_string'));
}

/**
 * Converts an array to an object, but leaves non-associative arrays as arrays. 
 * This is the same logic that `json_decode(json_encode($arr), false)` uses.
 */
function arrayToObject(array $array, $maxDepth = 10) {
    if($maxDepth == 0) {
        return $array;
    }

    if(isArrayAssociative($array)) {
        $newObject = new \stdClass;
        foreach ($array as $key => $value) {
            if(is_array($value)) {
                $newObject->{$key} = arrayToObject($value, $maxDepth - 1);
            } else {
                $newObject->{$key} = $value;
            }
        }
        return $newObject;
    } else {

        $newArray = array();
        foreach ($array as $value) {
            if(is_array($value)) {
                $newArray[] = arrayToObject($value, $maxDepth - 1);
            } else {
                $newArray[] = $value;
            }                
        }
        return $newArray;
    }
}

简单的方法是

$object = (object)$array;

但这不是你想要的。如果你想要对象，你想要实现一些东西，但这在这个问题中是缺失的。仅仅为了使用对象而使用对象是没有意义的。