我想像这样转换一个对象:

{"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}

输入一个键值对数组,如下所示:

[[1,5],[2,7],[3,0],[4,0]...].

如何将对象转换为JavaScript中的键值对数组?


当前回答

使用for in

var obj = { "10":5, "2":7, "3":0, "4":0, "5":0, "6":0, "7":0,
            "8":0, "9":0, "10":0, "11":0, "12":0 };

var objectToArray = function(obj) {
    var _arr = [];

    for (var key in obj) {
        _arr.push([key, obj[key]]);
    }
    return _arr;
}

console.log(objectToArray(obj));

其他回答

你可以使用Object.keys()和map()来做到这一点

var obj = {“1”:5,“2”:7,“3”:0,“4”:0,“5”:0,“6”:0,“7”:0,“8”:0,“9”:0,“10”:0,“11”:0,“12”:0} var result = Object.keys(obj).map((key) => [Number(key), obj[key]]); 控制台.log(结果);

递归转换对象到数组

function is_object(mixed_var) {
    if (mixed_var instanceof Array) {
        return false;
    } else {
        return (mixed_var !== null) && (typeof( mixed_var ) == 'object');
    }
}


function objectToArray(obj) {
    var array = [], tempObject;
    for (var key in obj) {

        tempObject = obj[key];

        if (is_object(obj[key])) {
            tempObject = objectToArray(obj[key]);
        }
        array[key] = tempObject;
    }
    return array;
}

下面是es6使用扩展操作符和Object.entries的“新”方法。

const data = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

const dataSpread = [...Object.entries(data)];

// data spread value is now:
[
  [ '1', 5 ],  [ '2', 7 ],
  [ '3', 0 ],  [ '4', 0 ],
  [ '5', 0 ],  [ '6', 0 ],
  [ '7', 0 ],  [ '8', 0 ],
  [ '9', 0 ],  [ '10', 0 ],
  [ '11', 0 ], [ '12', 0 ]
]

这是我的解决方案,我有同样的问题,似乎这个解决方案为我工作。

yourObj = [].concat(yourObj);

使用对象。以键值格式获取Object的每个元素,然后像这样映射它们:

var obj = {“1”:5,“2”:7,“3”:0,“4”:0,“5”:0,“6”:0,“7”:0,“8”:0,“9”:0,“10”:0,“11”:0,“12”:0} var res = Object.entries(obj).map(([k, v]) => ([Number(k), v])); console.log(res);

但是,如果你确定键是按递进顺序排列的,你可以使用Object。values和Array#map来做这样的事情:

var obj ={“2”,“1”:5:7,“3”:0,“4”:0,“5”:0,“6”:0,“7”:0,“8”:0,“9”:0,“10”:0,“11”:0,“12”:0}; // idx是索引,你可以使用任何逻辑来增加它(从0开始) let result = Object.values(obj)。Map ((e, idx) => ([++idx, e])); console.log(结果);