完整且随时可用的回答<ES6:

 var Strings = {
        create : (function() {
                var regexp = /{([^{]+)}/g;

                return function(str, o) {
                     return str.replace(regexp, function(ignore, key){
                           return (key = o[key]) == null ? '' : key;
                     });
                }
        })()
};

电话是

Strings.create("My firstname is {first}, my last name is {last}", {first:'Neo', last:'Andersson'});

将它附加到String.prototype:

String.prototype.create = function(o) {
           return Strings.create(this, o);
}

然后使用as:

"My firstname is ${first}".create({first:'Neo'});

如果你在>ES6上，那么你也可以这样做:

let first = 'Neo'; 
`My firstname is ${first}`; 

Var hello = "foo";

var my_string ="I pity the";

console.log (my_string,你好)

2020年和平语录:

Console.WriteLine("I {0} JavaScript!", ">:D<");

console.log(`I ${'>:D<'} C#`)

我会使用反撇号' '。

let name1 = 'Geoffrey';
let msg1 = `Hello ${name1}`;
console.log(msg1); // 'Hello Geoffrey'

但如果在创建msg1时不知道name1。

例如，如果msg1来自API。

你可以使用:

let name2 = 'Geoffrey';
let msg2 = 'Hello ${name2}';
console.log(msg2); // 'Hello ${name2}'

const regexp = /\${([^{]+)}/g;
let result = msg2.replace(regexp, function(ignore, key){
    return eval(key);
});
console.log(result); // 'Hello Geoffrey'

它将用他的值替换${name2}。

String.prototype.interpole = function () {
    var c=0, txt=this;
    while (txt.search(/{var}/g) > 0){
        txt = txt.replace(/{var}/, arguments[c]);
        c++;
    }
    return txt;
}

Uso:

var hello = "foo";
var my_string = "I pity the {var}".interpole(hello);
//resultado "I pity the foo"

也许

wrt=(s, arr=[])=>{
    arr.map((v,i)=>{s = s.replace(/\?/,v);});
    return s;
};
a='first var';
b='secondvar';
tr=wrt('<tr><td>?<td></td>?</td><tr>',[a,b]);
console.log(tr);
//or use tr in html(tr), append(tr) so on and so forth
// Use ? with care in s