Postgres是否自动将索引放在外键和主键上?我怎么知道呢?是否有返回表上所有索引的命令?
当前回答
对于PRIMARY KEY,索引将被创建,并带有以下消息:
NOTICE: CREATE TABLE / PRIMARY KEY will create implicit index "index" for table "table"
对于一个FOREIGN KEY,如果引用的表上没有索引,约束将不会被创建。
引用表上的索引不是必需的(尽管是需要的),因此不会隐式创建。
其他回答
下面是一个bash脚本,它使用@sergeyB的SQL生成SQL,为外键上缺失的索引创建索引。
#!/bin/bash
read -r -d '' SQL <<EOM
WITH fk_actions ( code, action ) AS (
VALUES ( 'a', 'error' ),
( 'r', 'restrict' ),
( 'c', 'cascade' ),
( 'n', 'set null' ),
( 'd', 'set default' )
),
fk_list AS (
SELECT pg_constraint.oid as fkoid, conrelid, confrelid as parentid,
conname, relname, nspname,
fk_actions_update.action as update_action,
fk_actions_delete.action as delete_action,
conkey as key_cols
FROM pg_constraint
JOIN pg_class ON conrelid = pg_class.oid
JOIN pg_namespace ON pg_class.relnamespace = pg_namespace.oid
JOIN fk_actions AS fk_actions_update ON confupdtype = fk_actions_update.code
JOIN fk_actions AS fk_actions_delete ON confdeltype = fk_actions_delete.code
WHERE contype = 'f'
),
fk_attributes AS (
SELECT fkoid, conrelid, attname, attnum
FROM fk_list
JOIN pg_attribute
ON conrelid = attrelid
AND attnum = ANY( key_cols )
ORDER BY fkoid, attnum
),
fk_cols_list AS (
SELECT fkoid, array_to_string(array_agg(attname), ':') as cols_list
FROM fk_attributes
GROUP BY fkoid
),
index_list AS (
SELECT indexrelid as indexid,
pg_class.relname as indexname,
indrelid,
indkey,
indpred is not null as has_predicate,
pg_get_indexdef(indexrelid) as indexdef
FROM pg_index
JOIN pg_class ON indexrelid = pg_class.oid
WHERE indisvalid
),
fk_index_match AS (
SELECT fk_list.*,
indexid,
indexname,
indkey::int[] as indexatts,
has_predicate,
indexdef,
array_length(key_cols, 1) as fk_colcount,
array_length(indkey,1) as index_colcount,
round(pg_relation_size(conrelid)/(1024^2)::numeric) as table_mb,
cols_list
FROM fk_list
JOIN fk_cols_list USING (fkoid)
LEFT OUTER JOIN index_list
ON conrelid = indrelid
AND (indkey::int2[])[0:(array_length(key_cols,1) -1)] @> key_cols
),
fk_perfect_match AS (
SELECT fkoid
FROM fk_index_match
WHERE (index_colcount - 1) <= fk_colcount
AND NOT has_predicate
AND indexdef LIKE '%USING btree%'
),
fk_index_check AS (
SELECT 'no index' as issue, *, 1 as issue_sort
FROM fk_index_match
WHERE indexid IS NULL
UNION ALL
SELECT 'questionable index' as issue, *, 2
FROM fk_index_match
WHERE indexid IS NOT NULL
AND fkoid NOT IN (
SELECT fkoid
FROM fk_perfect_match)
),
parent_table_stats AS (
SELECT fkoid, tabstats.relname as parent_name,
(n_tup_ins + n_tup_upd + n_tup_del + n_tup_hot_upd) as parent_writes,
round(pg_relation_size(parentid)/(1024^2)::numeric) as parent_mb
FROM pg_stat_user_tables AS tabstats
JOIN fk_list
ON relid = parentid
),
fk_table_stats AS (
SELECT fkoid,
(n_tup_ins + n_tup_upd + n_tup_del + n_tup_hot_upd) as writes,
seq_scan as table_scans
FROM pg_stat_user_tables AS tabstats
JOIN fk_list
ON relid = conrelid
)
SELECT relname as table_name,
cols_list
FROM fk_index_check
JOIN parent_table_stats USING (fkoid)
JOIN fk_table_stats USING (fkoid)
ORDER BY issue_sort, table_mb DESC, table_name;
EOM
DB_NAME="dbname"
DB_USER="dbuser"
DB_PASSWORD="dbpass"
DB_HOSTNAME="hostname"
DB_PORT=5432
export PGPASSWORD="$DB_PASSWORD"
psql -h $DB_HOSTNAME -p $DB_PORT -U $DB_USER -d $DB_NAME -t -A -F"," -c "$SQL" | while read -r line; do
IFS=','
parts=($line)
unset IFS
tableName=${parts[0]}
colsList=${parts[1]}
indexName="${tableName}_${colsList//:/_}_index"
printf -- "\n--Index: %s\nDROP INDEX IF EXISTS %s;\n
CREATE INDEX %s\n\t\tON %s USING btree\n\t(%s);
" "$indexName" "$indexName" "$indexName" "$tableName" "$colsList"
done
PostgreSQL自动在主键和唯一约束上创建索引,但不会在外键关系的引用端创建索引。
当Pg创建一个隐式索引时,它将发出一个notice级别的消息,您可以在psql和/或系统日志中看到该消息,因此您可以看到它何时发生。自动创建的索引在表的\d输出中也是可见的。
关于唯一索引的文档说:
PostgreSQL自动为每个唯一的约束和主键约束创建索引,以加强唯一性。因此,没有必要显式地为主键列创建索引。
约束条件的文档说:
从引用表中的一行的DELETE或引用表中的UPDATE开始 所引用的列需要对引用表进行扫描 与旧值匹配的行,通常是一个好主意 引用列。因为这并不总是需要的,而且有 关于如何索引、声明外键有许多选择 约束不会自动在引用上创建索引 列。
因此,如果需要外键,就必须自己创建索引。
注意,如果使用主外键,比如在M-to-N表中使用2个FK作为PK,您将在PK上有一个索引,可能不需要创建任何额外的索引。
虽然在引用端外键列上创建索引(或包含)通常是个好主意,但这并不是必需的。您添加的每个索引都会略微降低DML操作的速度,因此在每次INSERT、UPDATE或DELETE上都要付出性能代价。如果索引很少被使用,那么它可能就不值得拥有。
如果你想列出程序模式中所有表的索引,所有信息都在目录中:
select
n.nspname as "Schema"
,t.relname as "Table"
,c.relname as "Index"
from
pg_catalog.pg_class c
join pg_catalog.pg_namespace n on n.oid = c.relnamespace
join pg_catalog.pg_index i on i.indexrelid = c.oid
join pg_catalog.pg_class t on i.indrelid = t.oid
where
c.relkind = 'i'
and n.nspname not in ('pg_catalog', 'pg_toast')
and pg_catalog.pg_table_is_visible(c.oid)
order by
n.nspname
,t.relname
,c.relname
如果想深入研究(如列和排序),需要查看pg_catalog.pg_index。使用psql -E [dbname]可以方便地了解如何查询编目。
对于PRIMARY KEY,索引将被创建,并带有以下消息:
NOTICE: CREATE TABLE / PRIMARY KEY will create implicit index "index" for table "table"
对于一个FOREIGN KEY,如果引用的表上没有索引,约束将不会被创建。
引用表上的索引不是必需的(尽管是需要的),因此不会隐式创建。
是-主键,否-外键(更多在文档中)。
\d <table_name>
在“psql”中显示了一个表的描述,包括它的所有索引。
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